i3 4170

1. Enable Macros2. Record macro (Passbreak after entering macro name)3. View macro---Edit4.vb Editor Delete system automatically generated code enter the following code, save5. Run the macroThe code is as follows:Sub Passbreak ()Dim I As Integer, J As Integer, K as IntegerDim l As Integer, M as Integer, n as IntegerDim i1 As Integer, I2 As Integer, i3 as IntegerDim I4 As Integer, i5 as Integer, I6 as IntegerOn Error Resume NextFor i = 66:for j = 66:fo

. # strace -e trace=file -p `cat /var/run/httpd.pid`getcwd("/var/www/html", 4096) = 14stat64("/var/www/html/i1.php", {st_mode=S_IFREG|0644, st_size=39, ...}) = 0stat64("/var/www/html/i2.php", {st_mode=S_IFREG|0644, st_size=39, ...}) = 0lstat64("/var", {st_mode=S_IFDIR|0755, st_size=4096, ...}) = 0lstat64("/var/www", {st_mode=S_IFDIR|0755, st_size=4096, ...}) = 0lstat64("/var/www/html", {st_mode=S_IFDIR|0755, st_size=4096, ...}) = 0lstat64("/var/www/html/

// Ps_algorithm.h # Ifndef ps_algorithm_h_included # Define ps_algorithm_h_included# Include # Include # Include "cv. H" # Include "highgui. H" # Include "cxmat. HPP" # Include "cxcore. HPP"Using namespace STD; Using namespace CV; # Endif // ps_algorithm_h_marshded /*The program will transfor the colorImage to the gray image.The image must be color image.*/# Include "ps_algorithm.h"Int main (){String image_name ("2.jpg ");Mat image = imread (image_name.c_str ());Mat image_test (image. Size (),

Triangle operation(%i1) trigexpand(sin(10*x+y));(%o1) cos(10 x) sin(y) + sin(10 x) cos(y)(%i2) trigexpand(sin(2*x));(%o2) 2 cos(x) sin(x)(%i3) trigsimp(2*cos(x)^2+sin(x)^2); 2(%o3) cos (x) + 1(%i4) trigreduce(-sin(x)^2+3*cos(x)^2+x);cos(2 x)cos(2 x) 11(%o4) -------- + 3 (-------- + -) + x - - 2 2 22 Algebraic reasoning(%i1) assume(x>0,y(%o1)[x > 0, y (%i2) assume(a(%o2) [b > a, c > b](%i3) facts();(%o3) [x

lexicographically, that means sorted by the lowest number first, then by the second lowest and so on, as demonstrated in the sample output below. the test cases have to be separated from each other by exactly one blank line. do not put a blank line after the last test case.Sample Input 7 1 2 3 4 5 6 78 1 2 3 5 8 13 21 340Sample output 1 2 3 4 5 61 2 3 4 5 71 2 3 4 6 71 2 3 5 6 71 2 4 5 6 71 3 4 5 6 72 3 4 5 6 71 2 3 5 8 131 2 3 5 8 211 2 3 5 8 341 2 3 5 13 211 2 3 5 13 341 2 3 5 21 341 2 3 8 13

the xinit command ). To determine the client to run, startx/xinit first parses the client in the user directory ~ /. Xinitrc file, if ~ /. Xinitrc does not exist. Use the default/etc/X11/xinit/xinitrc, where the Twm Window Manager, Xterm terminal, and Xclock are used by default. Install the graphics card driver This step is special and requires actual hardware operations. This machine is used as an example. It has integrated graphics card and ATI independent graphics card. # pacman -S xf86-vide

Java constant pool and Java constant poolFor an interview question on the internet, find the output result: /** * *@authorDreamSea2011-11-19 */ publicclassIntegerTest{ publicstaticvoidmain(String[]args){ objPoolTest(); } publicstaticvoidobjPoolTest(){ Integeri1=40; Integeri2=40; Integeri3=0; Integeri4=newInteger(40); Integeri5=newInteger(40); Integeri6=newInteger(0); System.out.println("i1=i2\t"+(i1==i2)); System.out.println("i1=i2+

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recorded a video tutorial to solve this problem650) this.width=650; "Width=" "class=" Zoom "id=" AIMG_VEIGP "src=" https://img.alicdn.com/imgextra/i3/332189337/ tb2ql5bxpfyqebjy0fpxxcxcfxa_!! 332189337.jpg "border=" 0 "/>650) this.width=650; "Width=" "class=" Zoom "id=" AIMG_E33P8 "src=" https://img.alicdn.com/imgextra/i4/332189337/ tb2bciqxenaqebjszfkxxac5fxa_!! 332189337.jpg "border=" 0 "/>650) this.width=650; "Width=" "class=" Zoom "id=" Aimg_fect

when they are greater than or equal to 128 and less than or equal to 127.Java wrapper class constant pool detailedpublic class Integertest {public static void Main (string[] args) {Objpooltest ();}public static void Objpooltest () {Integer I1 = 40;Integer i2 = 40;Integer i3 = 0;Integer i4 = new Integer (40);Integer i5 = new Integer (40);Integer I6 = new Integer (0);Integer i7 = 140;Integer i8 = 140;System.out.println ("i1=i2\t" + (I1 = = i2));System.

(sx.comm.ver== "ie") { S.pastehtml (t.outerhtml); } else{ S.insertnode (t); S.insertnode (document.createelement ("BR")); } Sx.event.parseevent (Ww.close, "click"); } Ww.show (e); } function color () { var e=sx.event.target (); if (document.selection) { W.focus (); var s = w.document.selection.createrange (); } else { W.focus (); var s = w.getselection (). Getrangeat (0); } var ww=new wnd (); var colors = ["]," "," "," "," "CC", "FF"]; var cp=document.createelement ("span

. Therefore, they are stored in memory in different locations: The base type is stored in the stack, and the base type wrapper class is stored in the heap. The packaging classes mentioned above all implement the constant pool technique, and the other two types of floating-point type are not implemented. In addition, the string type implements the constant pool technique.Instance:[Java] View plain copy Public class Test { public static void Main (string[] args) { Objpooltest (); }

=0;i3. Problems encountered during commissioning and solutionsWhen a pointer variable is used, the *p++ is applied within the loop to represent the array element.Topic 6-2 Finding the maximum value and its subscript1. Design Ideas(1) Main description problem algorithmThe first step: Define N as 10. The main function defines an integer variable a[n],i,max,p=0;for the loop input array element, which is called by the function Fun (a,p,n) to get the maxim

Computer 2000 Yuan about how to match the machine. in front of the small series in everyone has brought a lot of game configuration, and recently a lot of small partners asked about 2000 yuan how to match the machine, the main use is home study, do not play games. In fact, for such a computer configuration scheme is very good choice. Assemble the computer three piece ok basically OK, the processor chooses six generation, 10 system motherboard, do not show alone, 8GB big memory enough. See Small

//pager.settransitioneffect (transitioneffect.fliphorizontal); //Vertical page //pager.settransitioneffect (transitioneffect.flipvertical); //fan-in swing //pager.settransitioneffect (Transitioneffect.rotatedown); //Bottom sector swing in //pager.settransitioneffect (transitioneffect.rotateup); //Standard //pager.settransitioneffect (Transitioneffect.standard); //tabs (Card form) ///pager.settransitioneffect (Transitioneffect.tablet); //zoom in //pager.settran

var someclosure: (Int, String), String = { The following sentence cannot be gazed at the compiler will report tuple types ' (int,string) ' and ' () ' Hava a different number of elements (2 vs. 0) [unowned Self] (Index:int, stringtoprocess:string), String in//closure body goes here return "A \ (self.cpu Name) "//Closure Reference self}//declares a closure, the same closure references self @lazy var machining: ()-String = {[unowned self] in This sentence is able to stare (according to the bo

Summary: Histogram balancing example Clear all; Close all; CLC; I = [1 5 255 255 100 200 255 200; 17 254 255 100 10 9; 37 10 100 100 2 9 6; 36 10 10 9 2 8 2; 21 8 8 9 3 4 2; 10 7 8 8 3 2 1; 11 8 8 7 2 2 1; 23 9 8 7 2 2 0] % Iw.imread('fig36.bmp '); % I = rgb2gray (I ); % Figure (3) % Imshow (I ); [M, N] = size (I) I1 = max (I); % calculate the maximum value of each column IMAX = max (I1) % to find the maximum value I3 = min (I); % calculates the m

# Include Int main (){Int i1 = lexical_cast Int i2 = lexical_cast Int i3 =-1;Try {I3 = lexical_cast } Catch (...){I3 = 0;} String temp = maid Char ch = lexical_cast Return 0;}; Lexical_cast can easily convert strings and numbers. For example, int i2 = lexical_cast I3 = lexical_cast Char character = lexical_c

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and str3 are generated through new, so the addresses between them are different, so str1! = Str3. For str1 and str4, you can use the String output pool to explain. When this object already exists in the constant pool, no new object will be created when it is used again, directly use the cached object. For str4 = "AB" + "c", JVM will talk about code optimization. The final result is str4 = "abc", which is exactly the same as str2.Integer constant pool We can start with an interview question abou