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Codeforces Round #440 A Search for pretty integers "hash/sort"

namespacestd;intMain () {intN,m,ma=Ten, mb=Ten; intx,y,a[Ten],b[Ten];//or without int, with BOOLMemset (A,0,sizeof(a)); memset (b,0,sizeof(b));//Hash array Note 0, otherwise the result is wrongCin>>n>>m; for(intI=1; i) {cin>>x; A[X]=1; Ma=min (x,ma); } for(intI=1; i) {cin>>y; B[y]=1; MB=min (Y,MB); } for(intI=1; i9; i++) { if(A[i] B[i]) {coutEndl; return 0;//really good, can not be break, otherwise it will be executed sequent

HTML5 Drawing flag with canvas

for (var i=0;i9;i++){ 40 ctx.rotate(Math.PI/5); 41 if(i%2 == 0) { 42 ctx.lineTo((r/0.525731)*0.200811,0); 43 } else { 44 ctx.lineTo(r,0); 45 } 46 } 47 ctx.closePath();

IoT testing guides__ Hardware hacking

passwords enabling Authentication) are available assess the solution to determine if encryption options (e.g. enabling AES-256 where AES-128 is the default setting) are available assess the solution to determine if logging for security events are available assess The solution to determine if alerts and notifications to the user for security events are available I9:insecure Software/firmware Assess the device to ensure it includes upda

Introduction to Ruby Grammar learning

assignment is done with "=". such as a=1,b=1+1 result is: a=1,b=2 = = Compare two values are equal, return true,false such as: a=1; b=1.0; A==b #true Eql? Compares the values of two objects, whether the types are equal, and returns true,false such as: a=1; b=1.0; A.eql? (b) #flase (A is an integral type, B is a floating-point type) Equal Compares two objects in an in-memory address for the same, returning true,false such as: a=1.0; b=1.0; A.equal? (b) #flase a=1.0; B=a; A.equal? (b) # True

The implementation of LR Syntax Analyzer in VC + + environment __c++

projects in the project set: Go (i,x) =closure (J), j={any project in the form of a->αx β | A->α Xβ belongs to i}. According to the above rules, the project set family of this example is calculated as I0-I11, respectively: I0={s '-> E, e-> aa, e-> BB} I1=go (i0,e) ={s '->e} I2=go (i0,a) ={e->a A, a-> CA, a-> D} I3=go (i0,b) ={e->b B, B-> CB, B-> D} I4=go (i2,c) ={a->c A, a-> CA, a-> D} =go (I4,C) I5=go (i3,c) ={e->c B, B-> CB, B-> D} I6=go (i2,a) ={e->aa} I7=go (i3,b) ={e->bb} I8=go (i4,a) ={a-

6 IO redirects for 5 DOS-only files (implementing piping Principles)

, see 103h char, change ' t ', on output, type TXT, see 1~4. act=2Ifdef ARGIF Arg GT 2IF Arg EQ 30Act=30ENDIF IF Arg EQ 31Act=31ENDIF IF Arg EQ 41Act=41ENDIF Std_=arg/10ELSEIF Arg GE 0Act=1Std_=arg IF Arg EQ 0Act=0ENDIFENDIFENDIFENDIF IF ACT EQ 2 is invalid%out/darg=0|1|2|30|31|41. ErrENDIF Just macroLocal J MOV di,es:[26] hit the key, I9 write low ASC, high scan to [1Ch tail text ++],i16 read [1Ah primer + +] to 3f function axSub di,2 CMP di

Sqlmap using Notes

Sqlmap-U "http://url/news?id=1"--level=3--smart--dbms "Mysql"--current-user #获取当前用户名称-Focus on cyber security-P, Z (q% {/O, j% |Sqlmap-U "http://www.xxoo.com/news?id=1"--level=3--smart--dbms "Mysql"--current-db #获取当前数据库名称-Focus on cyber security! j+ M9 \: U (v* o G8 WSqlmap-U "http://www.xxoo.com/news?id=1"--level=3--smart--dbms "Mysql"--tables-d "Db_name" #列表名www.t00ls.net5 m:i) k + Z. G7 B8 xSqlmap-U "http://url/news?id=1"--level=3--smart--dbms "Mysql"--columns-t "tablename" users-d "db_name"-

Basic knowledge of database exercises

of database development.A: Mesh ModelB: Relational modelC: Hierarchical modelD: All of the above5, to ensure the data independence of the database, need to modify is | | c| | 。A: Mode and external modeB: Mode and internal modeC: Two-layer mapping between level three modesD: three-layer mode6, the conceptual model is the first layer of abstraction in the real world, the most famous model of this kind of model is | | d| | 。A: Hierarchical modelB: Relational modelC: Mesh ModelD: Entity-Relationshi

Linux_ (4) Shell programming (bottom)

or more expressions,You do not need to add $ to the variable calculation to represent the variable, specifically: Bash let command.The while loop can be used to read keyboard information.In the following example, the input information is set to the variable film, ending the loop by Echo ' Press Echo-n ' Enter your favorite website name: 'While read filmDoecho "Yes! $film is a good website "Done8. Infinite LoopsSyntax format:While:DoCommandDoneOrWhile TrueDoCommandDoneOrfor ((;;))For ((i=1;ii+++

HDU 4324 Triangle Love (topological sort)

partial order on a set gets a full order on the set, and this operation is called topological ordering.A little more popular is that a point to delete the point, the deletion must be in the degree of 0, if the degree of 0 of all deleted, and the remaining side of the words will produce a deadlock, which must exist in the ring. See the code.1#include 2#include 3#include 4 5 using namespacestd;6 7 intindir[ .];//used to indicate the degree of penetration8 Charmap[ .][ .];//stored in I,j Two-node

[Javascript] memory leaks and circular reference parsing

under IE 8The browser before IE8 cannot clean up circular references between the DOM and JavaScript. This problem is relatively more severe in IE6 versions prior to Windows XP SP3Because the memory cannot be released before the page is unloaded.So SetHandler leaked in the browser before IE 8, elem and these closures can not be cleared.function SetHandler () { var elem = document.getElementById (' id ') elem.onclick = function () {/* ... */}}This behavior exists not only for DOM elements, incl

Auto-boxing and automatic unpacking in Java

programmer coding. */publicclassintegertest06{publicstaticvoidmain (String[]args) {Integer i1nbSp;=newinteger (+); Integeri2=newinteger (10);//There will be no automatic unpacking System.out.println ( I1==I2); //false//compares two integer data for equality and cannot use "= ="//integer has overridden the Equals method in object. SYSTEM.OUT.PRINTLN (i1.equals (I2)); //true//Focus: integeri3=128;integeri4=128;//above is equivalent to//integeri3 =newinteger (+);//integeri4=newinteger (128); Syste

Explanation of IOS name meaning (1)

IP routing(RIP, OSPF, BGP, Static), NAT, VoIP, and Voice over ATM Adaptation Layer 2 (voaal) I9 A simplified subset of IP addresses, removing IP routingRemote nodes and Terminal Services I10 IP routing(RIP, OSPF, BGP, Static), NAT (same as i8), isdn nbar, remove DSL support IBD IP subset, including Transfer Point (2600 ). J J Enterprise Edition, including Protocol Conversion J1 Bas

C + + string input digital output

#include #include using namespace STD;Const Charstr[][4] = {"Yi","ER","San","Si","WU","Liu","Qi","BA","JIU"};Const intNum[] = {2,2,3,2,2,3,2,2,3};//Find the size of the corresponding string. intGetIndex (Char*s) {inti =0; for(;i9; i++) {if(strncmp(Str[i], S,strlen(Str[i])) ==0)returnI }}voidGrial (Char*STR) {Char*p = str;Char*s =New Char[ One];intK =0; while(*p! =' + ') {intindex = GetIndex (p); p + = Num[index];//Skip the number that has been foun

BZOJ1026: [Scoi2009]windy number

[ -][ -],a[110000];typedefLong Longll;voiddp () { for(intI=0; i9; i++) f[1][i]=1; for(intI=2; i A; i++) for(intj=0; j9; j + +) for(intk=0; k9; k++) if(ABS (J-K) >=2) f[i][j]+=f[i-1][k];} ll Get_a (ll x) {ll len=0; while(x) {a[++len]=x%Ten; X/=Ten; } returnLen;} ll Findans (ll Len) {ll ans=0; for(intI=1; i) for(intj=1; j9; j + +) ans+=F[i][j]; for(intI=1; i) ans+=F[len][i]; for(inti=len-1; i>=1; i--)

15. Use of the For loop structure inside C #

In the C # programming language, the For loop is almost identical to the for loop inside Java . We've got a few examples here to let you know about The use of the For loop. Example 1: Calculates The and of 1 to. Console.WriteLine("The beginning of the calculation of 1 to the and:" );intresult;result=0; for(inti=1; i -; i++){Result=result+i;}Console.WriteLine("1 to " and for:{0} " , result);Example 2: Calculates the factorial of a number. For example: the factorial of 6 is:1*2*3*4*5*6. Co

"BZOJ1026" Windy number

the digits if it's illegal to quit immediately./*To the End of the Galaxy*/#include#include#include#include#include#include#include#include#include#include#includeSet>#include#include#defineDebug (x) cerr#defineINF 0x7f7f7f7f#defineLlinf 0X7FFFFFFFFFFFLL#defineP (x, Y) (((x-1) *c) +y)using namespaceStd;typedef pairint,int>Pii;typedefLong LongLl;inlineintinit () {intnow=0, ju=1;CharCBOOLflag=false; while(1) {C=GetChar (); if(c=='-') ju=-1; Else if(c>='0'c'9') { now=now*Ten+c-'0'; Flag=true; }

C # review 3

() the { About return "the overridden ToString ()"; the } the the}View Code4. Show the program run time1 Private voidButton4_Click (Objectsender, EventArgs e)2 {3 //string str = string. Empty;4 //StringBuilder sb = new StringBuilder ();5 ////Display Run time6 //Stopwatch sp = new Stopwatch ();7 //sp. Start ();8 //for (int i=0;i9

C + + array-pass parameter

The number of elements of an array is not passed as an argument to the calling function, which means that C + + does not allow a complete array to be passed to the function as a parameterInstance:1. The formal parameter is a pointer, and the argument includes the array length:1 void myFunction (int *param,int length) {for(1; i++) {"\ t" Endl; } 6} 2. The form parameter is an array of defined size:void myFunction (int param[]){for(0; i9; i

C Language Job 9

1. Write the function to determine whether the character entered by the user is a symmetric string (that is, a string that is the same as the Read and rewind). For example, "Xyzyx" and "Xyzzyx" are symmetrical.#include #includeintMain () {intF,i=0, a[ -],n,j; Charx; Do{i++; X=GetChar (); A[i]=(int) (x); } while(a[i]!=Ten); N=i; if(n==3|| n==4) { if(a[n-1]==a[1]) GotoEND1; Else GotoEND2; } for(j=1; Fj2); J + +) {f=0; if(a[j]==a[n-J]) F=1; } if((float) j

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