how many bits in qubit

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Leetcode Reverse Bits

Reverse bits of a given the unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 ( Represented in binary as 00111001011110000010100101000000).Followup:If This function is called many times, what would you optimize it?Related Problem:reverse IntegerCredits:Special thanks to @ts for adding this problem and creating all test cases.# @param {Integer} n, a positive integer# @return

Codeforces 484A Bits

Serie A champions:10000 RFQ each time the input L and R (10^18) in the interval of the binary output indicates 1 most digits 1 numbers likewise output the smallestIdeas:yy think after a few are all 1 time can guarantee 1 of the number of how to construct this number??Both L and R are converted to binary from high to low L and r the same number must be constant, because the constructed numbers are guaranteed to be in the interval and then in two cases.One is L and R, and that's all there is to it

Two binary bit bits with different numbers

1, programming implementation: two int (32-bit) integer m and n binary expression, how many bits (bit) is different?#include This article is from the "Flower Open Shore" blog, please be sure to keep this source http://zxtong.blog.51cto.com/10697148/1703538Two binary bit bits with different numbers

[Leetcode] Reverse Bits

Reverse bits of a given the unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represent Ed in binary as00111001011110000010100101000000).Follow up:If This function is called many times, what would you optimize it? class solution { public : uint32_t reversebits (uint32_t N) { int m = 0 for (int i = 0 ; I 32 ; I++) {m 1 ; M |= n1 ; n >>= 1 ;

"Leetcode" Reverse Bits (middle)

Reverse bits of a given the unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represent Ed in binary as00111001011110000010100101000000).Ideas:N moves right, ans moves left.classSolution { Public: uint32_t reversebits (uint32_t N) {uint32_t ans=0; for(inti =0; I +; i++) { if(N 0x0001==1) {n= N >>1; Ans= ans 1; Ans|=0x0001; } Else{n= N >>1; An

Leetcode Number of 1 Bits

1. TopicsWrite a function that takes an unsigned integer and returns the number of ' 1 ' bits it has (also known as the Hamming weigh T).For example, the 32-bit integer ' One ' 00000000000000000000000000001011 has a binary representation, so the function should return 3.2. Solution 1Class Solution {public: int hammingweight (uint32_t n) { int count = 0; while (n) { + + count; n = (n-1) n; } return count; }};For

Leetcode-190 Reverse Bits

Problem Description:Reverse bits of a given the unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 ( Represented in binary as00111001011110000010100101000000).Followup:If This function is called many times, what would you optimize it?Related problem: Reverse IntegerC + + code implementation:Java implementation: Failed to run on the system, I do not know how to handle the pro

Leetcode 191. Number of 1 Bits

Write a function that takes an unsigned integer and returns the number of ' 1 ' bits it has (also known as the Hamming weigh T).For example, the 32-bit integer ' One ' 00000000000000000000000000001011 has a binary representation, so the function should return 3.Question: Write a function to find out how many 1 in an unsigned int type of dataParsing: This problem can be solved by using bit arithmetic. class solution { public : int Hammingweight (

Leetcode "Number of 1 Bits"

Counting number of enabled bits in uint32_t. Here is a O (LG32) solution. Very Smart, like bottom-up parallel tree post-order traversal.Solution from discussion of LC:intHammingweight (uint32_t N){N= ((n >> (10)) 0x55555555) + (N 0x55555555); N= ((n >> (11)) 0x33333333) + (N 0x33333333); N= ((n >> (12)) 0x0f0f0f0f) + (N 0x0f0f0f0f); N= ((n >> (13)) 0x00ff00ff) + (N 0x00ff00ff); return(N >> (14)) 0xFFFF) + (N 0xFFFF);}Leetcode "Number of 1

[Leetcode] Number of 1 Bits

Write a function that takes an unsigned integer and returns the number of ' 1 ' bits it has (also known as the Hamming weigh T).For example, the 32-bit integer ' One ' 00000000000000000000000000001011 has a binary representation, so the function should return 3.Credits:Special thanks to @ts for adding this problem and creating all test cases.Can only think of the simplest method.1 classSolution {2 Public:3 intHammingweight (uint32_t N) {4

[Leetcode] Number of 1 bits bit 1

Write a function that takes an unsigned integer and returns the number of ' 1 ' bits it has (also known as the Hamming weigh T).For example, the 32-bit integer ' One ' 00000000000000000000000000001011 has a binary representation, so the function should return 3.Very simple operation bit operation problem, the recent new three questions are not what difficulty ah, this will mislead the newcomer, did the three to get a leetcode no difficulty conclusion,

OJ Practice 37--t190 Reverse Bits

do.Time consuming 9ms, ranked in the efficiency range of C."Other Code"uint32_t reversebits (uint32_t N) {uint32_t answer; uint32_t i; Answer=0; /*move a unsigned int number 1 to the left until it becomes full 0, and you get the length of the unsigned int within the machine .*/ for(i =1; I! =0; I 1) {Answer1; if(N 1) {Answer |=1; } N>>=1; } returnanswer; }EvaluationThe law "new Space", but also just an unsigned integer size, insignificant, people code is very concise.The beaut

Leetcode Reverse Bits

Reverse bits of a given the unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 ( Represented in binary as00111001011110000010100101000000).Followup:If This function is called many times, what would you optimize it?Related Problem:reverse IntegerThinking Analysis: This question is relatively simple, basic and reverse integer idea similar, n constantly right shift take the bot

Leetcode 190:reverse Bits

Reverse bits of a given the unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 ( Represented in binary as 00111001011110000010100101000000).Followup:If This function is called many times, what would you optimize it?Related Problem:reverse IntegerCredits:Special thanks to @ts for adding this problem and creating all test cases.Analysis:The title requires the binary rollover o

[Leetcode]-number of 1 Bits

Number of 1 BitsWrite a function that takes an unsigned integer and returns the number of ' 1 ' bits it has (also known as the Hamming weigh T).For example, the 32-bit integer ' One ' have binary representation 00000000000000000000000000001011, so the function should re Turn 3.Find a UINT Data 1 of the number, very simple does not analyze the#include #include typedef unsigned intuint32_t;typedef unsigned Charuchar8_t;intHammingweight (uint32_t N) {uin

[Leetcode]-reverse Bits

Reverse bits of a given the unsigned integer.Bits the UINT data in reverse orderFor example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represent Ed in binary as 00111001011110000010100101000000).Idea: Move the n data loop left, and move the moved data right into B and return Buint32_t reverseBits(uint32_t n) { 0; 1; 0; for(i=0;i32;i++) { if(n t) b = (b11;

191 Number of 1 Bits

Recently want to brush leetcode practice data structure algorithm and so on, start with the water problemThe title is like this.Write a function that takes an unsigned integer and returns the number of ' 1 ' bits it has (also known as the Hamming weigh T).For example, the 32-bit integer ' One ' 00000000000000000000000000001011 has a binary representation, so the function should return 3.Probably is the 32-bit number of numbers is calculated as 1 of th

Number formatting, four ways to add commas every three bits from right to left

Reprinted from: http://www.uedsc.com/micrometer-method.htmlSometimes I need to add a number to every three digits plus a comma, for example, 20000 to 20,000, in order to facilitate the financial reading, so I sorted out the following four ways to solve:1. javascript // a roundabout function FormatNumber (str) { if ( Str.length return Str; else { return FormatNumber (Str.substr (0,str.length-3)) + ', ' +str.substr (str.length-3 ); }} // test function (note that numbers are to be

Number of 1 Bits

Topic:Write a function that takes an unsigned integer and returns the number of ' 1 ' bits it has (also known as the Hamming weigh T).For example, the 32-bit integer ' One ' 00000000000000000000000000001011 has a binary representation, so the function should return 3.unsigned integer:http://baike.baidu.com/view/6052699.htm1 Public classSolution {2 //You need to treat N as an unsigned value3 Public intHammingweight (intN) {4 5 int

(easy) Leetcode 191.Number of 1 Bits

Number of 1 BitsWrite a function that takes an unsigned integer and returns the number of ' 1 ' bits it has (also known as the Hamming weigh T).For example, the 32-bit integer ' One ' 00000000000000000000000000001011 has a binary representation, so the function should return 3.Credits:Special thanks to @ts for adding this problem and creating all test cases.The beauty of reference programming 120 pagesMethod 1: Use bit manipulationThe code is as follo

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