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Objective Solution of A Baidu pen exam (+ 1 implementation-1)

~ Life on the Code:Click the plus sign to expand! Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->Def Add1 (x): # O (1) Return (x + 1) Def add (x, y): # O (y)For Loop in range (0, Y ):X = Add1 (X)Return x Def MUL (x, y): # O (xy)Ret = 0For Loop in range (0, Y ):Ret = add (Ret, X)Return ret Def sub1 (x): # O (X)"Notice sub1 (0) is always 0"Ret = TMP = 0;For Loop in range (0, x ):Ret = TMPTMP = Add1 (TMP)Return ret Def sub (x, y): # O (xy)"Since

Segment and rectangle intersect POJ 1410

}; + - structline{ $ Point s,e; $ intInx; - Line () {} - Line (Point _s,point _e) { theS=_s;e=_e; - }Wuyi }; the - //Line Line[n]; Wu BOOLInter (line L1,line L2) { - return AboutMax (l1.s.x,l1.e.x) >= min (l2.s.x,l2.e.x) $Max (l2.s.x,l2.e.x) >= min (l1.s.x,l1.e.x) -Max (l1.s.y,l1.e.y) >= min (l2.s.y,l2.e.y) -Max (l2.s.y,l2.e.y) >= min (l1.s.y,l1.e.y) -SGN ((l2.s-l1.s) ^ (L1.E-L1.S)) *SGN

bzoj1069: [SCOI2007] Maximum land area

Convex hull, (rotating jam). The first 4 points required must be on the convex hull, so a convex hull should be asked first. Then enumerate the first point, and its diagonal. And then the other two points make up a triangle with each of them. Depending on the nature of the convex polygon, the direction of movement of the triangle is monotonous, so the complexity of the enumeration is O (n^2). #include #include#include#include#defineEPS 1e-6using namespacestd;Const intMAXN = -+Ten;structVector {D

[Poj 1113] Convex Hull for geometric computation (1) {VOLUME wrap algorithm}

{ $ Inline on } Const Zero = 1e-6 ; Maxn = 100000 ; Type Point = Record X, Y: extended; End ; VaR P: Array [ 1 .. Maxn] Of Point;Ch: Array [ 1 .. Maxn] Of Longint;Temp, n, m, I, J, K: longint; Function SGN (X: Extended): longint; inline; Begin If ABS (X) Zero Then Exit ( 0 ); If X 0 Then SGN: =- 1 Else S

Uvalive 4431 Fruit Weights--floyd, differential constraints?

; Ms.clear (); for(i=1; i2*n;i++) { for(j=1; j2*n;j++) Mp[i][j]=Mod; Mp[i][i]=0.0; } for(i=1; i) {scanf ("%d",a); CIN>>R; if(!ms[s]) ms[s] = + +tot; U=Ms[s]; scanf ("%d",b); CIN>>S; if(!ms[s]) ms[s] = + +tot; V=Ms[s]; MP[U][V]= Min (Mp[u][v],log (Double) b/(Double) (a)); } for(k=1; k) { for(i=1; i) { for(j=1; j) Mp[i][j]= Min (mp[i][j],mp[i][k]+Mp[k][j]); } } strings1,s2; scanf ("%d",a); CIN>>S1; intK1 =MS[S1]; scanf (

"Effective Java" reading Records-12th-consider implementing the comparable interface

be followed . Here is the write description, the symbolic sgn (expression) that represents the Signum function in mathematics, which returns 1, 0, or 1, depending on the value of the expression (expression) as negative, 0, and positive. The implementing person must ensure that all x and Y are satisfied with sgn (X.compareto (y)) ==-sgn (Y.compareto (x)). The imp

IPhone OS 4.0 released Apple mobile phones into the multitasking Era

added social networking feature of iPhone OS 4. It brings together iPhone/iPod Touch gamers all over the world to invite friends to the game and include rankings, items, and other elements, as an interactive game SNS platform, Apple once again put huge pressure on Sony, Nintendo, and Microsoft Xbox.    IPhone OS 4 social networking functions game center   VII. IAD: IAD is also a new feature that has b

An example of an addition to the swift version of Adbannerview ads

Apple's official advertising has 4 kinds, today introduced Adbannerview, that is, the common bar-style ads Development process I. Application In the itunes connect to apply for advertising permission, this Google will have, a lot of tutorials!! When setting up the bank card, to inquire "modern payment system line number", can be found in this page of Zhejiang Merchant Bank Https://e.czbank.com/CORPORBANK/QYUK Second, the Code By adding the IAD fr

C # Switch wallpaper using activedesktop, suitable for most image formats

component pcomp, int dwreserved); void get1_topitemcount (Out int lpicount, int dwrese Rved); void getasktopitem (INT ncomponent, ref component pcomp, int dwreserved); void getasktopitembyid (intptr dwid, ref component pcomp, int dwreserved. lpwstr)] string pwszfilename, [in] ref component pcomp, int dwreserved); void addurl (intptr hwnd, [financialas (unmanagedtype. lpwstr)] string pszsource, [in] ref component pcomp, addurl dwflags ); Void getasktopitembysource ([delealas (unmanagedtype. lpws

Valid Java, inclutivejava

Valid Java, inclutivejava When the Comparable interface is implemented, the instance of the class itself has an inherent ordering relationship (natural ordering ).Therefore, this class can collaborate with many generic algorithms and collections.The only method we need to implement the Comparable interface --CompareTo. The following are related rules: Sgn (x. compareTo (y) =-sgn (y. compareTo (x )) (X. c

Halcon programming-texture-based Mara detection

)Dev_open_window (0, 0, 640, 480, ' black ', windowhandle)Set_display_font (WindowHandle, +, ' courier ', ' true ', ' false ')Dev_set_draw (' margin ')Dev_set_line_width (3)Dev_set_color (' Red ')For f: = 1 to 2 by 1Read_image (image, path+f$ '. 2i ')DECOMPOSE3 (Image, R, G, B)* Defects is characterized by dark patches. Hence, by substracting the* Estimated background illumination from the original image the* Defects become more apparentEstimate_background_illumination (B, ImageFFT1)Sub_image (B

Surround the Trees (convex bag)

(A-B) * (Ab));} /** Find convex hull, Graham algorithm * point number 0~n-1* return convex hull result Stack[0~top-1] is the number of the convex hull*/Const intMAXN =1010; Point LIST[MAXN];intStack[maxn],top;//Polar Order relative to list[0]BOOL_cmp (Point p1,point p2) {DoubleTMP = (p1-list[0]) ^ (p2-list[0]); if(SGN (TMP) >0) return true; Else if(SGN (tmp) = =0

Maple Trees (minimum cover circle)

(Point A,point b) {returnsqrt (A-B) * (Ab));} /** Find convex hull, Graham algorithm * point number 0~n-1* return convex hull result Stack[0~top-1] is the number of the convex hull*/Const intMAXN = the; Point LIST[MAXN];intSTACK[MAXN];//the point used to store the convex hullintTop//indicates the number of midpoints in the convex hull//Polar Order relative to list[0]BOOL_cmp (Point p1,point p2) {DoubleTMP = (p1-list[0]) ^ (p2-list[0]); if(SGN (TMP) >

HDU 4793 Collision -- solving equations

points that intersect the circular area. One pitfall is that T's solution may be negative and should be determined. Code: #include #include #include #include #include #include #define eps 1e-8using namespace std;#define N 10007int sgn(double x){ if(x > eps) return 1; if(x return -1; return 0;}int main(){ double Rm,R,r,x,y,vx,vy; while(scanf("%lf%lf%lf%lf%lf%lf%lf",Rm,R,r,x,y,vx,vy)!=EOF) { double A1 = (vx*vx+vy*vy);

Local sensitive Hashi Ksh

, we first need to define the remainder matrix, that is, the second item in the objective function, and then how to change after one bit. As followsApparently, R0=rs. Where A * is an already-completed parameter.The objective function of a single solution, then, is:In the first step equation, the first item is always equal to the square of L, and R does not change with a, so they are constants.Therefore, the single-step objective function becomes:Spectral easing (spectral relaxation)In order to s

POJ scrambled Polygon convex bag

#include#include#include#defineEPS 1e-8using namespacestd;structpoint{Doublex, y;};Const intMAXN = -;p oint p[maxn], pp;//pp is the datum pointintN;intSgnDoublex) { if(Fabs (x) EPS)return 0; returnX 0? -1:1;}Doubleget_direction (Point P1, point P2, point p3) {return((p3.x-p1.x) * (P2.Y-P1.Y)-(p2.x-p1.x) * (P3.Y-p1.y));}Doubleget_distance (Point p1, point p2) {returnsqrt ((p1.x-p2.x) * (p1.x-p2.x) + (P1.Y-P2.Y) * (P1.Y-p2.y));}BOOLcmpConstPoint P1,ConstPoint p2)//The comparison function of pol

Poj 2187 calculates the farthest point of the plane and the rotating jamming case of the convex hull

Without a doubt, the farthest point must be on the tubao. So we can calculate the convex hull first, and then enumerate the vertices on the tub. At this time, the point will be much less than in the original situation. The convex hull uses the quick tubao method. In some cases, this method degrades to N ^ 2. Http://www.cs.princeton.edu/courses/archive/spr10/cos226/demo/ah/QuickHull.html: Daniel blog: http://www.cnblogs.com/Booble/archive/2011/03/10/1980089.htmlView Code // Fast tubao algorithm,

Reading notes: Neuralnetworksanddeeplearning Chapter3 (2)

regularization effect is often good in neural networks, in most cases we will be regularization of the network.L1 regularization of other regularization techniquesThe L1 regularization form is similar to the L2, except that the regularization term is slightly different:\[c=c_0+\frac{\lambda}{n}\sum_w{|w|} \tag{95}\]Let's look at the impact of L1 regularization on the network.First, we have a 95-type bias guide:\[\begin{eqnarray} \frac{\partial c}{\partial W} = \frac{\partial c_0}{\partial W} +

Codeforces Round #384 (Div. 2)//review-like pressure ... Explode boom at penalty

Don't want to owe the question .... More dozen dozen CF just know oneself IQ is insufficient ah ...A. Vladik and flightsGive you a 01 string the same between casually fly no cost different fly need cost for ABS I-jReally test instructions kill Ah,,, actually we only consider the cost of 01 conversion must be 1 if the destination and the starting point of the same cost is 0The difference is definitely 1 because 0 is bound to have 1#include #include#include#include#includeSet>#includestring.h>#inc

G.711 Audio Encoding

A law and U law is defined as follows: a law code is a compression/decompression algorithm for pulse coding defined by ITU-T (International Telecommunications Institute of Standards. Most countries in the world adopt the law compression algorithm (including China ). The United States uses the U law Algorithm for pulse encoding. The English definition is roughly as follows: A-Law and U-law are companding schemes used in telephone networkGet more dynamics to the 8 bit samples that is available wit

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