how to get two decimal places in java

The Java backend retains two decimal places1. (double) (Math.Round (sd3*10000)/10000.0);this keeps the 4-bit( Double) (Math.Round (sd3*100)/100.0);this keeps the 2 bits.2. Another approachimport Java.text.DecimalFormat;DecimalFormat df2 = new DecimalFormat ("###.00");DecimalFormat df2 = new DecimalFormat ("###.000");System.out.println (Df2.format (Doube_var));The first one is 2 bits and the second is 3 bits

, otherwise the rounding behavior is the same as Round_down . Note that this is the rounding pattern that most of us have learned in primary school. Round_half_down Rounds the nearest number to the rounding mode that is rounded up if the distance to the two adjacent numbers is equal. If part > 0.5 is discarded, the rounding behavior is the same as round_up , otherwise the rounding behavior is the same as Round_down .

Java retains two decimal places 4 waysMethod One: The Format method of string (recommended)Double F = 111231.5585;System.out.println (String.Format ("%.2f", f));Method Two: The Format method of DecimalFormatDouble F = 111231.5585;DecimalFormat df = new DecimalFormat ("#.00");System.out.println (Df.format (f));Here's what you can do without looking at itMethod Thr

4 methods, all rounded, for example:ImportJava.math.BigDecimal; ImportJava.text.DecimalFormat; ImportJava.text.NumberFormat; Public classFormat {Doublef = 111231.5585; Public voidM1 () {BigDecimal bg=NewBigDecimal (f); DoubleF1 = Bg.setscale (2, bigdecimal.round_half_up). Doublevalue (); System.out.println (F1); } /*** DecimalFormat conversion is the easiest*/ Public voidm2 () {DecimalFormat DF=NewDecimalFormat ("#.00"); System.out.println (Df.format (f)); }

The topic requirement is a high-precision division, which requires the retention of n decimal places (rounding), and the display of 0 is removed when the integer part is 0 o'clock1 ImportJava.math.BigDecimal;2 ImportJava.util.Scanner;3 4 Public classBD5 {6 Public Static voidMain (string[] args)7 {8Scanner Scanner =NewScanner (system.in);9 while(Scanner.hasnext ())Ten { OneBigDecim

1 import Java.math.BigDecimal;2 import Java.text.DecimalFormat;3 import Java.text.NumberFormat;4 Public classFormat {5 Doublef =111231.5585;6 Public voidM1 () {7BigDecimal BG =NewBigDecimal (f);8 DoubleF1 = Bg.setscale (2, bigdecimal.round_half_up). Doublevalue ();9System. out. println (F1);Ten } One /** A * DecimalFormat conversion is the easiest - */ - Public voidm2 () { theDecimalFormat DF =NewDecimalFormat ("#.00"); -System.

Import Java.text.DecimalFormat; Import Java.math.RoundingMode; class text{ publicstaticvoid main (String args[]) { new DecimalFormat (); Formater.setmaximumfractiondigits (2); Formater.setgroupingsize (0); Formater.setroundingmode (Roundingmode.floor); System.out.println (Formater.format (123456.7897456));} }Java retains two decimal places

1 //1, as long as the output results can be used the following methods:2 DoubleX1 = 0.026;3System.out.println (String.Format ("%.2f", X1));4 //Results: 0.035 //2. Using Data conversion (4 methods)6 //programme One:7Get_double = (Double) (Math.Round (result_value*100)/100.0)8 //Scenario Two:9DecimalFormat DF =NewDecimalFormat ("#.##");TenGet_double =double.parsedouble (Df.format (Result_value)); One //Programme III: Aget_double = double.parsedouble (String.Format ("%.2f", Result_value)); - //Prog

Java truncated decimal places 1.Java. Text. numberformat formater = java. Text. decimalformat. getinstance ();Formater. setmaximumfractiondigits (2 );Formater. setminimumfractiondigits (2 );System. Out. println (formater. Format (3.1415927 ));; AddFormater. setminimumf

Import Java.math.BigDecimal;Import Java.text.DecimalFormat;Import Java.text.NumberFormat;public class Format {Double F = 111231.5585;public void M1 () {BigDecimal bg = new BigDecimal (f);Double f1 = Bg.setscale (2, bigdecimal.round_half_up). Doublevalue ();System.out.println (F1);}/*** DecimalFormat conversion is the easiest*/public void m2 () {DecimalFormat df = new DecimalFormat ("#.00");System.out.println (Df.format (f));}/*** String.Format Printing is the easiest*/public void m3 () {System.o

Package decimal; Import Java.math.BigDecimal; Import Java.text.DecimalFormat; Import Java.text.NumberFormat; /** * Java several ways to retain several decimal places and add thousands separator *

Conversion between decimal places and binary decimal places1. Convert binary to decimalThe basic practice of converting a binary number into a decimal number is to first write the binary number as an expansion of the weighting coefficient, and then sum the values according to the d