insertion sort pseudocode

One, what is the direct insertion sort: The first one compares the top two numbers, the second number is then inserted into an ordered table by size; The second one scans the third data with the first two digits, inserting the third number into an ordered table by size, and then, in turn, completes the entire sorting process after the (n-1) scan. In simple terms, the array to be sorted is divided into order

#pragma once#includeFrom for notes (Wiz)Insert Sort Insertion Sorting

#include Two-way insertion sort

As a sort algorithm, insertion sorting is stable. Time Complexity: O (N * n), space complexity: O (1 ). The best time complexity is O (n), and the worst and average is O (n * n ). Algorithm idea: given an unordered array, we start with its second number and assign it to the mark variable to compare the size of mark with the previous number, if the number is smaller than the previous one, move the previous o

Actionscript3.0 insert sorting implementation /** * ● The basic idea of insertion sort is to insert a record to be sorted each time. * Insert the record to the appropriate position in the subfile that has been sorted according to the keyword size, * Until all records are inserted. * */ Public Static Function insertionsort (Source: array): Array {var Len: Int = Source. length; For (Var I

"How many inverted pairs"-so usually ends up with mergesort solution (of course there is other solutions out there)defmergesort (arr):ifLen (arr) = = 1: return0, arr mid= Len (arr)//2Cnt1, arr1=mergesort (Arr[:mid]) Cnt2, arr2=mergesort (arr[mid:])#RET =[] CNT=0 I=0 J=0 Inx=0 whileI andJ Len (arr2):ifArr1[i] Arr2[j]: Ret.append (arr1[i]) I+ = 1elifARR2[J] Arr1[i]: Ret.append (arr2[j]) CNT+ = Len (arr1)-I#arr2-arr1J + = 1 whileI Len (arr1): Ret.append (Arr1[i]) I+ = 1 whileJ Len (arr2): R

/*** Definition for singly-linked list. * public class ListNode {* int val; * ListNode Next; * ListNode (int X) {val = x;}}*/ Public classSolution { PublicListNode insertionsortlist (ListNode head) {if(head==NULL) return NULL; ListNode Next=Head; ListNode Newhead=NULL; while(next!=NULL) {ListNode temp=Next; Next=Next.next; Temp.next=NULL; //start inserting if(newhead==NULL) {Newhead=temp; } Else{ListNode I=Newhead; ListNode Tail=NULL; while(i!=NULL)

/** * Definition for singly-linked list. * struct ListNode {* int val; * ListNode *next; * listnode (int x): Val (x), Next (NULL) {} *}; */class Soluti On {public: listnode* insertionsortlist (listnode* head) { if (head==null) return NULL; listnode* P=head; listnode* start=p->next; while (start) { listnode* q=p; while (Q!=start q->val Leetcode (4): Insertion Sort

#include using namespacestd;intFindIndex (Char* V,CharKeyintindex) { intM,left,right; Left=0; Right=index; while(1) {m= (right-left)/2; if(KeyLeft )) { returnLeft ; } Else if(Key>* (v+Right )) { returnRight ; } Else { if(m==0) { returnleft+1; } if(Key==* (v+left+m)) {returnleft+m; } Else if(Key > * (v+left+m)) { left=left+m; } Else{ Right=left+m; } } } return-1;}intShortInsertTest2 (intCChar*v

1 /**2 * Definition for singly-linked list.3 * struct ListNode {4 * int val;5 * ListNode *next;6 * ListNode (int x): Val (x), Next (NULL) {}7 * };8 */9 classSolution {Ten Public: OneListNode *insertionsortlist (ListNode *head) { AListNode *list =head; - - if(List = = NULL | | list->next = =NULL) the { - returnlist; - } - +ListNode *P1 =list; -ListNode *P2 = p1->Next; +ListNode *P3 = p2->Next; A at if(P1->val > p2->val) - { -Swap (P1->val, p2->val); - } - -

//C Implementation1#include"stdafx.h"2#include"stdlib.h"3 4 int_tmain (intARGC, _tchar*argv[])5 {6 intarr[6] ={0,5,3,4,6,2};7 inti,j;8 for(i=1;i6;++i)9 {Ten if(arr[i]1]) One { Aarr[0] =Arr[i]; - for(J =i-1; arr[j]>arr[0];j--) - { thearr[j+1] =Arr[j]; - } -arr[j+1] = arr[0]; - } + } - for(inti =0;i6;++i) + { Aprintf"%d\t", Arr[i]); at } -System"Pause"); - return 0; -}"Big Talk data S

#include The establishment, insertion, deletion, lookup of binary sort tree and the complete implementation version of C + + 4 traversal methods

introduction of direct insertion sort Each time the first element is removed from the unordered table, it is inserted into the proper position of the ordered table, so that the ordered table is still orderly. The first one compares the top two numbers, the second number is then inserted into an ordered table by size; The second one scans the third data with the first two digits, inserting the third number i