imvu coins

// Simple simulation # include # include using namespace STD; int main () { int day, coin, N; while (CIN> Day) { If (Day = 0) break; coin = 0; N = floor (SQRT (double) day * 2)-0.5); // The number of gold coins obtained per day for the

# Include # include # include # include # include # include # include # include # define INF 0x3f3f3f # define ll _ int64using namespace STD; int n, m, DP [100010], a [100010], C [1010]; void pack01 (INT cost, int W) {for (INT I = m; I >=

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1, we open Taobao mobile phone end, as shown in the following figure 2, then in the Taobao interface, we find "recharge", click it, as shown in the picture 3, such in the Taobao "Recharge Center" you will see there are phone calls,

1. Can buy directly 2. Can be obtained by doing activities 3. Can be won at the quiz there 4.C is a 15-minute event, C currency can be exchanged for spinach, the host can open spinach, for example, sieve size, a single double, as a small wager

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Here is a price, and the number of banknotes with a nominal value of 100, (unit: Mao, if you want to generate the price with the minimum number of banknotes and the maximum number of banknotes, you can export the minimum and maximum quantity. The

Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 2844 There are A1, A2,..., An, and the corresponding numbers of the N denominations are C1, C2,..., CN. Ask how much money can be made up based on so much money If multiple backpacks

/* the O (log amount) time is given to process items in multiple backpacks. amount indicates the number of items: procedure multiplepack (cost, weight, amount) If cost * Amount> = V completepack (cost, weight) return integer k = 1 while K

This is my first thought of as a mother function, but it is said that when the mother function uses TLE, multiple backpacks are decisive. Here we use multiple backpacks, obviously we cannot directly output DP [N, in this case, the result is wrong.

Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 1398Similar to HDU 1284 hdu1028Code:# Include # include # include # include # include using namespace STD; int main () {int N, I, j; int DP [310]; memset (DP, 0, sizeof (DP); DP [0]

It is a small variant of the typical change problem. Both DP and primary functions can be used. # Include # include # include # include # include # include # include # include # include # include # include # include # include using

The question is to give you a few numbers, then give you the available numbers, and then randomly find a few numbers to accumulate,   Let me calculate the number that can be accumulated!   Solution: First initialize the backpack to-1, calculate it

Question: How many kinds of money can be formed with a certain amount of paper money and a nominal value without exceeding the total amount of money?Thought: I thought of multiple backpacks. I wrote it with multiple backpacks, tle. Later I used

[Cpp]Description: divide the coin into two portions, and you can find the smallest difference with the average.# Include # Include Bool s [50010];Int num [110];Int main (){Int n, t, sum, flag, p, m;// Freopen ("a.txt", "r", stdin );Scanf ("% d", & t

[Cpp]# Include # Include # Include Using namespace std; Const int maxn = 305;Int c1 [maxn], c2 [maxn];Int main (){Int n;Int I, j, k;While (scanf ("% d", & n )! = EOF & n){For (I = 0; I {C1 [I] = 1;C2 [I] = 0;}For (I = 2; I * I {For (j = 0; j For (k =

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