purchased in 2005 and 2006, running the WinXP standard, the memory is about 256M to 1G. If this part of the PC to upgrade to Vista, the need to pay not only the software costs of Vista, but also to pay some of the hardware upgrade costs. The retail price of Vista is also quite high. Because these "master" PCs have been unable to run Vista, need to upgrade in memory support and graphics. If you do so, you may also encounter compatibility issues that are not desirable.
Buy the retail vista price
P3381 "template" Minimum cost maximum flow topic descriptionTitle, a network diagram is given, along with its source and sink points, each edge is known for its maximum flow rate and unit traffic cost, and the minimum cost of its maximum flow and maximum flow is calculated.Input/output formatInput format:The first line contains four positive integers n, M, S, T,
Original address:Http://www.leiphone.com/news/201408/g8UwvbLLea2GKUT2.htmlAt present, the domestic app developers are facing the promotion dilemma, the promotion of the cost is further improved, (some promotional form of the cost has not changed but the effect is declining), the effect of good promotion form price is generally higher, will undoubtedly push developers to the high threshold of the promotion o
Issue background:Huffman tree is widely used in coding. Here, we only care about the construction of the Huffman tree.Given the number of columns {pi}={p0, p1, ..., pn-1}, the process of constructing the Huffman tree with this number is as follows:1. Find the minimum of two in the {pi}, set to PA and Pb, remove the PA and Pb from the {pi}, and add them to the {pi}In The cost of this process is recorded as PA + PB.2. Repeat step 1 until only one number
At present, the domestic app developers are facing the promotion dilemma, the promotion of the cost is further improved, (some promotional form of the cost has not changed but the effect is declining), the effect of good promotion form price is generally higher, will undoubtedly push developers to the high threshold of the promotion of the road. Therefore, the success of a product depends largely on the ope
Link:
Http://acm.hdu.edu.cn/showproblem.php? PID = 1, 1385
Question:
There are n cities, and then the adjacent matrix between these cities is directly given. In the matrix,-1 indicates that the two cities are not connected by road, and other values represent the path length.
If a car passes through a city, you must pay a certain amount of money (possibly a toll ).
Now, from City A to City B, the cost is the sum of the path length, plus the total toll
The emergence of requirements and Scheme Review, product design, technical implementation, technical details, no., emergence of requirements, and Scheme Review
Imagine that you (Web developers) have a movie website (including introduction, comments, and cinema information ), how do you make movie applications of web sites into iPad applications at minimal cost?
Preferred solution: if your father or son is an iOS developer, the
Question: Here is a target string str_t. You can use the following n strings (STR [N] [N]). the limit [I] characters are selected from each STR [I] string. The cost of taking a character from the string I is I. Ask the minimum price for the string. If the string cannot be str_t, output-1.
Set a super Source Vertex st and a super sink vertex ed. Create an edge with a capacity of limit [I] from the Super source point to each STR [I] at a
Today, I have been busy purchasing a Dell poweredge for a day, and I have never been able to buy it at the end, so I am depressed.
The current project needs to purchase an entry-level server. I don't know how to do it. The first reaction was to go to the Dell website. Coincidentally, the reference configuration sheet sent by my colleagues was also Dell. After reading the configuration, I have finalized a poweredge sc440. The message I got when I was about to ask is to help with procurement is
Poj 2135 Farm Tour [maximum minimum cost of undirected graphs], poj2135
Title: poj 2135 Farm Tour
Question: Give an undirected graph, ask from to, and then return to a total of the shortest paths.
Analysis: if this question is not carefully read, it may be used as the shortest path. The shortest path is not necessarily the best. It is the shortest path of the two, but not necessarily the shortest path.
We can easily solve the problem by using the bi
The maximum flow of minimum fees learned here.
Definition: Graph G uses s as the Source Vertex and T as the sink vertex. C (I, j) is the capacity of G, F (I, j) is the capacity of G, w (I, j) is the unit traffic fee and w (I, j) =-W (J, I ). Cost WF = Σ (fij * wij) (I, j) ε E (G ). That is, when the maximum stream F is obtained, the WF is minimized.
Thought: using the Ford-Fulkerson Algorithm, we constantly find augmented paths in the residual network
divided into several items, each of which has a factor, and the cost and value of the item are the original cost and value multiplied by this factor. Make these coefficients 1,2,4,...,2^ (k-1), n[i]-2^k+1, and K is the largest integer that satisfies the n[i]-2^k+1>0. For example, if N[i] is 13, the items are divided into four items with coefficients of 1,2,4,6 respectively.Original title Link: http://acm.h
Build: From the source point to the first layer of the edge, the first layer of the day to use out how many napkins, the second layer of how many napkins are needed for the day, so pay attention to the purchase of the napkin edge capacity for infinity, to start from the source point to the second level point, every day there may be surplus, Nodes that are represented in the first layer as flowing into the second day. See the code, the first time to write the
Topic Link: Click to open the linkTest instructionsA graph with a forward edge for a given n points m bar, beginning S, end point TBelow M edge U,v, a, b if you choose this side to spend a, do not choose to spend aConstructing a Euler path makes the starting point S, the end point is T, and the cost is minimized.Ideas:First you can think of a simple idea: Assume that all sides are selected, and then run in the expense flow, there will be a negative ri
"Test Instructions" gives an no-map, starting from 1 to N, two without a common edge of the shortest, so that the sum of the distance is minimal
The weight of each edge is set to cost, the maximum flow is set to 1, and then is the minimum charge flow from the source point to the meeting point flow rate of 2.Because it is the specified traffic, a new source point and a sink point, the source point to the node 1 a maximum flow of 2, the
The main idea: give a picture of a few of the one-way side, the rest of the side arbitrary orientation. How many ternary rings can be formed.Idea: For any three points, they are composed of ternary rings, when and only if these points are in degrees = degrees = 1. If there is no ternary ring, just change the direction of any one of these sides, so that a point into the degree of 2, a point of the degree of 2. We just need to figure out how many of the three points have a point in the degree of 2
At on the afternoon of October 30, at the invitation of Guangzhou guanglianda company, the company participated in the cost management software application (GCM) of the "Expansion Project of the fourth Bureau of construction of Baiyun Airport" organized by the company. Many units in Guangzhou participated in the activity, mainly for housing construction systems, road construction units only support us.
The project is located on the right side of the
When determining the installation and supply of bids for the network, the total investment cost of the network owner is a key factor. BecauseStructured CablingThe system network has a service life of at least 15 years, so the network operation cost and upgrade cost will be equal to or greater than the initial investment amount. After the network is installed, add
Luogu P4016 Load Balancing (maximum minimum cost), p4016 Load BalancingDescription
GG has nn warehouses arranged in a circular manner along railway lines. Each Warehouse stores a different amount of goods. How to use a minimum volume of transportation can make the inventory of nn warehouses the same. When carrying goods, it can only be carried between adjacent warehouses.Input/Output Format
Input Format:
There are 11 positive integers nn in the row 1
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