imap server not responding

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Timeout time has arrived. The time-out elapses before the operation completes or the server is not responding.

Connect timeout=18000; "constr" connectionstring="Data source=127.0.0.1;initial CATALOG=HXMRP_PRD; User Id=sa; Password=sa_sa; Max Pool size=150; Connect timeout=18000; " />Also some say is Connect timeout=500;But it does not seem to solve my problem, the same 30 seconds after continuing to error .....After the CSDN blog, find a Solution: http://blog.csdn.net/ulark/article/details/5208779 (original)The commandtimeout code for setting SqlCommand is as follows:SqlCommand cmd = new SqlCommand ()

"Original" server 10.192.242.184 not responding, still trying

When the mount file system on the arm Development Board has been error-checking on the internet, most of them say that UDP drops are a serious cause, and there is no solution to the problem after the attempt.Finally found that the arm Development Board and other people's board IP conflict = =1. Use arp-a to view IP and corresponding Mac, find MAC address inconsistent with your own Development Board MAC address, initial suspicion is IP conflict[Email protected]:/usr/share/python/ns$ arp-aUdp16124

SQL Server (MSSQLSERVER) failed to start, prompting "request failed or service not responding in a timely manner

Tags: style io ar os sp for strong file data1.SQL Server (MSSQLSERVER) startup failure, prompting " The request failed or the service did not respond in a timely manner. ---------------------------SQL Server Configuration Manager---------------------------The request failed or the service did not respond in a timely manner. See the event log or other applicable error logs for more information.--------------

phpMyAdmin connection MySQL appears 2002 server is not responding

Yesterday, when using phpMyAdmin to connect to MySQL, there was a #2002– server that was not responding (or the socket for the local MySQL server was not configured correctly), but I did not have any problems with the PHP connection. The code is as follows Copy Code $link =mysql_connect ("127.0.0.1", "root", "password");if (! $link)

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