hss lte

1. Background and objectives The traditional UMTS wireless communication network is basically designed around the core of the voice service, from the development of 3G, LTE and 4G technology in the future, we can all see that the data service driver plays an important role in the change of network architecture. In the future, communication networks will not only integrate a variety of heterogeneous wireless networks, but also integrate wireless networ

4G + 6 years before 5G 5 Gbps network test speed: 5 Gbps Although the domestic TD-LTE and LTE-FDD of the 4G convergence network test license just recently issued, but unable to cope with the communication equipment vendors run faster: a few days ago, Ericsson announced 5G wireless testing, the maximum network transmission speed is 5 Gbps. Although this data is half faster than the theoretical speed of 5g a

With the continuous development of wireless networks, multi-Stream Aggregation (MSA, Multiple Stream Aggregation) can improve the edge throughput by 500% through deep fusion of Multi-standard, multi-carrier and multi-layer networks, realizing the concept of borderless networks enables users to enjoy high-speed and stable data access services wherever they are on the network. It will become a key technology for network evolution in the future. The popularity of smart terminals and the rapid devel

Which Internet of Things strategies and network strategies are distributed by global operators? --> After several years of preparation and development, the concept of IoT was quickly recognized worldwide and became one of the core driving forces of the new scientific and technological revolution and industrial revolution. According to statistics from Strategy Analytics, as of the end of 2017, nearly 20 billion IOT and networking devices will be deployed worldwide and 10 billion more devices

base station is equipped with large-scale antenna array, and the spatial freedom and effective multipath components formed by multiple antennas are used to improve the spectrum utilization efficiency of the system.Multi-beam AntennasThe multi-beam antenna uses multi-beam to split the sector, thereby increasing the capacity.2G to 4G Base station antenna development2G/3G era, the antenna is more than 2 ports.▲GSM antenna▲CDMA antenna▲LTE-FDD Independen

, so that each page shows 50 records. 2. Duplicate data for a column in the current clustered collection after the query has been removed Copy Code code as follows: Db.userInfo.distinct ("name"); Will filter out the same data in name Equivalent: Select Distict name from UserInfo; 3, Query age = 22 Records Copy Code code as follows: Db.userInfo.find ({"Age": 22}); Equivalent to: SELECT * from userInfo where age = 22; 4. Check the records of age > 22

; 4. Check the records of age > 22 Db.userInfo.find ({age: {$gt: 22}}); Equivalent to: SELECT * from UserInfo where >22; 5. Check the records of age Db.userInfo.find ({age: {$lt: 22}}); Equivalent to: SELECT * from UserInfo where 6. Check the records of age >= 25 Db.userInfo.find ({age: {$gte: 25}}); Equivalent to: SELECT * from UserInfo where age >= 25; 7. Check the records of age Db.userInfo.find ({age: {$lte: 25}}); 8. Query age >= 23 and age D

; 22 Db.userInfo.find ({age: {$gt: 22}}); Equivalent to: SELECT * from UserInfo where >22; 5. Check the records of age Db.userInfo.find ({age: {$lt: 22}}); Equivalent to: SELECT * from UserInfo where 6. Check the records of age >= 25 Db.userInfo.find ({age: {$gte: 25}}); Equivalent to: SELECT * from UserInfo where age >= 25; 7. Check the records of age Db.userInfo.find ({age: {$lte: 25}}); 8. Query age >= 23 and age Db.userInfo.find ({age: {$g

where >22;5. Check the records of age Db.userInfo.find ({age: {$lt: 22}});Equivalent to: SELECT * from UserInfo where 6. Check the records of age >= 25Db.userInfo.find ({age: {$gte: 25}});Equivalent to: SELECT * from UserInfo where age >= 25;7. Check the records of age Db.userInfo.find ({age: {$lte: 25}});8. Query age >= 23 and age Db.userInfo.find ({age: {$gte: $lte: 26}});9. Query the data containing MON

to: SELECT * from userInfo where age = 22;4. Check the records of age > 22 Copy CodeThe code is as follows: Db.userInfo.find ({age: {$gt: 22}});Equivalent to: SELECT * from UserInfo where >22;5. Check the records of age Copy CodeThe code is as follows: Db.userInfo.find ({age: {$lt: 22}});Equivalent to: SELECT * from UserInfo where 6. Check the records of age >= 25 Copy CodeThe code is as follows: Db.userInfo.find ({age: {$gte: 25}});Equivalent to: SELECT * from UserInfo where age >= 25;7. Chec

. Check the records of age >= 25Db.userInfo.find ({age: {$gte: 25}});Equivalent to: SELECT * from UserInfo where age >= 25;7. Check the records of age Db.userInfo.find ({age: {$lte: 25}});8. Query age >= 23 and age Db.userInfo.find ({age: {$gte: $lte: 26}});9. Query the data containing MONGO in nameDb.userInfo.find ({name:/mongo/});Equal to percentSELECT * from UserInfo where name is like '%mongo% ';10, que

Db.userInfo.find ({age: {$lt: 22}});Equivalent to: SELECT * from UserInfo where 6. Check the records of age >= 25Db.userInfo.find ({age: {$gte: 25}});Equivalent to: SELECT * from UserInfo where age >= 25;7. Check the records of age Db.userInfo.find ({age: {$lte: 25}});8. Query age >= 23 and age Db.userInfo.find ({age: {gte:23,lte:26}});9. Query the data containing MONGO in nameDb.userInfo.find ({name:/mong

follows:Db.userInfo.distinct ("name");Will filter out the same data in nameEquivalent: Select Distict name from UserInfo;3. Check the record of age = 22The code is as follows:Db.userInfo.find ({"Age": 22});Equivalent to: SELECT * from userInfo where age = 22;4. Check the records of age > 22The code is as follows:Db.userInfo.find ({age: {$gt: 22}});Equivalent to: SELECT * from UserInfo where >22;5. Check the records of age The code is as follows:Db.userInfo.find ({age: {$lt: 22}});Equivalent to:

});Equivalent to: SELECT * from userInfo where age = 22;4. Check the records of age > 22Db.userInfo.find ({age: {$gt: 22}});Equivalent to: SELECT * from UserInfo where age > 22;5. Check the records of age Db.userInfo.find ({age: {$lt: 22}});Equivalent to: SELECT * from UserInfo where age 6. Check the records of age >= 25Db.userInfo.find ({age: {$gte: 25}});Equivalent to: SELECT * from UserInfo where age >= 25;7. Check the records of age Db.userInfo.find ({age: {$

; 22Db.userInfo.find ({age: {$gt: 22}});Equivalent to: SELECT * from UserInfo where >22;5. Check the records of age Db.userInfo.find ({age: {$lt: 22}});Equivalent to: SELECT * from UserInfo where 6. Check the records of age >= 25Db.userInfo.find ({age: {$gte: 25}});Equivalent to: SELECT * from UserInfo where age >= 25;7. Check the records of age Db.userInfo.find ({age: {$lte: 25}});8. Query age >= 23 and age Db.userInfo.find ({age: {$gte: $

");Will filter out the same data in nameEquivalent: Select Distict name from UserInfo;3. Check the record of age = 22 The code is as follows:Db.userInfo.find ({"Age": 22});Equivalent to: SELECT * from userInfo where age = 22;4. Check the records of age > 22 The code is as follows:Db.userInfo.find ({age: {$gt: 22}});Equivalent to: SELECT * from UserInfo where >22;5. Check the records of age The code is as follows:Db.userInfo.find ({age: {$lt: 22}});Equivalent to: SELECT * from UserInfo where 6.

page, using dbquery.shellbatchsize= 50, which shows 50 records per page.2. Duplicate data for a column in the current clustered collection after the query is removed Copy CodeThe code is as follows: Db.userInfo.distinct ("name");Will filter out the same data in nameEquivalent: Select Distict name from UserInfo;3. Check the record of age = 22 Copy CodeThe code is as follows: Db.userInfo.find ({"Age": 22});Equivalent to: SELECT * from userInfo where age = 22;4. Check the records of age > 22 Copy

after the query is removedCopy CodeThe code is as follows: Db.userInfo.distinct ("name");Will filter out the same data in nameEquivalent: Select Distict name from UserInfo;3. Check the record of age = 22Copy CodeThe code is as follows: Db.userInfo.find ({"Age": 22});Equivalent to: SELECT * from userInfo where age = 22;4. Check the records of age > 22Copy CodeThe code is as follows: Db.userInfo.find ({age: {$gt: 22}});Equivalent to: SELECT * from UserInfo where >22;5. Check the records of age Co

age > 22 Db.userInfo.find ({age: {$gt: 22}}); Equivalent to: SELECT * from UserInfo where >22; 5. Check the records of age Db.userInfo.find ({age: {$lt: 22}}); Equivalent to: SELECT * from UserInfo where 6. Check the records of age >= 25 Db.userInfo.find ({age: {$gte: 25}}); Equivalent to: SELECT * from UserInfo where age >= 25; 7. Check the records of age Db.userInfo.find ({age: {$lte: 25}}); 8. Query age >= 23 and age Db.userInfo.find ({age

How GSM is calculated:A: This is GSM, whether the LTE should be different.ASU conversion to dbm:dbm=-113+ (2*asu)All* Get the GSM Signal strength, valid values is (0-31) as defined in TS* 27.007 8.5if (ASU else if (ASU >=) level = Signal_strength_great (4);else if (ASU >= 8) level = Signal_strength_good (3);else if (ASU >= 5) level = Signal_strength_moderate (2);else level = Signal_strength_poor (1);Lte:The LTE