how to send data to server in android using json

understood as an array (array).Because this kind of data structure exists in some form in most modern computer languages. Therefore, it is possible for a data format to be exchanged between programming languages that are also based on these constructs. For example, when writing API interfaces to Android and iOS, cross-platform support can be implemented in

processing"); in the}Else { the AboutSYSTEM.OUT.PRINTLN ("Request Server failed"); the the } the + -}Catch(Exception e) { theSYSTEM.OUT.PRINTLN ("Request Exception");Bayi Throw NewRuntimeException (e); the } the - returnresult; - } the the}Test receive1 @ Page Language="Java"Import="java.util.*,java.io.*"pageencoding="UTF-8"%>2 3 4 System.ou

Logger = Loggerfactory.getlogger (Httputil.class);Private static final String URL = "Http://***/osa/interface";/*** HttpPost request to send JSON parameter** @param request Parameters*/Public Responsevo Httppostwithjson (String jsonparam) {Responsevo Responsevo = null;try {Defaulthttpclient httpclient = new Defaulthttpclient ();HttpPost method = new HttpPost (URL);Method.addheader (HTTP. Content_Type, "App

Typically, the front end submits data to the server via a POST request in 4 format, "application/x-www-form-urlencoded" format, "multipart/form-data" format, "Application/json" Format and "Text/xml" format. Often the most common is the "Application/json" format, which is the

Recently engaged in an Android app that uses JSON interactive technology to and from the server. Server side I was simply using a servlet to receive requests from the app, processing JSON using the Org.json jar package.Server-side:1. The object to be sent is processed into a

(conn.getresponsecode () = =) {InputStreamReader ISR = new InputStreamReader (Conn.getinputstream ()) ; BufferedReader br = new BufferedReader (ISR); String inputline = null; while ((Inputline = Br.readline ()) = null) {result + = Inputline; } isr.close (); Conn.disconnect (); } else {//If an error occurs, be sure to check the URL pair no! BufferedReader br = new Buffe

JSON file: [ { "Name": "Xujun", "Sex": "Male", "Home": "Nanjing" }, { "Name": "Jack", "Sex": "Male", "Home": "Beijing" } ] The $.ajax of this method, inside the datatype: "JSON" set, if the server returns a JSON-formatted string, it is not necessary to call the Eval method to convert t

Controller controllersUsing system;using system.collections.generic;using system.linq;using system.web;using System.Web.Mvc;using System.web.script.serialization;namespace mvcapplication2.controllers{public class Homecontroller:controller { Public ActionResult Index () {return View (); }//---------------------------------The first notation: Server returns a JSON object public Action

Postjson (String uri, string json,intConnectTimeout,intConnectionrequesttimeout,intsockettimeout) - throwsIOException, ParseException { - if(Stringutils.isanyblank (URI, JSON)) { the return NULL; - }Wuyi theCloseablehttpclient client =Httpclients.createdefault (); -HttpPost post =NewHttpPost (URI); Wu //Create Request Da