how to make simple chatbot in python

What is virtualenv? Virtualenv can create a standalone python development environment, such as the current global development environment is python3.6, now we have a project to use django1.3, another project needs to use django1.9, this time you can use Virtualenv created the respective Python development environment. Advantages of virtualenv Make dif

I often get questions about email crawlers. There are indications that people who want to grab contact information from the Web are interested in the problem. In this article, I want to demonstrate how to use Python to implement a simple mailbox crawler. This crawler is simple, but you can learn a lot from this example (especially when you want to be a new worm).

to study slowly. The following will be my recent reading study to make a note, of course, this is for reference only, there may be some of their own speculation and ideas, not authoritative basis, the improper place also want to point out. 1. Install SQLAlchemy The installation section is not intended to be described in detail and can be installed via Easy_install or PIP, as follows: Copy Code code as follows: Easy_install SQLAlchemy

Original Reprint Address: http://www.cnblogs.com/91allan/p/4889167.html Needless to say, we often work with the need for HTTP services, if we do not want to engage the complex Apache, IIS servers, and so on, we can use Python to help us build a simple server. The operation is as follows: 1, download and install a python; 2, then set the environment variable, in

= -0.555000 Test no.5:1.11* ((2.22-3.33) * (4.44+ 5.55)/(6.66+7.77) = -0.852992 Test no.6: (1.11+2.22) * (3.33+4.44)/5.55*6.66 = 31.048920 Test no.7: (1.11-2.22) /(3.33+4.44)/5.55* (6.66+7.77)/(8.88) = -0.041828 Test no.8:error: (1.11+2.22) * (3.33+4.44:missing ")", please Check your expression Test no.9:error: (1.11+2.22) *3.33/0+ (34-45): divisor cannot be zero test no.10:error:12+8 9^7:invalid Character: ^ Implementation code The implementation of the stack The stack is actually a res

applications. How does Django distinguish between URLs with duplicate names? For example, Vote s app has a detail view, and maybe another blog app has a view with the same name. How does Django know {%url%} which URL of the app the tag corresponds to?The answer is: Add a namespace to the root URLconf. Make a s/urls.py slight change in the vote file, plus app_name set the namespace: fromDjango.urlsImportPath from.ImportViewsapp_name='votes'Urlpatterns

The new engineer does not know Hbase,java, Python is ok, I suggest he can consider using HBase thrift call, complete the current work. First, install Thrift Download thrift, here, I'm using this version of thrift-0.7.0-dev.tar.gz. Tar xzf thrift-0.7.0-dev.tar.gz cd thrift-0.7.0-dev sudo./configure--with-cpp=no--with-ruby=no sudo Make sudo make install

[]: Re.findall (R ' ab* ', ' abbbbbbb ')OUT[96]: [' abbbbbbb ']Non-greedy mode: match the content of the compound regular condition as little as possibleGreedy mode---"non-greedy mode method: Back Add"? ”That is *? +??? {m,n}?in [+]: Re.findall (R ' ab*? ', ' abbbbbbb ')OUT[100]: [' a ']In [101]: Re.findall (R ' ab+? ', ' abbbbbbb ')OUT[101]: [' AB ']In [102]: Re.findall (R ' ab?? ', ' abbbbbbb ')OUT[102]: [' a ']In [103]: Re.findall (R ' ab{2,4}? ', ' abbbbbbb ')OUT[103]: [' ABB ']Regular expr

the Copy object. Summarize:For shallow copy, deep copy, if the element of the copied object is an immutable type (or non-mutable object)No matter the shallow copy, the deep copy, the change of the original object will not affect this element of the copied object.Because an immutable type of change is actually a new object, it will naturally not affect the original objectWhen the copied object contains elements of a mutable type, changes to the elements of this mutable type of the

When we surf the web on a daily basis, we often see some beautiful pictures, we would like to save these pictures to download, or users used to do desktop wallpaper, or to do design material. Our most common practice is to choose to save as with the right mouse button. But some pictures of the right mouse button is not saved as an option, there is a way to pass through the screenshot tool to intercept, but this reduces the clarity of the picture. All right, ~!. In fact you are very good, right

A simple Python script that determines if the remote server port is on or offImport Socket #导入socket模块sk = Socket.socket (socket.af_inet, socket. SOCK_STREAM) sk.settimeout (1) try:sk.connect ((' 192.168.0.1 ', +)) #连接21号端口 and make a judgment print ' Server Port ok! ' Except Exception:print ' Server port not connect! ' Sk.close ()This

. the case of all characters in the string , call the upper and lower methods, respectively. Upper () is to make all strings uppercase, lower the opposite. For example:>>> str.upper ()'qazwsxedc'>>> str.lower () ' Qazwsxedc ' C concatenation of strings , using the plus sign for stitching, if required, a space string with two strings in the middle. For example: >>> str1 = " adu " >>> str2 = " you Has to more harder!! " >>> str3 =str1 + str2 >>

, Tkinter. END) -Count =0 - forStreinchstr2: -Count = Count + 1 inT.insert (Tkinter. END,'Section'+ STR (count) +'Step:'+ Stre +'\ n') -T.insert (1.0,'[Altogether'+ STR (count) +'Step]\n') to T.pack () +Tkinter. Button (Root, text="Determine", command=calc). Pack () -Root.mainloop ()Then after running the results such as the number of layers of input Hanoi is 3, and then click the OK button below will show the detailedSteps.(PS: Write this is to make