jar file

1. Defining File Enumeration Classes/*** file Type Enumeration classes **/publicenumFileType{/** *jepg.*/jpeg ("FFD8FF"), /** *png.*/png ("89504E47"), /** *gif.*/gif ("47494638"), /** *TIFF.*/ tiff ("49492a00"),/** *tif.Nbsp;*/tif ("49492a00"), /***Windows Bitmap.*/bmp ("424D"), /** *RichTextFormat.*/ rtf ("7b5c727466"), /***XML. */xml ("3c3f786d6c"), /***HTML. */nbSp;html ("68746d6c3e"), /** *AdobeAcrobat.

");;String [] files = AF. List ();If (files. Length = 0) system. Out. println ("nulllength ");;For (INT I = 0; I If (files [I]! = NULL) system. Out. println (files [I]);Else system. Out. println ("null ");}}Catch (exception e ){System. Out. println ("hugeerror ");}}} // ================================================ ====================================== Running result: A. bat B .png That's right. [NO2] type 2 We recommend that you use the (2) method below, because (1) problems that may not b

We often use compression software such as WinZip to compress files for easy transmission. In Java also provides a file compression to reduce the amount of data transmission of the class, you can easily compress the file into a zip, JAR, gzip, and other forms, gzip mainly in the Linux system under the compressed file.

: = $ (common_android_package_suffix)Include $ (build_prebuilt) (9) Add a static Java LibraryLocal_path: = $ (call my-DIR)Include $ (clear_vars)# Build all java files in the Java subdirectoryLocal_src_files: = $ (call all-subdir-Java-files)# Any libraries that this library depends onLocal_java_libraries: = Android. Test. Runner# The Name Of The JAR file to createLocal_module: = sample# Build a static

size info, e.g. from their layoutif (packframe) {Frame.pack ();}else {Frame.validate ();}Center the windowDimension screensize = Toolkit.getdefaulttoolkit (). Getscreensize ();Dimension framesize = Frame.getsize ();if (Framesize.height > Screensize.height) {Framesize.height = Screensize.height;}if (Framesize.width > Screensize.width) {Framesize.width = Screensize.width;}Frame.setlocation ((screensize.width-framesize.width)/2, (Screensize.height-framesize.height)/2);Frame.setvisible (TRUE);} Mai

Import resource file in spring, there are two cases: Classes directory and JAR packageIf the resource file is in the classes directory:Note:1, the directory of files such as: Classes/bean/test.xmlIf the resource file is in the jar package:1, pay attention to add * number aft

It took N minutes to finally create an executable JAR file. I am afraid to share it with you.If you want to download this file, go to http://yourhome.arkoo.com/lilao/a.rar. As a beginner, I prefer the following mistakes:1) Not all java can be packaged into a jar package, as if there is no frame (not sure)Because the r

Preconditions: Run Java programs using Java-jar Xxx.jar, where some of the code needs to read the configuration files in the jarProblem Description:Discovery could not read to the configuration fileSolution Ideas:1. The configuration file is not hit in the jar package2. The configuration file is corrupted and cannot be

Sometimes you need to package a properties file inside a library that contains some configuration information and cannot be deployed externally.In the MAVEN project, place the properties file under the Src/main/resources directory. will be automatically packaged into the classes directory.Then in the jar package code to read this

Select the default program:. jar file Right-click, open-> Select default program-> Browse, select JRE under Bin file Javaw.exe. Edit registry: Hkey_classes_rootapplicationsjavaw.exeshellopencommand, modify the data value to [D:program filesjavajdk1.6.0_ 21jrebinjavaw.exe '-jar '%1 '] (in square brackets, add –

JDK used on my machine is free of installation. After selecting the XXX. jar file, the corresponding JAR file cannot be executed. Solution: 1. Go to "my computer" --> "Tools" --> "Folder Options" --> "file type" --> Find the JAR