java board game

#include #includeusing namespacestd;intMain () {//-1 No one wins 0:o win 1: X Winintsize;printf ("0 means "party a", 1 means "Party B" \ n");p rintf ("Please enter the size of the matrix \ n"); while(SCANF ("%d", size) = =1){intboard[ -][ -];intNum_of_o;intnum_of_x;intresult =-1;intI, J; for(i =0; i ) for(j =0; J ) {scanf ("%d", board[i][j]);}//Check Row for(i =0; I 1; i++) {Num_of_o= Num_of_x =0; for(j =0; J ){if(

Http://acm.hdu.edu.cn/showproblem.php? PID = 1281 Problem description James and gardon are playing a game: For an N * m board, put as many "cars" as possible in chess boxes ", this makes it easy for them not to attack each other, But gardon restricts that only some grids can be placed. xiaoxi easily solves this problem (see) note that the locations where vehicles cannot be placed do not affect the mutual at

(2-Point Matching of graph theory algorithms) hdu 1281 (board game) A: give an n * m board and put it on the board. The cars that are placed on the Board cannot attack each other (they can attack each other on the same line or column), and only some dots can hold the

Dear Csdn Users:According to the volume of access and user demand, the "game development" plate is upgraded from the original small board to the large plate, and the plate is adjusted to the "hardware/embedded development" under the big slab. Below is the game development plate navigation tree.Game developmentCocos2d-xUnity3dOther

Title Description Description The game on a board with a 10*10 lattice, the initial pieces in the upper left corner, the end point is the lower right corner, the chessboard of each lattice has a number 0 to 9, each time a pawn can move to the right or lower adjacent lattice, to find a number and the smallest and through the 0 to 9 of all the number of the legal path, Output its length. (The number passed in

independently, but for a game like the landlord, players are grouped, Ai robot and when the farmer's card strategy should be different.(2) Note cardAi Bots are able to respond to cards already played by individual players for future decision-making. At the same time, you should also provide an interface for server cheating. For example, Mahjong games, AI robots in the decision-making can secretly look at other players in the hands of the cards or to

Problem description James and gardon are playing a game: For an N * m board, place as many "cars" as possible in the grid as possible in chess ", this makes it easy for them not to attack each other, But gardon restricts that only some grids can be placed. xiaoxi easily solves this problem (see) note that the locations where vehicles cannot be placed do not affect the mutual attack of vehicles. So gardon wa

A day at home this weekend, thinking about and writing the core functions of the chess game map. The so-called core function of my understanding is to abstract on the specific game, engine-level things. Before the reference to other people's code, according to their own ideas and understanding to come. The following features have now been implemented 1. The creation of logical maps The logical map contai

(inti =1; I if(Book[i] = =0 P[u][i] = =1) {Book[i] =1;if(Match[i] = =0|| DFS (Match[i])) {Match[i] = u;return true; } } }return false;}intMain () {intCA =1; while(scanf("%d%d%d", n, m, k)! = EOF) {memset(P,0,sizeof(p));memset(Match,0,sizeof(match)); for(inti =0; I scanf("%d%d", a, b); it[i].x = A; It[i].y = b; P[A][B] =1; }intAns =0; for(inti =1; I memset(Book,0,sizeof(book));if(Dfs (i)) ans++; }intTMP =0; for(intj =0; J 0;intANS1 =0;memset(Match,0,sizeof(match));

Problem Solving Ideas:Enumerates all the squares on the board, and if the point is deleted, the maximum number of matches is reduced, then the point is the key point.#include HDU 1281 board game (two-part chart matching)

Online board game 6930 that can be played in linux ~~ -- Linux general technology-Linux technology and application information. For details, refer to the following section. I don't want to talk about it anymore. Http://www.6930.com In addition: the webmaster Income Plan is coming soon. 5 RMB will be sent if the number of recommenders playing in over 100 games! The website itself is also a model for w

#define _CRT_SECURE_NO_WARNINGS#includeUsing C language to realize "retarded" board game

#include This article is from the "vs LV" blog, so be sure to keep this source http://survive.blog.51cto.com/10728490/1705319"C-language" board game

PHP master please teach novice! PHP enables multiple users to interact with the same interface in a project board game

Analysis: The problem can be used to match the x-coordinate of the y-coordinate, the match is a successful one can put a piece of points, the last to find the best binary matching is the maximum number of pieces can be put. The maximum match of the binary graph is using the Hungarian algorithm. After the deletion of an edge to determine whether a point is a key point, if the deletion, the maximum number of matches is not the same, otherwise, by deleting each point to test, you can finally calcul

namespace STD;intT,n;intSSGG[M][M];structnode{intx, y;} Pt[n];intsgintXintY) {if(x==0|| y==0)return 0;if(x==y)returnssgg[x][y]=0;if(ssgg[x][y]!=-1)returnSsgg[x][y];BOOLv[10010];memset(V,0,sizeof(v)); for(intk=1;; k++) {if(x-k0y-k0) Break;if(x-k>0x-k!=y) V[SG (x-k,y)]=1;if(y-k>0y-k!=x) V[SG (x,y-k)]=1;if(x-k>0y-k>0) V[SG (x-k,y-k)]=1; } for(intI=0;; i++)if(!v[i])returnSsgg[x][y]=ssgg[y][x]=i;}intMain () {scanf("%d", t);memset(ssgg,-1,sizeof(SSGG)); while(t--) {scanf("%d", n);intflag=0; for(intI=

2013-03-03 This is a major task of studying the "real-time embedded System experiment" course last semester. It is to use the resources of the wild fire board and add an AHRS (Attitude and Heading Reference System) module, use gravity sensing to control the ball moving forward in the maze. Gravity sensor module.At first, I bought a firefire extension module, MMA7455 three-axis acceleration sensor, 36 RMB, and I2C bus. The I2C1 (STM32F103VET6 has two

Analysis: First to find out the maximum number of matches, and then with a matching point of a single removal to see if the maximum match, can be the key point (very violent AH), but unexpectedly just 31ms************************************************* #include #include string.h>#include usingnamespaceStdConstintMAXN = the;BOOLG[MAXN][MAXN], USED[MAXN];BOOLFind (intIintNintP[]){ for(intj=1;j{if(G[i][j] used[j] = =false){USED[J] =true;if(!p[j] | | Find (P[j], N, p)){P[J] = i;returntrue;}}}retu

- if(map[u][v]!Used[v]) the { -used[v]=true; - if(linker[v]==-1||DFS (Linker[v])) -{//find an augmented path, reverse +linker[v]=u; - return true; + } A } at return false;//don't forget it, always forget it. - } - intHungary () - { - intres=0; - intu; inmemset (linker,-1,sizeof(linker)); - for(u=1; u) to { +memset (Used,0,sizeof(used)); - if(Dfs (U)) res++; the } * returnRes; $ }Panax Notogi

The main topic: slightlyTopic ideas: First find a maximum match, and then enumerate each edge. (Just beginning to feel good violence ...) But the truth is that it only used 31ms.#include #includestring.h>#include#includeusing namespacestd;#defineMAXN 1500BOOLG[MAXN][MAXN], VIS[MAXN];intP[MAXN];intN, m, cas =1;BOOLFind (intu) { for(intI=1; i) { if(G[u][i] !Vis[i]) {Vis[i]=true; if(P[i] = =-1||Find (P[i])) {P[i]=u; return true; } } } return false;}intGetans () {memset (P