Ultraviolet A 562 Dividing coins (01 backpack basics), dividingcoins
[Question link]: click here ~~
Code:
/** Problem: Ultraviolet A No. Running * Running time: 0 MS * Complier: C ++ * Author: ACM_herongwei * Create Time: on Wednesday 11, X zeroonebags * used half of the total value of the gold coin as the backpack capacity, and then zeronebags */# include
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Problem description:There are three kinds of coins: 1 $, 2 $, 3 $. given a chique of N $(0 Sample input: 1 2 3Sample outpt: 1 2 3
That is to say, I want to change the check for N $ to 1 $, 2 $, and 3 $. How many exchange methods are there? The question seems simple, the problem is that ACM-ICPCProgramThere is a strict limit on the running time of, for the input is 10 ^ 9 such a large number to calculate its exchange method is not goodAlgorithmIt too
The difficulty of the provincial competition in the year before was that the stone was not well handled.
Later I read the summary of Yang Shen's provincial competition and found that this stone is here, because there are only four or five sub-members, it is enough to deal with violent DFS. First, we regard the stone as a common obstacle, perform a full graph of DFS or BFs, find the available points, and then each time the DFS explores a new point in a new area, we can figure it out.
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BFS + DFS
Complex search questions.
Because the data is small, there are up to five rock databases, up to 10 coin databases, and up to 4 ^ 5 = 1024 states for moving rock;
Ideas:
Take the coin that can be obtained in the current status and set the current location of the map to '.' (the location of the coin to be removed is empty)
After coin is taken away, you can search for it once. When rock is found to determine whether it can be pushed, you can create a new map and set the Rock Point '. '(nu
My wife was very happy to have finally successfully modified the fishing talents on the iPad.
Paste the complete process and required tools.
Not in the lab. I will give a rough look at the principle. When I get home, I will sort out the relevant tools and update them.
1 first, if your iPad is out of jail
2. Connect your iPad to 91
3. Back up existing archives first
4. Open the archive with a software that can modify SQLite.
5. zsignnum and zplayermoney match each other (this
long-time problem, according to he said is because before the 360, and then the whole computer regardless of how to set the best resolution, see things are enlarged and not clear, because afraid of trouble, big thousands of of the computer, Fang teacher so always make use of! 100 More bucks!Anyway I remember Fang teacher owes me 150 soft sister currency. When I publish my essay, I choose the classification of the website, so it's awkward!There is no operating system installed this option! The c
Given a sequence, can only take D, next door will flip, ask can all take away.Notice that if you can take it, it's okay to take the order of D. Simulation can#include #include#include#include#includeusing namespacestd;#defineINF (0X3F3F3F3F)typedefLong Long intLL; #include#include#include#includeSet>#include#include#includestring>Const intMAXN = 1e5+ -;CharSTR[MAXN];CharSUB[MAXN];voidWork () {Charbook[ the]; book['B']='D'; book['D']='B'; intN; scanf ("%d",N); scanf ("%s", str+1); strcpy (Sub+1,
Hdu 1398 Square Coins (primary function, full backpack), hducoins
Link: hdu 1398
There are 17 currencies with an unlimited denomination of I * I (1
Given a value of n (n
Analysis: You can use the idea of the primary function to pre-process the values less than 300.
You can also use a full backpack to calculate the number of solutions within 300.
Primary function:
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Full backpack
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Hdu1398, just learned the master function, I w
From mona1 coins to billionaires
A coin, find a brother on the road to buy 50 fake money;Call the 50 pieces of books and periodicals kiosk at the entrance of the primary school and get 49 yuan of 6 yuan of real money from Grandpa Hua's eyes;Buy yellow disks in the underground market and buy 9 disks at a price of 4 cents. Take the longest distance to the nearby county, and buy 135 yuan at the price of 15 RMB each;5 RMB for the return trip, 260 yuan
Mashup, whether displaying photos of houses for sale or current weather conditions, locations of supermarkets and restaurants, natural gas prices, and summer vacation photos, has changed the way people use the Internet to view and display information. The data tells you a story.
This section describes several ways to use Microsoft popfly to build map mashups.
PopflyMapMashup1: Photos, gold coins and houses for sale
In this course, the interprete
Question: There are two n bowls of noodles, each time you throw a coin to determine which one to eat (until one to finish eating), and ask about the expected mathematical expectations of the coin.
Analysis: Dynamic Planning and probability DP. Calculate the probability of each ending state (that is, there is a way to finish) and multiply the step by the expected step.
Rhubarb solution: number of remaining bowls in the state bit, reverse solution, state equation:
DP [I] [J] = (DP [I-1] [J] + dp [
[Live broadcast notice] Q A for the Free Open Class of 3D Game Engine in July 18, and participate in sending C coins !, 3d Open CourseGood news!
To thank the majority of students, CSDN has released a free technical Q A class for iOS and 3D game engine development, allowing you to have a full summer vacation ~ To participate in this open course, you will have the opportunity to earn 50C!
Public Q A course time:-, January 1, July 18
Q A: Jiang xuew
Hdu 1398 Square Coins (primary function), hducoins
#include
Backpack
#include
Copyright Disclaimer: This article is an original article by the blogger and cannot be reproduced without the permission of the blogger.
the eye next to gloat has been watching the play of friends and subordinates Zhong Tianxing.Then the eyes sweep to the girl under the body, a slap face, heroic spirit of eyebrows, bright big eyes are flashing anger staring at themselves, rich lips because of anger and a one-off, pretty red short hair as the sky red clouds.This is a beautiful and full of wild little lion.Liang hook up the lip, make her hand change to hug in her waist, pull out a touch of cold and charming smile: "Baby, I was wro
the eye next to gloat has been watching the play of friends and subordinates Zhong Tianxing.Then the eyes sweep to the girl under the body, a slap face, heroic spirit of eyebrows, bright big eyes are flashing anger staring at themselves, rich lips because of anger and a one-off, pretty red short hair as the sky red clouds.This is a beautiful and full of wild little lion.Liang hook up the lip, make her hand change to hug in her waist, pull out a touch of cold and charming smile: "Baby, I was wro
"Topic link": Click here~~Code:/** Problem:uva no.562* Running time:0ms* complier:c++* author:acm_herongwei* Create time:11:12 2015/9/9 Wed * ZeroOne Bags * Half of the total value of the coin as a backpack capacity, then zeronebags*/#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. UVA 562 Dividing coins (01 backpack base)
condition is used first, and if the number of remainder is +1,//The insufficient portion is made up of smaller denominationsT= ((price-sum[i-1])/a[i]) + (((price-sum[i-1])%a[i])?1:0); Ans+=T; Price-=t*A[i]; } } returnans+Price ;}intMain () {intt,price,i,j; inta[6]={0,1,5,Ten, -, -};//face value intnum[6];//QuantityCin>>T; while(t--) {cin>>Price ; intsum=0; for(i=1; i5; i++) {cin>>Num[i]; Sum+=num[i]*A[i]; } if(Sum"-1-1"Continue;} intMi=fewest (A,num,price); if(mi==-1) {cout"-1-
#include#includeUsingnamespace Std;int arr[100066];int main () {int n,m; scanf"%d%d", n,m);Forint i=0; I"%d", arr[i]); Sort (arr,arr+n);int l=0,r=n-1; //around pointer while (l//"caution" There can be no "=" here, equals words to go in l=r the same coordinate cannot be 2 numbers {int tmp=arr[l]+arr[r]; if (tmp==m) //the sum of the numbers pointing to the left and right pointers is equal to M, that is to find {printf ( "%d%d" arr[l],arr[r]); return 0;} else if (tmp//and less than m, left pointer
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