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2nd B is (LONB, LATB), according to the datum of 0 degrees longitude, the positive value of longitude (longitude), the longitude is negative (-longitude), north latitude takes 90-latitude value (90- Latitude), 90+ latitude value (90+latitude), the two points after the above treatment are counted as (Mlona, Mlata) and (Mlonb, MLATB). Then, according to triangular derivation, we can get the following formula to calculate the distance of two points:C = sin (mlata) *sin (MLATB) *
2nd B is (LONB, LATB), according to the datum of 0 degrees longitude, the positive value of longitude (longitude), the longitude is negative (-longitude), north latitude takes 90-latitude value (90- Latitude), 90+ latitude value (90+latitude), the two points after the above treatment are counted as (Mlona, Mlata) and (Mlonb, MLATB). Then, according to triangular derivation, we can get the following formula to calculate the distance of two points:C = sin (mlata) *sin (MLATB) *
= sin (mlata) *sin (MLATB) *cos (mlona-mlonb) + cos (mlata) *cos (MLATB)Distance = R*arccos (C) *pi/180Here, R and distance units are the same, if the use of 6371.004 km as a radius, then distance is the unit, if you want to use other units, such as mile, also need to do unit conversion, 1-kilometer =0.621371192mileIf the longitude is treated only as positive or
longitude of 2nd B is (LONB, LATB), according to the datum of 0 degrees longitude, the positive value of longitude (longitude), the longitude is negative (-longitude), north latitude takes 90-latitude value (90- Latitude), 90+ latitude value (90+latitude), the two points after the above treatment are counted as (Mlona, Mlata) and (Mlonb, MLATB). Then, according to triangular derivation, we can get the following formula to calculate the distance of two points:C = sin (mlata) *sin (MLATB) *
we assume that the Earth is a perfect sphere, its radius is the mean radius of the Earth, which is recorded as R. If the zero-degree longitude line is used as the basis, the distance between the two points can be calculated based on the latitude and longitude of any two points on the Earth's surface. (here, the error caused by the calculation of the earth's surface topography is ignored, only theoretical estimates ). Set the longitude and latitude of the first Vertex a to (Lona, Lata), and the
the image .)
2.
Public static AffineTransform getScaleInstance (double sx, double sy) scaling and transformation, scale the horizontal coordinates of each point to sx times, vertical coordinates to sy times, and the transformation matrix is:
[Sx 0 0][0 sy 0][0 0 1]
3.
Public static AffineTransform getShearInstance (double shx, double shy) shear transformation. The transformation matrix is:
[1 shx 0][Shy 1 0][0 0 1]
It is equivalent to the combination of a transverse shear and a longitudinal she
The affine transform can be understood as the scaled, rotated, and obtained value of the new coordinate after translation. The value of the original coordinate in the new coordinate field after the rotation, rotation, and translation of the coordinate axis. As shown in, the coordinate axes of the XY coordinate system rotate θ and the coordinate origin moves (x0, y0 ). X, Y in xy Coordinate System ・
Cos θ-y then ・
Sin θ + x0y = x ・ sin θ + Y then ・
I wrote my blog for the first time.
When using the imrotate function of MATLAB to rotate a binary image, you cannot implement the function. You have written a rotation program. The basic principle of rotation is as follows: rotate the vertex A (x0, y0) in the source image to (x1, Y1). If the rotation angle is Alpha, then X1 = x0 * Cos (alpha) + y0 * sin (alpha); Y1 =-x0 * sin (alpha) + y0 * Cos (alpha );
Op
FW: http://blog.csdn.net/ok9034875/archive/2007/04/24/1578259.aspx The affine transform can be understood as the scaled, rotated, and obtained value of the new coordinate after translation. The value of the original coordinate in the new coordinate field after the rotation, rotation, and translation of the coordinate axis. As shown in, the coordinate axes of the XY coordinate system rotate θ and the coordinate origin moves (x0, y0 ). X, Y in xy Coordinate System ・
(called Cos value), user attributes (A or Class B user), and so on.In the recent past, the support staff of a commercial ringtones of the software system have fed back a problem: The database has accumulated outdated user data, and many of the data that should have been deleted remains.Second, the cause of the initial analysisIn this software system, there is an outdated data cleansing module dedicated to cleaning up outdated user data. Since there a
Https://www.youtube.com/watch?v=1yR3F9hnwGUFirst, popularize the femtocell:https://zh.wikipedia.org/wiki/%e5%ae%b6%e5%ba%ad%e5%9f%ba%e7%ab%99.Home Base Station ( English:Femtocell, also translated as Pico Honeycomb Base station), originally called the access point base stations , is a small cellular base station that is generally designed for use in home or small commercial establishments. Connecting to the operator's network via broadband access (such as DSL, cable, fiber) can integrate 2G, 3G
, the constraint can be met)The range for Ax, Ay, AZ is [0, 2*pi]. For example, when ay=0, the y-axis of the phone is vertical upward; when ay=pi, the y-axis of the phone is down; AY=PI/2, the phone level, screen up, AY=3*PI/2, the phone level, the screen downAccording to the law of 3D vector algebra, we know:
Gx=g*cos (Ax)
Gy=g*cos (Ay)
Gz=g*cos
Yesterday, the iPhone 6 was released in China. I just published a graph about kidney. Nephroid indicates a kidney. But this curve does not look like a kidney. When you see it, what do you think it is like.
The name nephroid (meaning 'Kidney shaped') was used for the Two-cusped epicycloid by Proctor in 1878. The nephroid is the epicycloid formed by a circle of RadiusARolling externally on a fixed circle of radius 2A. The nephroid has length 24AAnd area 12 π 2.
The mathematical formula is:
X=A(
favorites or save it as an address. You may want to read it later. There are too many such examples. Maybe you haven't opened this page a few years later. In any case, be patient and read it. This article is much easier and happier than reading textbooks ......
P.s. Both COs and sin use the word "Sine Wave" to represent the harmonic.I. What is frequency domain?
Since we were born, we have seen the world run through time, and the trend of stocks, huma
ABS
Prototype: extern int ABS (int x );
Usage: # include
Function: calculates the absolute value of integer x.
Description: calculation | x |. If X is not negative, X is returned. Otherwise,-X is returned.
Example:
// Abs. c
# Include # Include
Main (){Int X;
Clrscr (); // clear screen
X =-5;Printf ("| % d | = % d/N", X, ABS (x ));X = 0;Printf ("| % d | = % d/N", X, ABS (x ));X = + 5;Printf ("| % d | = % d/N", X, ABS (x ));
Getchar ();Return 0;}
Related functions: FABS
ACOs
Prototype: exter
,\\
I ^ 4 ={} 1, \ quad
I ^ 5 ={} I, \ quad
I ^ 6 {}=-1, \ quad
I ^ 7 {}=-I ,\\
\ End {Align} "class =" Tex ">
And so on. The functionsEX, CosXAnd sinXOf the (real) VariableXCan be expressed using their Taylor expansions around zero:
E ^ X {}= 1 + x + \ frac {x ^ 2} {2 !} + \ Frac {x ^ 3} {3 !} + \ Cdots \\
\ Cos x {}= 1-\ frac {x ^ 2} {2 !} + \ Frac {x ^ 4} {4 !} -\ Frac {x ^ 6} {6 !} + \ Cdots \\
\ SiN x {}= X-\ fra
Finally, the two-dimensional graphics are finished. Starting from this section, we enter the 3D graphics world.
The following is an introduction to the three-leaf knot in the Wiki:
In the knot theory, trefoil knot is the simplest and extraordinary knot. You can use the backhand to connect two ends. It is the only knot with three intersections. It can also be described as a ring knot. Because the structure of the three-leaf knot is extremely simple, it is an important basic case for studying the
transform: matrix(a,b,c,d,e,f) this transformation matrix. The 6 variables here make up a 3-medium transformation matrix.
The translation, rotation, and scaling transformations of any point P (x, y) and their various combinations can be achieved through this transformation matrix:
Note: Here we use homogeneous coordinates to express a point. Simply put, p (x, y) is expressed as P ' (x ', y ', 1)
Translation matrix
V (x, y) pans the TX along the x-axis, translating ty along the y-axis. Then ther
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