how to create vpn server on android

============ Problem Description ============A service port was created in activity through New ServerSocket (9090), why is the port not open when viewed through the netstat command?And then at the client anyway also connected not on that sureCode:Server=new ServerSocket (12345);System.out.println ("IP:" +server.getlocalsocketaddress () + "----Port:" +server.getlocalport ());SYSTEM.OUT.PRINTLN ("Server IP:" +server.getinetaddress ());SYSTEM.OUT.PRINTL

==================== Problem Description ====================A service port was created in activity through New ServerSocket (9090), why is the port not open when viewed through the netstat command?And then at the client anyway also connected not on that sureCode:Server=new ServerSocket (12345);System.out.println ("IP:" +server.getlocalsocketaddress () + "----Port:" +server.getlocalport ());SYSTEM.OUT.PRINTLN ("Server IP:" +server.getinetaddress ());S

In the andorid project, we send requests to the server through get. URL parameters contain Chinese characters, and garbled characters are generated. There are two possible causes for garbled characters: 1,When you submit a parameter, the Chinese parameter is not URL encoded. 2,The Tomcat server uses IOS8859-1 encoding by default (Chinese characters are not supported) to get the parameter value Solution: 1,

This article together with you understand how the Android client and server interface is how to interact with the specific content as follows 1. Use a simple servlet in the background to support get or post. the servlet eventually returns to the foreground a string flag, the value is true or FALSE, indicating whether the login was successful. The servlet needs to be configured before it is used, and the s

action button in the commit (the second button on the left of the SVN related operation button); after clicking Commit, Android Studio will parse the current code into code, if there is an error or warning will pop up the following box, if there is an error conflict, etc. need to be resolved before committing, if the warning can be ignored (same as Eclipse) , the first time the entire code is submitted to the SVN

Workaround under Windows:If you are running a 32-bit Android studio, you need to modify the file:In the startup directory of Andriod Studio. Find studio.exe.vmoptions this file. Add in the back-djava.net.preferipv4stack=true-didea.updates.url=http://dl.google.com/android/studio/patches/updates.xml -didea.patches.url=http://dl.google.com/android/studio/patches/If

/*************************************** **************************************** ************** Author: conowen @ Dazhong* E-mail: conowen@hotmail.com* Http://blog.csdn.net/conowen* Note: This article is original and only used for learning and communication. For more information, indicate the author and its source. **************************************** **************************************** ************/ 1. How to communicate with the server da

Android-set up a simple server + ListView to load data Asynchronously May 6, 2014 This blog post will teach you how to build a server in MyEclipse, communicate with them on your mobile phone, and load data asynchronously. I am using MyEclipse. You can also use Eclipse to create a Java Web project. The ADT Bundle prov

Genymotion-Android simulator prompts "Unable to connect to the Genymotion server. Please check your Internet connection." solution, Genymotion was just installed yesterday and used well last night. Start the system tonight and enable Genymotion again, but the message "Unable to connect to the Genymotion server. Please check your Internet connection." is display

. getlocalizedmessage ();Final stacktraceelement [] stack = ex. getstacktrace ();Final string message = ex. getmessage ();// Use toast to display exception informationNew thread (){@ OverridePublic void run (){Logoff. Prepare ();// Toast. maketext (mcontext, "program error:" + message,// Toast. length_long). Show ();// You can create only one file, append all the files in it, and then send them. This leads to duplicate information, which is not recomm

In Android, file upload is actually very simple. It is the same as in java. Basically, it is familiar with the operation output stream and input stream! Another important thing is to configure some parameters of content-type! If all of these are done, the upload will be simple. The following is a tool class for uploading: package com. spring. sky. image. upload. network; import java. io. dataOutputStream; import java. io. file; import java. io. fileIn

The Android Network program transmits data to the server (ii)Please respect the results of other people's work, reproduced please specify the Source: Android Network Programming transfer data to the server (ii)I have in the "Android network programming data to the

(); Final String message = Ex.getmessage (); Use Toast to display exception information New Thread () { @Override public void Run () { Looper.prepare (); Toast.maketext (Mcontext, "program error:" + message, Toast.length_long). Show (); You can create only one file, then all the way to the inside append and then send, so there will be duplicate information, the individual does not recommend String fileName = "crash-" + system.currenttimemill

First, the client obtains json data from the server. 1. Use HttpUrlConnection Copy codeThe Code is as follows :/** * Get an array from the specified URL * @ Param urlPath * @ Return * @ Throws Exception */ Public static String readParse (String urlPath) throws Exception { ByteArrayOutputStream outStream = new ByteArrayOutputStream (); Byte [] data = new byte [1024]; Int len = 0; URL url = new URL (urlPath ); HttpURLConnection conn = (HttpURLConnectio

Android Network Programming transfer data to the server (i)Please respect other people's labor results, reproduced please specify the source: The Android Network program transmits data to the server (a)because Android the program needs to communicate with the

know.Of course, the development of WebApp of course there are limitations, is the speed of anything, this can not be changed, here is not nonsense. But in development, if it's just the interaction between pages, we just need to provide a webview control,But if it is related to mobile devices or software interaction (such as open album, Camera, etc.), this requires us and the page by the line JS interaction, JS Interaction can be said to be bidirectional, one is, we call the page, is called the

Datagramsocket object and specifies the listening port. (UDP uses Datagramsocket)datagramsocket socket; Try{Socket=NewDatagramsocket (10025); //Create an array of type byte to hold the received data byteData[] =New byte[4*1024x768]; //creates a Datagrampacket object and specifies the size of the Datagrampacket objectDatagrampacket packet =NewDatagrampacket (data,data.length); //read the Received datasocket.receive (packet); //converts the

Java.io.OutputStreamWriter; Import Java.io.PrintWriter; Import Java.net.ServerSocket; Import Java.net.Socket; public class Server implements Runnable { public void Run () { Try { Create ServerSocket ServerSocket serversocket = new ServerSocket (54321); while (true) { Accept client Requests Socket client = Serversocket.accept (); System.out.println ("accept"); Try { Receive client message

This article is an example of how the client of Android programming communicates with the server via a socket. Share to everyone for your reference, specific as follows: The following is a demo,android client communicates with the server through a socket. Since Android can

The XMPP protocol (extensible Messaging and PRESENCEPROTOCOL, Extensible Message Processing field protocol) is an XML-based protocol that is designed to address the standards of timely communication and is first implemented in Jabber. It inherits the flexibility of development in the XML environment. As a result, XMPP-based applications have super-scalable capability. and XML is easy to pass through firewalls, so applications built with XMPP are not susceptible to firewalls. Using XMPP as a univ