i3 2120

Ice_cream ' s World I Time limit:3000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 1072 Accepted Submission (s): 638Problem Description Ice_cream ' a rich country, it has many fertile lands. Today, the Queen of

single display configuration, in fact, the power of 250W is enough, the following figure: From the results of actual test data, we can see that in fact, the initial configuration of the power is indeed very low, even in the platform alone, the power is less than 200W, if not with the single show, the Power can also be reduced by dozens of Watts, so in some SNB or APU entry configuration in fact, the rated power of 200W has been completely enough, So for getting started configuratio

int pidemu=14; Period of averagingFor indicator calculation double Lots=1; That mean 0.1 value if your want 1 lot type 10Double tp=17; Take profit profit, take profitDouble sl=7777; Stop Loss Stop Lossint start (){int arraysize=200;Double rsi[];Double rsi_sma[];ArrayResize (rsi,arraysize);ArrayResize (rsi_sma,arraysize);Arraysetasseries (rsi,true);for (int i3=arraysize-1;i3>=0;

Both the Apriori algorithm and the fptree algorithm are the Association Rule Mining Algorithms in Data Mining. They process the simplest single-dimension boolean association rules. Apriori algorithm The Apriori algorithm is the most influential algorithm used to mine frequent item sets of Boolean association rules. It is based on the fact that algorithms use a prior knowledge of the nature of frequent item sets. Apriori uses an iteration method called layer-by-layer search,K-Item Set for explora

T100T200T300T400T500T600T700T800T900 I1, I2, I5I2, I4I2, I3I1, I2, I4I1, I3I2, I3I1, I3I1, I2, I3, I5I1, I2, I3 The basic process of an algorithm is as follows: First, scan all transactions, get 1-item set C1, filter out the item set that does not meet the condition according to the support requirement, and get the frequent 1-item set. Perform the following recursive opera

() { timecost.lock (); int a = ten; Timecost.unlock (); } public static void Main (string[] args) {for (int i = 0; i The performance of the test machine is as follows: Cpu:4 Intel (R) Core (TM) i3-2120 CPU @ 3.30GHz Memory: 8G Test results: 50 Threads: Taslock average time to acquire a lock: 339715 NS Ttaslock average time to acquire a lock: 67106.2 NS 100 Threads: Taslock average time t

and TipsData Size Hint"Data Range"There is 1≤n≤30,1≤m≤12 for 30% of the data.For 50% of the data is 1≤n≤120,1≤m≤50, and 4 kinds of crawling cards, each card will not exceed the number ofOver 20.For 100% of the data is 1≤n≤350,1≤m≤120, and 4 kinds of crawling cards, each card number of cards will notMore than 40;0≤ai≤100,1≤i≤n;1≤bi≤4,1≤i≤m. Input Data Assurance N−1=σmI B1Assuming the remaining T1 Zhang 1,t2 Zhang 2,t3 Zhang 3,t4 Zhang 4, the maximum score is F[T1,T2,T3,T4]Then push forward, the

///////// ///////// AB5A: pausepausepause //////// // CW_GO_2: eval "{I1}-{I2}" mov test, ##+ $ RESULTmov [mem], testmov eax, ID_2shr eax, 10mov I3, axmov eax, ID_2mov I4, axitoa I3, 16.mov I3, $ RESULTlen I3cmp $ RESULT, 04je CW_GO_3 // AB1B: cmp $ RESULT, 03jne AB2Beval "0 {I3}" mov

); in for(inti =1; I i) { -scanf" %d%d%d", a[i].x, AMP;A[I].Y, a[i].z); to for(intj =1; J j) { +COST[I][J] = cost[j][i] = (a[i].x-a[j].x) * (a[i].x-a[j].x) + (A[I].Y-A[J].Y) * (A[I].Y-A[J].Y) + (a[i].z-a[j].z) * (A [I].z-a[j].z); - } the } * edge s1, S2, S3; $ intans, res =0, x1, x2, y1, y2, len1, len2;//X1 Y1 is a triangular face with different sides of the ends len1 for the isosceles triangle of the waistPanax Notoginseng for(intI1 =1;

example above, the confidence indicates the percentage of users who purchased the milk and who bought the eggs. As with support, the confidence will also have an initial value (60% in the above example, indicating that 60% of the users who purchased the milk also purchased the eggs), if the final confidence level is less than the initial value, then milk and eggs can not become a frequent modeSupport and confidence can also be represented by specific data, not necessarily a percentageThe basic

operations if(! Triplearray.array)returnnotpresent; if(i10|| i20|| i30|| i1>=triplearray.m1| | i2>=triplearray.m2| | i3>=triplearray.m3)returnIllegalindex; *x=* (triplearray.array+i1*m2*m3+i2*m3+i3); returnOK;} Status Storearrayitem (Triplearray*triplearray,intI1,intI2,inti3,intx) { if(! Triplearray->array)returnnotpresent; if(i10|| i20|| i30|| i1>=triplearray->m1| | i2>=triplearray->m2| |

be as accurate as possible, in order to ensure easy to understand, may not reach the academic level of accuracy.3) This post emphasizes knowledge and understanding. And in reality, is to spend six hundred or seven hundred to buy a i3, or 1000 buy a i5, the specific situation of the specific analysis, there is no fixed answer.4) If it is local tyrants, just a ' cool ' word. Do not seek cost-effective, only the most expensive. This post is not recommen

The last one has been described when simulating lines through a polygon, the vertex data for each vertex includes: endpoint coordinates, offsets, previous endpoint coordinates, and the last endpoint coordinates, of course, if we are drawing by index, we also include indexed arrays, The following code creates the above related data by passing a group of end points for a set of lines:?```Bk. Line3d = function (points,colors) {??? this.points = Points;??? this.colors = colors;}Bk.Line3D.prototype.c

Java Problem Summary 13-input and output from the keyboard, plus three numbers from the keyboard, output and sort from large to small.Package java2;/** * This is a test from the keyboard input and output * @author xubo601450868 * @time 2015.8.26 * @version v1.0 * */import JAVA.UTIL.SCA Nner;public class Test4 {public static void main (string[] args) {Scanner s=new Scanner (system.in); System.out.println ("Please enter a string"); String S1=s.next (); System.out.println ("Please enter the first n

type (although the string type can be converted to an integer type, but the string must also be a number) integer i3= newinteger ( "abc"); //Compile pass, run times exception: NumberFormatException system. Out.println (I1); system. out.println (I2); } } /span> Take a look at the commonly used methods in integer./*Common methods in integer*/PublicClassintegertest03{PublicStaticvoidMainString[] (args) {Integer i1=NewInt

;public class Calculatoractivity extends Activity {Private random num1=new random ();//Stochastic number generationPrivate random num2=new random ();//Stochastic number generationPrivate random R = new Random ();Private char[] ch = {' + ', '-', ' x ', ' ÷ '}; Character arrayprivate int index = R.nextint (ch.length); Random number, less than the length of the array, 0~3Private char a=ch[index];//get operation symbolPrivate TextView text1,text2,text3;Private EditText answer;Private button surebutt

+ Sb +Sg; + for(inti =1; I ) A for(intj =1; J "%d", a[i][j]); atm++; - for(inti =1; I i; - } - - intComputeintt) { - intN =0, arr[ -], f[ -][ -][ -]; in BOOLb[ -]; memset (b,0,sizeof(b)); - for(inti =1; I ) to if(!B[i]) { + intpos = i, cnt =0; - while(!B[pos]) { theB[pos] =1; cnt++; *pos =A[t][pos]; $ }Panax NotoginsengArr[++n] =CNT; - } theMemset (F,0,sizeof(f)); + intsum =0; Af[0][0][0] =1; the for(

frequent, the candidate is certainly not frequent, so that it can be removed from CK. (Tip: Why do you compress CK?) Because the actual situation of transaction records are often stored on the external storage, such as databases or other formats of the file, in each calculation of the candidate count will need to compare the candidate with all transactions, it is known that access to the external memory is often relatively low efficiency, so Apriori joined the so-called pruning step, The candid

conform to the interface isolation principle, the interface I must be split. Here we split the original interface I into three interfaces, split the design 2 as shown:(Figure 2 follows the design of the interface isolation principle)Routinely post code for a friend who is unfamiliar with class diagrams:[Java]View Plaincopy print? Interface I1 { public void Method1 (); } Interface I2 { public void Method2 (); public void Method3 (); } Interface

name ^ content (or file stream) ^ Byte [] B = Utf32encoding. utf8.getbytes (MSG ); // Simulate the received byte array Int _ I1 = - 1 , _ I2 = - 1 , _ I3 = - 1 , _ I4 = - 1 ; // Used to record the four locations where the separator character "^" appears For ( Int I = 0 ; I B. length; I ++ ){ If (B [I] = ( Byte ) ' ^ ' ){ If (_ I1 = - 1 ){_ I1 = I;} Else If (_ I2 = -