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2017-2018-20172309 "Java Programming" course pair programming Exercises _ arithmetic

2017-2018-20172309 "Java Programming" course pair programming Exercises _ arithmeticTeam member: ShanshaStudy No.: 20172310Blog Address: Click here1. Demand Analysis: can generate the topic:-Enter the number of topics you want to generate and output a set of topics at random levels.-Operator stochastic equal probabilities (subtraction), arithmetic random probabilities (integers, true fractions). Judgment System:-The user enters the answer

2017-2018-2 20172315 "Java Programming" course pair programming Exercises _ arithmetic

Pair of people Hu Zhihui: infix suffix and calculation of suffix expression Peng Lin: Fractional-related procedures and solving small problems Ludasui: Topic generation and Compilation of driver classesDemand analysis Goal1. Automatic generation of topics可独立使用(能实现自己编写测试类单独生成题目的功能)可生成不同等级题目,类似于:1级题目:2 + 5 =;10 - 5 =之类的两个数,一个运算符的题目2. Problem calculation (question)可独立使用实现中缀表达式转为后缀表达式并计算判断用户答题正误,并输出正确结果3. Support True Score可独立使用实现分数算

Pair development returns the sum of the largest sub-array in an integer array

First, the topic requirementsTitle: Returns the and of the largest sub-array in an integer array.Requirements: Enter an array of shapes, with positive numbers in the array and negative values. One or more consecutive integers in an array make up a sub-array, each of which has a and.If the array a[0] ... A[j-1] next to each other, allowing a[i-1], ... A[n-1], a[0] ... A[J-1] and the largest. Returns the position of the largest subarray at the same time.The maximum value for the and of all sub-arr

Pair development---Two-dimensional array

) - { WuN=0; - } AboutSum=0; $ } -y--; -N=0; -} while(y>=0); A } +System.out.println ("Max:" +M); the } -}(3):(4) Cooperation Process:In this cooperation, I am responsible for the preparation of the program, Xin Shin is responsible for the detection of the program, in her test due to the error in the value of the pair when the result is wrong, we analyzed the program after the error wa

C + + pair usage

Brush Leecode has such a problem:Given two arrays of equal size A , the B Advantage of a relative to B can be described by the A[i] > B[i] i number of indexes that are satisfied.Returns A an arbitrary arrangement that maximizes its relative B advantages.The first time I thought about the enumeration method, and then timed out.classSolution { Public: Vectorint> Advantagecount (vectorint> A, vectorint>B) {intMax =0; Vectorint>Maxvector; Maxvector.insert (Maxvector.begin (), A.begin (), A.en

XOR and favorite number (Mo pair algorithm)

E. XOR and favorite numbertime limit per test4 secondsmemory limit per test256 megabytesinputstandard Inputoutputstandard OutputBob has a favorite numberkanda i of length n. Now he asks your to answer m queries. Each query was given by a pair li and Ri and asks you to count th E number of pairs of integers i and J, such thatl? ≤? I? ≤? j. ≤? r and the xor of the numbers ai,? Ai? +?1,?...,? AJ is equal to k. InputThe first line of

Implementation of two-dimensional planar nearest point pair algorithm based on divide and conquer

Summary:There is a lot of discussion on the method of divide and conquer on the Internet, but there is no complete running code, this article mainly introduces a complete and running code for this problem.For those who are interested in the reference.Body:As a comparison, we also implement the nearest point pair enumeration solution, the main function is as follows:#include The above-mentioned force () is the implementation of the enumeration, Callmin

Rsa-java programming: Generate RSA key pair __ algorithm

You can use Keypairgenerator to generate a public/private key pair in your code. Generating a key is a CPU-consuming job. public static void Test3 () throws Exception { //Generate key pair keypairgenerator KeyGen = Keypairgenerator.getinstance ("RSA"); Keygen.initialize (1024); KeyPair key= Keygen.generatekeypair (); the original Byte[]plaintext = "Shaofa". GetBytes (); Encryptio

Agile development "loose pair Programming" series 16: L-Type Code structure (ii) (i) __ programming

This is the 16th article in the "Loose pair programming" series. (Pine pair Programming column directory) Today it's time to reuse a frame (asp.net MVC3, take the range including controller and view) and record the process. There are several features of the L-code structure compared to the general process of reuse: 1. If it is difficult to reuse, before reuse, generally do not deliberately form a "reusable

Linux nginx Load Balancer, SSL principle, generate SSL key pair, Nginx configuration SSL Introduction

encrypted HTTPS protocol, if the HTTPS communication packets are intercepted during transmission, we can decipher the information in these packets, there are some user name, password, cell phone number and other sensitive information, and if the use of HTTPS communication, even if the packet is intercepted, And we can't decipher what's inside. Interpreting the SSL workflow The browser sends an HTTPS request to the server; Server to have a digital certificate, you can make it y

Discussion on the practical application of twisted pair wires in the Video Monitoring System

can supervise and manage the image informatization of paid jobs and provide creden。 for fraudulent behaviors. The monitoring software also displays images of multiple toll channels, toll booths, and important road sections at the same time, and records multiple images at the same time. However, based on my years of experience in cabling, I realized that with the extension of distance, the main character of traditional cabling-coaxial cable is increasingly unable to meet the needs of constructi

Data structure Merge sort-inverse number pair

Reverse order refers to a series of a[1],a[2],a[3] ... Any two numbers in A[i],a[j] (iWhile merging the sorted two permutations of the processThe elements of the ordered sequence on the right are inserted sequentially into the preceding sequential sequence.E.G. (3 7 12) (5 6 8)Insert 5 in (3 7 12)Because the back is ordered, it assumes that all elements of 5 and left are in reverse order, so there are mid+1.And the left sequence has start1 number than 5, so the reverse number is Mid+1-start1This

Hibernate annotations: A pair of primary key associations

(Cascade=Cascadetype.all, Mappedby= "Company") Privatesite site;}Companycontroller.java: Public classCompanycontrollerextendssimplecontroller{@Autowired Sitedao Sitedao; @Autowired Companydao Companydao; @RequestMapping PublicString indexaction (model model, HttpServletRequest request)throwsException { site site = Sitedao.fetchone (1); Company Company = Site.getcompany (); if (company = = null) Company = new company (); if(Request.getmethod ()! = "POST") {Model

Springmvc4+hibernate4+spring4 annotations to a pair of multilevel saves

Javax.servlet.http.httpservletresponse;import Org.springframework.stereotype.controller;import Org.springframework.web.bind.annotation.requestmapping;import Com.h3c.zgc.user.service.PersonService; @Controller Public classPersonController {@ResourcePrivatePersonservice Personservice; @RequestMapping ("Saveperson") PublicString Saveperson (httpservletrequest request) { This. Personservice.saveperson (); Request.setattribute ("Flag","Success"); return "H4/flag"; } @RequestMapping ("Savepersonh

2017-2018-2 20172302 "Java Programming" course pair programming Exercises _ arithmetic

Standard Code specification (to develop appropriate specifications for current development) 60 Design UML Design Project UML class diagram 60 Coding Specific code 1500 Code Review Code review 30 Test tests (Self-test, modify code, commit changes) 300 Size Measurement calculation effort (actual time) 2 2 Postmortem Process Improvement Plan Summariz

The traversal of JS pair image and array

0. General traversal method 0.1 for...in ...Let obj = {0: "A", 1: "B", 2: "C"}; for inch obj) { console.log (Obj[key]) }0.2 for...of ...Let obj = {0: "A", 1: "B", 2: "C"}; for (let value of obj) { Console.log (value) }A. JS Traversal Object 1.1 Object.keys () traversalLet obj = {0: "A", 1: "B", 2: "C"= = { console.log (key, Obj[key]);});1.2 Object.values () traversalLet obj = {0: "A", 1: "B", 2: "C"= = { console.log (key, value);});1.3 Object.entries () traversalLet obj = {0: "A", 1: "

Linux public key Private key pair

://s3.51cto.com/wyfs02/M01/47/C0/wKioL1P_SBzzadrAAADxSvKCIiE725.jpg "style=" float: none; "title=" 4.png "alt=" Wkiol1p_sbzzadraaadxsvkciie725.jpg "/>This holds the public and private keys, and now we're going to copy the public key to the server side.650) this.width=650; "src=" http://s3.51cto.com/wyfs02/M00/47/BE/wKiom1P_RwawUYHFAAH7kvDMrjM558.jpg "style=" float: none; "title=" 5.png "alt=" Wkiom1p_rwawuyhfaah7kvdmrjm558.jpg "/>it copies it to the other's . Ssh/authorized_keys and renamed to A

Pair development--four implementing a cyclic two-dimensional array to find the maximum Subarray

First, the realization of ideasOn the basis of the previous experiment, we implement the ring idea that each column is replaced in turn, until all the two-dimensional arrays that can appear are replaced, and then the previous method of solving the maximal subarray is implemented.Second, the experimental codePackage Com.minirisoft;import Java.io.bufferedreader;import Java.io.file;import java.io.filereader;import Java.util.scanner;public class Huantwoarray {public static int Exchange (int arr[][],

The development of software engineering pair The sum of 2 consecutive maximal sub-arrays in a two-dimensional array

First, the topic requirementsTitle: Returns the number of the largest sub-arrays in a two-dimensional integer array. Requirements: Enter a two-dimensional shape array with positive and negative numbers in the array. A two-dimensional array is connected to the end of the line, like a belt. One or more consecutive integers in an array make up a sub-array, each of which has a and. The maximum value for the and of all sub-arrays.Requires a time complexity of O (n). Second, the design idea first call

Merge sort to find the inverse number pair.

1#include 2#include 3#include 4#include 5 using namespacestd;6 inthigh[100010];7 inttemp[100010];8 intangry[100010];9 intnum;Ten voidMergeSort (intFirstintMidintLast ) One { A intLeft1=first,right1=mid,left2=mid+1, right2=Last ; - intI=0; - while(left1right2) the { - if(high[left1]high[left2]) - { -temp[i++]=high[left1++]; + } - Else + { Atemp[i++]=high[left2++]; atangry[left2]+=right1-left1+1; -num+=right1-left1+1; - for(intJ

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