how to hanging indent

Upper Kamishirasawa Tone Title Description In Gensokyo, the Kamishirasawa sound is a well-known teacher with a profound knowledge. Spring snow changes cause many roads in the world to be blocked by heavy snow, so that some students can not successfully reach the village where the Hui sound. So the comet decided to change to a village that could gather the largest number of people as a new teaching location. The earth is made up of N villages (numbered 1). N) and M Road, the road is di

1. Press V to enter the visual state, select multiple rows, and use> or 2. generally, auto indent layout is used based on language features: In the command status, the current row is used = (two connections by =), or N = (N is a natural number) indicates that N rows are automatically indented from the current row. You can try to unindent the code and use n = for typographical layout, which is equivalent to the code format in the general ide. You can

runs to If sequentially, it detects the true value (true) and runsX = x + 1, After that,Print xThe statement is not indented, so it is outside of if. If you change the first sentence to I =-1, if you encounter a false value, becauseX = x + 1This sentence is skipped if.Print xThere is no indentation, so it is outside of IF and will not be skipped. Continue execution. ThisFour SpacesIndent to representAffiliationAs we will see in the future. Python emphasizes ProgramReadabilityThis forced

In the new version of Office, you can use custom shortcuts to improve work efficiency. Specific operations: File -- option -- custom ribbon -- keyboard shortcut custom -- find all commands in the category drop-down list -- find indentfirstline in the command on the right -- you can identify it by pressing the new shortcut key below, press Ctrl + j -- click the icon in the lower left corner and close it. After setting it, press the shortcut key and you will see the

{ the for(intI=0; I) the { - intv=G[u][i]; the if(sccno[u]!=Sccno[v]) the inch[sccno[v]]= out[sccno[u]]=1; the }94 } the intA=0, b=0; the for(intI=1; i) the {98 if(!inch[i]) Abouta++; - if(! out[i])101b++;102 }103 intans=Max (A, b);104 if(scc_cnt==1) theans=0;106printf"%d\n", ans);107 }108 return 0;109}View Code

; iintX=L[I].X,Y=L[I].Y;if(Belong[x]==belong[y]) {tag[belong[x]]=1;Continue;} Edgeadd (BELONG[X],BELONG[Y],REV_EDGE,REV_HEAD,REV_CNT); in[belong[y]]++; }}intF[n];voidTopsort () { Queueint>Q for(intI=1; iif(!in[i]) Q.push (i); f[belong[n]]=1;if(Tag[belong[n]]) F[BELONG[N]]+=MAXN; while(!q.empty ()) {intU=q.front (); Q.pop (); for(inti=rev_head[u];i!=-1; i=rev_edge[i].next) {intto=rev_edge[i].to; F[to]+=f[u];if(F[TO]GT;MAXN) f[to]=maxn+1; in[to]--;if(!in[to]) {if(tag[to]f[to]>0) f[to]=ma

) { if(Mp[u][i]) {intv=i; if(!Dfn[v]) {Tarjan (v,u); Low[u]=min (low[u],low[v]); } Else if(V!=FA) low[u]=min (low[u],dfn[v]); } } if(low[u]==Dfn[u]) { intv; CNT++; Do{v=stack[--top]; CPNT[V]=CNT; } while(u!=v); }}intDEG[MAXN];intSeek () {intans=0; for(intI=1; i) for(intj=1; j) if(mp[i][j]cpnt[i]!=Cpnt[j]) {Deg[cpnt[i]]++; DEG[CPNT[J]]++; } for(intI=1; i) if(deg[i]==2) ans++; returnans;}intMain () { while

(v); -low[u]=min (low[u],low[v]); in}Else if(Instack[v]) { -low[u]=min (low[u],dfn[v]); to } + } - if(dfn[u]==Low[u]) { the intV ++Bn; * Do{ $v=stack[top--];Panax Notoginsenginstack[v]=0; -belong[v]=Bn; the++Size[bn]; +} while(u!=v); A } the } + - intD[MAXN]; $ intDfsintu) { $ if(D[u])returnD[u]; - intres=size[u],tmp=0; - for(intI=head[u]; i!=-1; I=Edge[i].next) { the intv=edge[i].v; -tmp=Max (Tmp,dfs (v));Wuyi } the returnd[u]=

, NUM_OF_SCC =0;108memset (DFN,0,sizeof(DFN));109memset (SCC,0,sizeof(SCC)); thememset (VAL_SCC,0,sizeof(VAL_SCC));111Tarjan (0, -1); the 113 if(NUM_OF_SCC = =1){ thePuts"Impossible"); the Continue; the }117 118 //to reconstruct a tree graph with the connected component indented point119memset (First,-1,sizeof(first)); -K_SCC =0;121 for(intI=0; i){122 if(scc[e[i].x] = = Scc[e[i].y])Continue;123 ADD_EDGE_SCC (scc[e[i].x], scc[e[i].y]);124

; Created time:2015 March 16 Monday 12:33 11 seconds ********************************* ***************************************/#include #include #include #include #include #include #include #include #include #include #include using namespace STD;Const DoublePI =ACOs(-1.0);Const Long LongINF = (1LL -);Const DoubleEPS =1e-15;typedef Long LongLL;typedefPair int,int> PLL; LL dp[(1 -) +Ten];structnode{intStaintCostintNum;} fri[ the];intCMP (Node A, Node B) {returnA.num intMain () {intN, M, b; while(

Topic linksTest Instructions: given a graph, ask at least a few points to traverse the full map. And adding at least a few edges makes the graph a strong connected graph. Ideas: for a directed graph, a few strongly connected components are first found, and each strongly connected component is then shrunk to form a dag. The first sentence at the beginning of the question is that the diagram is connected. Then you want to traverse the whole picture. Just to find out how many points are in the 0, a

Php DOMDocument recursively formats indent HTML documents, Function format (\ DOMNode $ node, $ treeIndex = 0) {// unformatted label if (in_array ($ node-> nodeName, array ("title", "p ", "span") return; if ($ node-> hasChildNodes () {$ treeIndex ++; $ tabStart = "\ r \ n ". str_repeat ("TTT", $ treeIndex); $ tabEnd = "\ r \ n ". str_repeat ("EEE", $ treeIndex-1); $ I = 0; while ($ childNode = $ node-> childNodes-> item ($ I ++ )) {if ($ childNode-> n

)) response = Opener.open (req) Print ( Response.read ())"""#Simulation Login unsuccessfulImportHttp.cookiejarfilename='Cookie.txt'Cookies=Http.cookiejar.MozillaCookieJar (filename) opener=Urllib.request.build_opener (urllib.request.HTTPCookieProcessor (cookie)) PostData= Urllib.parse.urlencode ({'Stuid':'******','pwd':'******'}). Encode (encoding='UTF8')#How do we know the names are stuid and pwd??? Loginurl ='http://xxxxxx.com'result=Opener.open (loginurl, PostData) cookie.save (Ignore_discard

(Subtask B). One extension means introducing one new member into the list of receivers of one school.InputThe first line contains a integer n:the number of schools in the network (2 OutputYour program should write, lines to the standard output. The first line should contain one positive integer:the solution of subtask A. The second line should contain the solution of subtask B.Sample Input52 4 3 04 5 0001 0Sample Output12Test instructions: The software is sent in a direction, each school can be

1. After we open WPS, we then create a document, or press CTRL+F1 as shown in the following figure. 2. Then in the pop-up new document Drop-down menu, we click "Style and Format" as shown in the following figure. 3. Then in the pop-up "style and format" We found the text 4. Then click on the back of the text. There will be a modified option, and then open! 5. Then we find the "format" click in the Red box below, as shown in the following figure. 6. Then we click "Paragraph" in the

Title Link: http://poj.org/problem?id=1236Test instructions: Give the network link between the N schools and some schools, the network between schools is one-way side, let you find the answer to two questions, 1. At least how many copies of software are needed so that all schools can receive it. 2. If you want to use a piece of software to make all schools receive the need to add several sidesThe first is to find a strong connected component and then shrink the point, so-called indentation is a

Vim automatically increases indentation when pasting data from the Clipboard, which is a nightmare for Python, a language that requires strict indentation. How do you make it non-indented and keep it in the original format? The answer is paste mode.Before pasting the data, enter the following to specify the open paste mode : Set Paste After the paste is finished, enter the following to specify turn off paste mode : Set Nopaste It is not too much trouble to input each

The configuration file for vim in CentOS is stored in the/etc/vim directory with the configuration file named VIMRCin the terminal, enter the following command to edit the VIMRC configuration file:sudo vim/etc/vim/vimrcor sudo gedit/etc/vim/vimrc1, display line numberadd a new line at the end of the file, enter set Nu2. Syntax highlightingin the file, find "syntax on this line, remove the preceding double quotes", double quotation marks are the meaning of the comment3. Auto Indentadd a line at t