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In Linux, tcpdump is saved and the result is pcap file wireshark analysis.

The command parameter for saving tcpdump packets to a file is-wxxx. cap capture eth1 package tcpdump-ieth1-w/tmp/xxx. cap catch 192.168.1.123 package tcpdump-ieth1host192.168.1.123-w/tmp/xxx. cap catch 192.168.1.123 port 80 package tcpdump-ieth1ho TcpdumpThe command parameter for saving a packet to a file is-w xxx. cap

bzoj1834: Maximum flow + minimum cost maximum flow

Why yesterday looked at the time has been not understand, sure enough IQ is flawed ... And then I see it tonight. Orzorz, the key is to limit the capacity of that skill ... --------------------------------------------------------------------------------------------#include #include #include #include #include using namespace Std;#define REP (i,n) for (int i=1;i#define CLR (x,c) memset (x,c,sizeof (x))const int inf=0x3f3f3f3f;int read () {int X=0;char C=getchar ();while (!isdigit (c)) C=getchar ()

MINA framework ---------- android client and server, androidmina framework

. Server display: 10:01:43 org. apache. mina. filter. logging. LogLevel $4 logInformation: CREATED/127.0.0.1: 61982[QC] INFO [NioProcessor-1] TimeServerHandler. sessionCreated (17) | sessionCreated10:01:43 org. apache. mina. filter. logging. LogLevel $4 logInformation: OPENED[QC] INFO [NioProcessor-1] TimeServerHandler. sessionOpened (68) | Server-to-client connection opens10:01:43 org. apache. mina. filter. logging. LogLevel $4 logInformation: Written ed: HeapBuffer [pos = 0 lim = 6

POJ-3281 Dining (isap ek Dinic)

POJ-3281 Dining (isap ek Dinic) There are nheaded cattle, F kinds of food, D kinds of drinks, each type of food and drink only oneNow, I will show you the foods and drinks that each ox loves. I will ask you how many cows can get their favorite foods and drinks at most. Solution: Split the ox into two points. The weight is 1. One item is connected to the favorite food, the weight is 1, and the other is connected to the favorite drink. The weight is 1.Connect all the food to the super source. The

July 2013 latest GoDaddy host related discount code recommended

GoDaddy any scheme of host 35 percent discount, the lowest price of the whole network Http://www.godaddy.com/hosting/dedicated-servers.aspx?isc=iapvpssite Economy Program host one year, only 12 U.S. dollars, or 73 yuan Http://www.godaddy.com/hosting/web-hosting.aspx?isc=iap1hfd Purchase any scheme VPS host 70 percent discount, low to $16.8/month; Send SSL and 3 independent IP Http://www.godaddy.com/hos

The use of vector geometry in game Programming 2

two modulo equality vector C is collinear with C ' . Let's finish it: ( B ' . A1 ) =-( b.a1 ) = ( B '. A1 ) = ( b.a1 ), good, substituting C = ( b . A1 ) * A1 , get C= -(B '. A1)*A1= (B '. A1)*A1=-C = "c = (b. A1)*A1 = (-B '. A1)*A1C ' = (b '. A1)*A1 = (-B. A1)*A1So far, we have come to the conclusion that when a vectorbwith another vectoraThe angle between (0, PI/2) (3*PI/2, 2*PI), it is inaThe projection vector in the directionCIt isC

Ubuntu-16.04 Building DHCP Service

Ubuntu-16.04 Building DHCP service One, what is DHCPDHCP (Dynamic Host Configuration Protocol) is commonly used in large local network environment, the main role is centralized management, assigning IP address, so that the host in the network environment to obtain the dynamic IP address, gateway address , DNS server address and other information, and can increase the usage of the address.Second, install the DHCP service softwareInstall Isc-dhcp-server

ubuntu14.04 Deployment Kickstart

Tags: eth0 default tftp res boot apache2/etc/otl swaTransferred from: http://www.mamicode.com/info-detail-1646465.htmlThe kickstart is used for the automatic installation system of the inner network.Installing a system using PXE requires the installation of services such as Dhcp,tftp,http (and, of course, other file sharing methods such as NFS,FTP).Lab Environment:1. VMware 122. Network segment 10.0.0/8, PXE server ip:10.0.0.100First, install DHCP serviceYou can choose to install

Some basic concepts of Vector Plotting

[Reproduced in] http://www.jiscdigitalmedia.ac.uk/stillimages/advice/vector-graphics-illustrated-glossary/ Summary An alphabetical list of commonly-used terms in vector graphics. EachTerm is defined and accompanied by one or more than strations. There are applying applications capable of producing vector graphics And most of them share the same terminology for the elements that makeUp a vector object. Some use slightly different terms-we have listedThe most common terms, together with variation

POJ3184 Ikki ' s Story i-road reconstruction (Max Stream)

Once the maximum flow is calculated, the capacity of all the edges of the full stream is +1, and then the augmented path is found.1#include 2#include 3#include 4#include 5 using namespacestd;6 #defineINF (17 #defineMAXN 5558 #defineMAXM 111119 Ten structedge{ One intV,cap,flow,next; A }EDGE[MAXM]; - intVs,vt,ne,nv; - intHEAD[MAXN]; the - voidAddedge (intUintVintcap) { -Edge[ne].v=v; Edge[ne].cap=

DP10 0-1 backpack Problem 0-1 Knapsack Problem @ geeksforgeeks

than W. from all such subsets, pick the maximum value subset. 1) Optimal Substructure:To consider all subsets of items, there can be two cases for every item: (1) the item is encoded in the optimal subset, (2) not supported ded in the optimal set.Therefore, the maximum value that can be obtained from n items is max of following two values.1) Maximum value obtained by n-1 items and W weight (excluding nth item ).2) Value of nth item plus maximum value obtained by n-1 items and W minus weight of

POJ 2396 Budget upstream and downstream network streams

found that the edge was added in order, and I instantly felt that the world was beautiful.In my template, the cap stored in the edge indicates how much traffic is available on the edge, and flow indicates the traffic that is used now.[Cpp]# Include # Include # Include # Include # Include # Include # Include # Include # Include # Define maxn555# Define MAXM 555555# Define INF 1000000007Using namespace std;Struct node{Int ver; // vertexInt

C # using recursive algorithm to solve classic knapsack problem _c# tutorial

, then cap>=2 can accommodate item1, this time the value of the backpack inside the item1. Value=1, get the following array 0 1 2 3 4 5 6 7 8 9 10 11 12 0 0 1 1 1 1 1 1 1 1 1 1 1 Next deal with items 1 and a subset of 2, item2 size of 3, then only cap=3 to accommodate the ite

Go language trivia append () function

The built-in append () function appends an item to slice. If the slice also has free capacity (Cap (s) > len (s)), it is appended directly. Otherwise, the slice is expanded before being appended. These are detailed in the documentation for the Append () function, but the document does not say how the expansion is done, so the following is an experiment with a piece of code: Package Main func main () { s: = []int{}; println (

POJ-2516-Minimum Cost

POJ-2516-Minimum Cost N Customers, M suppliers, K types of goods, provide some supply and demand relationships, and find the minimum price when the conditions are met The minimum cost and the maximum flow. You can calculate the minimum cost for each of the k types of goods at a time and add them together. [Cpp]# Include # Include # Include # Define maxn300# Define INF 0x7fffffffInt min (int x, int y){Return x }Int map [maxn] [maxn], vis [maxn], cap [

Full tutorial aircrack-ng crack WEP, WPA-PSK encryption weapon

save, it will Generate a file named Longas-02.ivs, be sure to pay attention oh, do not find it and blame me not to write clearly:)Ah, it is estimated that some friends see here, and will ask at the time of the crack can be used together with these captured packets, of course, as long as you load the file using Longas*.cap, where the asterisk refers to all the prefixes consistent files. After the carriage return, you can see the interface a

Network Flow Example Learning

Before it seems that the network flow of the construction of the problem is relatively few ah ... Now let's do a little. The first is the template. poj1273 Grassland Drainage #include #include#include#include#includestring.h>#include#include#includeSet>#includeusing namespacestd;#defineSZ 233333intn,m=1; typedefLong Longll;intFst[sz],nxt[sz],vb[sz]; ll Cap[sz];voidAD_DL (intAintb,ll c) { ++m; Nxt[m]=fst[a]; Fst[a]=m; Vb[m]=b;

Codeforces 653D Delivery Bears (maximum flow)

The topic probably said that there is a simple graph of n-point M-side, each side can only allow a certain amount of goods through. To allow the X-Bear to deliver goods from 1 to n, each bear is transported and transported in the same weight, asking for the maximum value of the weight.The two-part weight judgment is established.If the weight is known, then how many bears can be found on each side, that is, the capacity of the side divided by the weight. And judging whether the X-Bear can go to 1

Architect Express 8.3-rules that architects must understand

As an architect, some rules have to be mastered, which is the axiom of the software, if you learn physics do not know Newton's law, then do not learn. There are similar things in the software industry, I call it the software law. For example:Acid,cap,baseACIDIn a traditional database system, transactions have acid 4 properties(1) atomicity (atomicity): A transaction is an atomic manipulation unit whose modifications to the data are either all executed

POJ 3189 Steady Cow Assignment (largest stream in the network flow + binary diagram)

POJ 3189 Steady Cow Assignment (largest stream in the network flow + binary diagram) Address: POJ 3189 I'm dizzy... What is the use of quickly completing Daytime tasks... The saved time was wasted by my hands... After another whole day of adjustment, the problem was actually the inverse of n and m in one place !!! Reflection .. Reflection... Face to face... This is the binary interval, and then the enumerated range position. Create a graph. Not to mention .. The Code is as follows: #include

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