java 8 compiler

Recently tried a few Java obfuscation (Java obfuscator), feel not a completely satisfactory, so I want to simply write one. After a few pages of Java Virtual Machine specifications, the whim of other obfuscation is compiled in the byte code on the fuss, can be directly compiled from the source code into a confusing class file? It took one weeks to write a

If we want to set a explicit encoding for the Java compiler in Gradle we can use the property options.encoding . For example we could add the following line to our Gradle build file to change the encoding for the compileJava task:View Sourceprint?0.apply plugin: ‘java‘1.2.compileJava.options.encoding = ‘UTF-8‘To set th

public int getInt(){ return 6; } } Public classMain {public static void main (String [] args) {MyInterface my = null; // obtain the instance my. getInt ();} of MyInterfaceImpl or MyInterfaceImpl1 Based on the factory or other methods ();}} In the above Code, during compilation, the compiler cannot determine the implementation class of the current "my" object. It can be determined only when the corresponding instance is cre

When importing a project from another place, you will often encounter Eclipse/myeclipse description Resource Path location Type Java compiler levels does not match the Vers Ion of the installed Java project facet. This problem occurs because the Eclipse/myeclipse JDK build version is inconsistent with the problematic JDK compilation version of the project!1, firs

Original address: Http://java.dzone.com/articles/gradle-goodness-set-javaIf we want to set a explicit encoding for the Java compiler in Gradle we can use the Options.encoding property. For example we could add the following line to our Gradle build file to change the encoding for the Compilejava task:Apply plugin: ' java '= ' UTF-

First, prefaceAs the Java compiler continues to evolve, it provides programmers with more and more "Honey" (Compiler Suger), which greatly facilitates the development of programs, such as the enhanced mode of foreach, automatic unboxing and boxing, and string connection operations ...These "honey" bring us a lot of convenience, but there are also some pitfalls.Se

The project developed in Eclipse has a JDK that can be configured in Java build path, and a Java compiler can be configured with compiler level, which is different, Java compiler The JDK version of level is the version you develop

Java compiler level does not match the V Examime.The Java compiler level does not match the project version.Solve:Right-click on the current project, in Properties Properties->myeclipse->project facets, configure the compiled version to match the version of Java

Basic knowledge:What is the anti-compilerAs we all know, the process of converting source code to binary execution code is called "compiling", such as compiling C source code into EXE executable file, then the process of binary code execution is called "anti-compilation", such as converting EXE to C source code is called "Anti-compilation".Since the mainstream C compiler has been optimized for code, it is very difficult to decompile the exe file gener

Span style= "font-size:15px" >1. When you create a new MAVEN project, the JDK uses 1.8, but the compile code hints fail ide to set a few places 1. Click Project Selection Project Structure 2. Setup Project SDK and project language level 3. Set the JDK version of the modules, select 8 4. Select setting, set Java compiler select jdk1.8

There is a problem today:When you create a new Web project with Maven in Eclipse and then update it with MAVEN, the JDK version automatically becomes 1.5.By finding the data, we finally found the following explanation in the documentation for the MAVEN compiler plugin (maven Compiler Plugin):The Compiler Plugin is used to compile the sources of your project. Sinc

The problem is as follows:Http://stackoverflow.com/questions/19889145/setting-up-intellij-12-idea-with-java-1-7-and-resolve-java-system-java-compile IntelliJ CE downloaded and installed Latest Java 1.7 downloaded and installed JDK is setup to make and run the project I faced the following strange

= = b)); result = TrueThe visible compiler optimizes the string + base type to be evaluated directly as a constant expression.Again, look at the string here is "* *" like this, we change the variable to try:String a = "AB";String BB = "B";String B = "a" + BB;System.out.println ((A = = b)); result = FalseThis good understanding, "a" + BB is a variable, can not be optimized. This is a good explanation of why the 3 view is incorrect, and if the string+s