imei sv

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Reproduced At instruction detailed

forbidden to convert to the Me original character set).Test result:at+cscs?+cscs: "PCCP437"Ok1.11 AT+CGSNCommand explanation: Query the IMEI number of the module.Command format: at+ cgsnCommand returns:Test result:at+cgsn012345678901234OkNote: If the display 012345678901234 indicates that the module does not write the IMEI number, there is an IMEI numberShould b

Unity pack Android Games part of the problem summary

One: Virtual navigation bar block to the game button:The solution is as follows:1. Hide the virtual navigation bar when you get the focusNavigation Bar Hidden Navigation bar2. When the navigation bar appears, change the game interface sizeUnity tidbits:changing the visibility of Android ' s navigation and status bars, and implementing immersive modeTwo: Unity and Android call each other:Https://coding.net/u/fatlin/p/unity_android_plugin/gitThree: Get the phone

[Android] obtains information about the mobile phone's hardware and android hardware.

void onCreate (Bundle savedInstanceState) {super. onCreate (savedInstanceState); setContentView (R. layout. activity_main); mTextView = (TextView) findViewById (R. id. textViewId); getPhoneInfo ();}/*** get mobile phone information */public void getPhoneInfo () {Telepho NyManager tm = (TelephonyManager) this. getSystemService (TELEPHONY_SERVICE); String mtyb = android. OS. build. BRAND; // mobile BRAND String mtype = android. OS. build. MODEL; // mobile phone MODEL String

Java encoding and JSON

1. Encodingserialization (UrlEncode encoding): UrlEncode encodedString a= "[{\" clubno\ ": \" 10000002\ ", \" clubtype\ ": \" 1\ "},{\" clubno\ ": \" 10000003\ ", \" clubtype\ ": \" 4\ "},{\" clubno\ ": \" 10000004\ ", \" clubtype\ ": \" 3\ "}]";Encode string A through UrlEncode: a = Java.net.URLEncoder.encode (A, "utf-8");deserialization (UrlDecode decoding):String a= "%5b%7b%22clubno%22%3a%2210000002%22%2c%22clubtype%22%3a%221%22%7d%2c%7b%22clubno%22%3a%2210000003%22% 2C%22CLUBTYPE%22%3A%224%

Sharing fruit powder skills with good iPhone6 plus 10 tips

 1, the website quickly check whether the iphone has a lock With the popularity of the iphone, more and more users are using the iphone, but how quickly do you know if the iphone has a lock for the fruit powder? You can quickly query through the site, such as the common site iphoneox.com. The specific use method: The first step, in the settings of the application, the Common Options page, click into the "about this machine", you can view the IME

Android Gets the native number problem and gets the system version information

1, using the method provided by Telephonymanager, the core code: The code is as follows Copy Code Telephonymanager TM = (Telephonymanager) this.getsystemservice (Telephony_service);String IMEI = Tm.getdeviceid (); Take out the IMEILOG.D (TAG, "IMEI:" +imei);String Tel = tm.getline1number (); Remove MSISDN, most likely emptyLOG.D (TA

Android WebView FAQ and Solutions _android

Onwebviewresource method, and then the request header to be added to the end of the URL in get formIn the Shouldinterceptrequest () method, you can intercept resource requests in all Web pages, such as loading JS, images, Ajax requests, and so on. Ex: @SuppressLint ("Newapi") @Override public webresourceresponse shouldinterceptrequest (WebView view, String url) { //non-hyperlink (such as Ajax) request cannot directly add the request header, now stitching to the end of the URL, w

Codeforces Round #364 (Div. 1) 700B (tree)

Main topicThere are 2k matching points on the tree of N nodes, pairing them 22 to make the distance and maximum outputSelect a Point vLV Expression v with the side of the fatherSo consider the number of times the LV is passed, for one of the largest cases, the LV should be min (SV, 2*K-SV), where SV is the point in the V subtree that needs to be paired (including

[Home Squat University Mathematics magazine] The No. 435 issue of the seventh Chinese College Students Mathematics Contest Preliminary Examination Questions (mathematics, October 2015) Reference solutions

I. ($ $) Set $L _1$ and $L _2$ is a two-plane line in space. In the standard Cartesian coordinate system, the line $L _1$ the point of the $a $, in the unit vector $v $ for the straight line direction, and the line $L _2$ the point with the $b $, in the unit vector $w $ To a straight line direction. (1). Proof: There is a unique point $P \in l_1$ and $Q \in l_2$ makes two-point connection $PQ $ while perpendicular to $L _1$ and $L _2$. (2). $P $ point and $Q $ point coordinates (expressed in $a,

Reflected emit Implementation (2)

After thinking about it, I posted the field, but to be honest, I cannot decide which one is the best solution (the reason is as follows ). Code Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->Public class user { Internal string _ username; Public String username {get {return this. _ username;} set {This. _ username = value ;}} Internal Int? _ Id;Public Int? Id {get {return this. _ id;} set {This. _ id = value ;}}} That is to say, the field mu

Implicitly convert type "Int" to "short" causes and solutions

Take a look at the following Code : Copy code The Code is as follows: sbyte SBA, SBB, SBV; SBA = 1; SBB = 2; SBV = SBA + SBB; Byte Ba, BB, BV;BA = 1;BB = 2;Bv = BA + BB; Short SA, Sb, SV;Sa = 1;SB = 2;SV = SA + Sb; Ushort USA, USB, usv;USA = 1;USB = 2;Usv = USA + USB; Do you think this code can be correctly executed? What will happen? The result is: a compilation error occurs in this Code.The co

Fifth algorithm-Gem and stone algorithm

TopicThe given string J represents the type of gem in the stone, and S the string represents the stone you own.SEach character represents a type of stone you have, and you want to know how many of the stones you have are gems. The J letters in are not repeated, J and all the S characters in are letters. Letters are case-sensitive, so "a" and "A" are different types of stones. AnalysisGive two strings, comparing the number of repetitions of a string in the data in another string

Linux Learning Notes < 20 >--System Clipping II

On the basis of one of the system clipping, the system is added such as Mount file system, shutdown restart, set hostname, run corresponding level of service script, start terminal, load NIC driver and enable network.Mount File System① re-mount the root file system for read-writeVim edit/mnt/sysroot/etc/rc.d/rc.sysinit Add to Downlinkecho "Remount rootfs ..."Mount-n-O REMOUNT,RW/②vim Edit/mnt/etc/fstab/DEV/SDB2/EXT3 Defaults 0 0/dev/sdb1/boot ext3 defaults 0 0Proc/proc ext3 defaults 0 0Sysfs/sys

Implicitly convert type ' int ' to ' short ' the reason and solution _ practical Tips

Look at the following code: Copy Code code as follows: SByte SBA, SBB,SBV; SBA = 1; SBB = 2; SBV = SBA + SBB; byte Ba, BB, BV; ba = 1; bb = 2; BV = ba + bb; Short SA, SB, SV; SA = 1; SB = 2; SV = sa + sb; ushort USA, USB, USV; USA = 1; USB = 2; USV = USA + USB; Do you think this code can be executed correctly? The result: This code will have a

The uniqueness of Android

1.IMEItelephonymanagertm= (Telephonymanager) This.getsystemservice (context.telephony_service); stringimei=tm.getdeviceid (); LOG.V ("Ola_log", "IMEI:" +imei); Permissions:Description: The phone's IMEI Value Cons: Some of the only Wifi tablet, the obtained value is NULL2.Android_idString android_id = secure.getstring (This.getbasecontext (). Getcontentre

IPhone 6s need to do after hand

1. Check the housingBefore and after the two parts of the casing are closed tight, the gap is very large, the identification method is to carefully observe the front and back of the shell seams have been tilted or thought to open traces. See if the two screws under the iphone's fuselage have been touched by a screwdriver.See if the edges are polished or damaged.Hearing holes, charging holes with no dustScreen without fingerprints, whether the screen is a yin-yang screen, sliding is smoothis the

Mark a high CPU problem caused by GC

Record my windbg debugging journey. Problem description: There is a project with a high CPU jump. Please come out immediately for windbg 1. adplus packet capture; 2. windbg open the file and run. Load SOS; 3. Run! Threads, found that the process 71 and 77 have exceptions, GC is disabled; 4 .~ 71 s switch to this thread ,! Clrstack view hostingCodeTo see which page it is. The page is imei_list.aspx; 5 .! DSO, a string is found to report the following error: 0: 071>! Dsoos thread ID:

Get the current app version number and system version number

/*** Get app Crash exception report** @param ex* @return*/Private String Getcrashreport (context context, throwable ex) {PackageInfo pinfo = getpackageinfo (context);StringBuffer exceptionstr = new StringBuffer ();Exceptionstr.append ("Version:" +Pinfo.versionname+ "("//version number of the current app.) Corresponds to the version number set in the manifest+ Pinfo.versioncode + ") \ n");Exceptionstr.append ("Android:" +Android.os.Build.VERSION.RELEASEVersion number of the system+ "(" +Android.o

Java Server calls jpush Aurora push API to push notification messages

Calling the jpush API has been described in detail on the official website. I just wrote a small demo for testing! Register an account on the official website of Aurora push to obtainApplication ID (Ppkey),APIMastersecret,APK application. Install and run the APK on your mobile phone, Background test code: Package COM. zensoftware. test; import CN. jpush. API. errorcodeenum; import CN. jpush. API. jpushclient; import CN. jpush. API. messageresult; public class testpush {jpushclient jpush = new jp

AFN synchronous asynchronous request and afn synchronous asynchronous request

AFN synchronous asynchronous request and afn synchronous asynchronous request Asynchronous request: -(BOOL) getOnlyKey1 {NSString * myUUIDStr = [[UIDevice currentDevice] identifierForVendor] UUIDString]; _ block bool isTrue = false; AFHTTPRequestOperationManager * manager = [Queue manager]; manager. responseSerializer. acceptableContentTypes = [NSSet setWithObject: @ "text/plain"]; NSString * urlstr = [NSString stringWithFormat: @ "http: // 122.225.89.70: 28080/try/check"]; NSURL * url = [NSURL

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