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+Beta ). To the Cartesian coordinate system, the point after rotation is changed to (cos (α +Beta) * r, sin (α +Beta) * r ). Then use the formula: Cos (α + β) = cos α cos β-sin α sin β Sin (α + β) = sin α cos β + cos α sin β A

By doing this, I also confirmed that GDI + can directly display transparent images in PNG, GIF, and TIF formats. // Red and green rotate around blue (R is radian) colormatrix: tcolormatrix = (COS (R), sin (R), 0.0, 0.0, 0.0 ), (-sin (R), cos (R), 0.0, 0.0, 0.0), (0.0, 0.0, 1.0, 0.0, 0.0), (0.0, 0.0, 0.0, 1.0, 0.0), (0.0, 0.0, 0.0, 0.0, 1.0); // rotate green and blue (R is a radian) colormatrix: tcolormatr

function must use the dot Multiplication operation because the two are vectors. Example 52 plot a curve This is a curve equation given in the form of parameters. As long as the parameter vectors are given and then the X and Y vectors are obtained respectively, the curve can be output: > T =-Pi: PI/100: PI; > X = T. * Cos (3 * t ); > Y = T. * sin (T). * sin (t ); > Plot (x, y) After the program is executed, open a graphical window and draw the follow

Http://acm.hdu.edu.cn/showproblem.php? PID = 1, 3790 Typical short circuit problem. It indicates that after learning and checking the set in the morning, I learned the shortest short circuit because of the most short-circuit exercise, it means that he learned the code in the algorithm competition book of Liu rujia, and the guidance of the Senior Student Of the pigeon, finally wrote the first shortest circuit (orz...) in my ACM career ...) The typical Dijkstra algorithm uses the DIS and

the line and press enter to wrap the line. For example: S = 1-1/2 + 1/3 + 1/4 + sin (3 * x * y)-cos (x )... -Over 1/8 + 1/10 + 1/20 : Control keys and direction keys used for command line editing Press ''to display the command line you just typed; Press the ''key repeatedly to call back all the previously typed command lines; ''Key to move the cursor; There are also 'home', 'end', 'esc 'keys, and so on. 'esc' to clear a row. Variable It must

Because of the needs of the experiment report, we have matlab plotting. X = 0: pi/1000:2 * pi; y1 = sin (2 * x); y2 = 2 * cos (2 * x); % output image plot (x, y1, 'r-', x, y2,' B -- '); title ('plot of f (x) = sin (2x) and its derivative '); % set the xlabel ('x') for the X and Y coordinates; ylabel ('y'); % create the legend ('f (x) = sin (2x )', 'd/dx f (x) ') % display grid on; 1. x = 0: pi/1000:2 * pi. It indicates that the x coordinate starts f

How to determine the scale Size of the horizontal and vertical coordinates in the drawing command (self-defined range)How to draw multiple curves in one coordinate and use different colors.Hope to get the answer. Thank you !!!!!!!!!!!Help plotHelp axisAxis ('xlabel', 'ylabel ')A1 = plot ();Hlevels onA2 = plot ();Legend ([a1 a2], 'figure 1 name', 'figure 2 name ')Hold offMoreX1 =-Pi: PI/12: PI;X2 =-Pi: PI/12: PI;Y1 = sin (X1 );Y2 = cos (X2 );Plot (x1,

QoS learning notes marking: 1. the class-map.class-map defined [match-all/match-any] {map-name} is not typed by default. define the match command matchmatch access-group {NO} match input-interface {interface} match class-map {map-name} class-map nested match source-address {mac-address} source mac address match destination-address {mac-address} destination mac address match vlan {vlan-ID} match ip dscp {DSCP} match ip precedencc {precedence} match protocol {protocol} Based on NBARRouter (config)

How to sort complicated PHP queries. $ Latitude =$ _ GET ['Y']; $ Longpolling = $ _ GET ['x']; $ Distance = 500; $ SQL = "select * from ". $ GLOBALS ['ecs']-> table ('weixin _ map '). "where sqrt ((((". $ longpolling. "-longpolling) * PI () * 12656 * cos (((". $ latitude. "+ Latitude)/2) * PI ()/180)/180 )*((". $ longpolling. "-longpolling) * PI () * 12656 * cos (((". $ latitude. "+ Latitude)/2) * PI ()/180

latitude and longitude of 1th A is (Lona, LatA), the latitude and longitude of 2nd B is (LONB, LATB), according to the datum of 0 degrees longitude, the positive value of longitude (longitude), the longitude is negative (-longitude), north latitude takes 90-latitude value (90- Latitude), 90+ latitude value (90+latitude), the two points after the above treatment are counted as (Mlona, Mlata) and (Mlonb, MLATB). Then, according to triangular derivation, we can get the following formula to calcula

There is such an SQL statement. is used to inquire about nearby people. You know how many people are using it. Use the model's Count method. Here is the SQL statement: SELECT userid ,username,homeland,headImage,(ACOS(SIN(('.$lat.' * 3.1415) / 180 ) *SIN((latitude * 3.1415) / 180 ) +COS(('.$lat.' * 3.1415) / 180 ) * COS((latitude * 3.1415) / 180 ) *COS(('.$lon.'

(:);%x to 10x1 Matrix Y=ij (:, 2:2:8)%y 25x4 matrix y=y (:);%y to 100x1 matrix sj=[x y];%100x2 Matrix d1=[70,40];% start point sj=[d1;sj; d1];% Add the starting point and end point sj=sj*pi/180;% angle to radians% calculate distance d=zeros (102);% build a 102x102 empty distance matrix, then fill in the corresponding distance%A (r cos X1 cos y1, r sin X1 cos y 1

), latitude values (90+latitude) are 90+, then two points after the above treatment are counted (Mlona, Mlata) and (Mlonb, MLATB). Then according to the triangular derivation, we can get the following formula for calculating the distance of two points:C = sin (mlata) *sin (MLATB) *cos (mlona-mlonb) + cos (mlata) *cos (MLATB)Distance = R*arccos (C) *pi/180Here, R

76. >> x=[0 0 0];y=[30 90];z=[0 0 0];% draw a straight line on the plane z=0PLOT3 (x, Y, z)On>> grid on>> x1=[0 0 0 0];y1=[0 36];z1=[3 3 3 3];% draw a straight line on the plane z=3PLOT3 (X1,Y1,Z1)Grid onOn>> x2=[0 0 0 0];y2=[0 0];z2=[0 0 1 1];% draw an unclosed rectanglePLOT3 (X2,Y2,Z2)On>> x2=[0 0 0 0 0];y2=[0 0 0];z2=[0 0 1 1 0];% draw enclosing RectanglePLOT3 (X2,Y2,Z2) 77. Three-dimensional pie chartX=[32 45 11 76 56];Explode=[0 0 1 0 1];%1 means separate.Pie3 (X,explode) PLOT3 drawing thre

a vector b and another constant quantity a collinear two opposite projection vector Let's take a look at the diagram above, obviously, CosA (a=x) about the y-axis symmetry, is even function, so cosA = cos (-a),And because CosA is a periodic function, and the period is 2*PI, there is a cos (a+2*pi) = CosA = cos (-a) = cos