how to get dynamic ip

In general, the usual way to get a user's IP address is:1 stringIpAddress ="";2 if((httpcontext.current.request.servervariables["http_x_forwarded_for"]!=NULL 3 httpcontext.current.request.servervariables["http_x_forwarded_for"] !=String.Empty))4 {5ipaddress=httpcontext.current.request.servervariables["http_x_forwarded_for"] ;6 }7 Else8 { 9httpcontext.current.request.servervariables["REMOTE_ADDR"]; Ten}View

Using System.net.http;public static class httprequestmessageextensions{Private Const string HttpContext = "Ms_httpcont Ext "; Private Const string remoteendpointmessage = "System.ServiceModel.Channels.RemoteEndpointMessageProperty"; Private Const string Owincontext = "Ms_owincontext"; public static string getclientipaddress (this httprequestmessage request) {//web-hosting. Needs reference to System.Web.dll if (request. Properties.containskey (HttpContext)) {

/*** Get the user real IP *@paramRequest *@return */ Public Staticstring getipaddr (HttpServletRequest request) {string IP= Request.getheader ("X-forwarded-for"); if(IP = =NULL) || (ip.length () = = 0) | | ("Unknown". Equalsignorecase (IP))) {

//Get IP Address Publicstring getipaddr (HttpServletRequest request) {string IP= Request.getheader ("X-forwarded-for"); if(IP = =NULL|| Ip.length () = = 0 | | "Unknown". Equalsignorecase (IP)) {IP= Request.getheader ("Proxy-cl

an array that contains IP information String [] Whether For example: count=2, which indicates an array length of 2 (0,1) STRAREA_IP[0] IP address requested by the client String Whether For example: "218.108.242.108" STRAREA_IP[1] IP Address Region information String Whether For ex

"Lnmp a key installation package" needs to obtain IP address, there are 2 kinds of cases: if the server only private network address does not have public network address , this time to obtain the IP (that is, private network address) can not be used to determine the location of the server, so take its gateway address Used to determine whether the server is domestic or foreign (script to enable domestic user

NGINX+TOMCAT+SPRINGMVC Get user Access IP1.Nginx Reverse Proxymodifying Nginx configuration FilesLocation/ { *********** before code *******; Proxy_set_header host $host; Proxy_set_header X-forwarded- for $proxy _add_x_forwarded_for; // set the proxy IP header, the parameters when the code gets Proxy_set_header x-real-ip

Usually we get the IP from the following code: REMOTE_ADDR Description: access the IP address of the client . This information cannot be modified by the user. If you really change, you can not connect with the server, the server is to follow this to establish a connection with the client and communicate. Actually I test to modify this Se

remote host that made the request.Remote_hostThe name of the remote host that made the request.Request_methodThe method of making the request. such as, post, and so on.Script_nameThe name of the execution script.server_nameThe host name, DNS address, or IP address of the server.Server_portThe server port number on which the request was accepted.Server_port_secureIf the server port that accepts the request is a secure port, it is 1, otherwise 0.Server

as we all know, in order to infiltrate the intranet, you have to be in that intranet. But when you install Kali in VMware, most users do not choose bridging mode for convenience, but instead choose to use IP networks shared with nativeof course, this will be able to surf the Internet, but your virtual machine does not actually get the intranet IP. If you do not i

Tag: Class Port request Ali like STS main end returnspython3.x: Get proxy IPGet proxy IP, code:#Python3#Domestic High Stealth proxy IP website: http://www.xicidaili.com/nn/#Crawling Home proxy IP address fromBs4ImportBeautifulSoupImportRequestsImportRandom#Get home

[From] https://www.cnblogs.com/xiaoBlog2016/p/7076230.htmlDiscussed:This blog is at work, need to get the current network under the correct IP address, online access to a lot of blogs, online a more popular argument is through Inetaddress.getlocalhost (). Gethostaddress (). But only can obtain the Simple network environment the IP address, then ignores the

In a Web project with high security requirements, we often have this requirement:Blacklist: Disables the designation of IP access.Whitelist: Allows you to specify IP access.Follow the rogue intrusion system by IP.In Java we can usually get the client IP address in this way:REQUEST.GETREMOTEADDR ()However, this method h

//How to get the real IP () Publicstring Getipaddr () {string IP= Request.getheader ("X-forwarded-for"); if(IP = =NULL|| Ip.length () = = 0 | | "Unknown". Equalsignorecase (IP)) {IP= Request.getheader ("Proxy-client-

I. NetworkInterface conceptJava provides a NetworkInterface class. This class can get information about all the physical network interfaces of the machine and the logical network interfaces that the virtual machines and other software use to create the physical network interface of the machine.Step One: NetworkInterface enumerates all of the network interfaces of the machine by means of the Getnetworkinterfaces method.Step two: Traverse all network IP

In fact, the server remoting can be like reading a variable to get to the IP of the connected client, but this IP is not too easy to take.There is a solution on the web to use the configuration file to suck the IP address, but this scenario requires us to use the configuration file to use remoting, if we are the code f

= getenv ("Http_client_ip"); } ElseIf (getenv ("REMOTE_ADDR")) { $ip = getenv ("REMOTE_ADDR"); } Else { $ip = "Unknown"; } echo "Your IP:". $ip; ?> if (getenv (' http_client_ip ')) { $onlineip = getenv (' http_client_ip '); } elseif (getenv (' http_x_forwarded_for ')) { $onlineip = getenv (' http_x_forwarded_for ');