java data structures video tutorials

The enumeration (enumeration) interface, although not part of the data structure itself, is widely used in other data structure categories. The enumeration (the enumeration) interface defines a way to retrieve contiguous elements from a data structure.For example, an enumeration defines a method called Nextelement, which is used to get the next element of a

Java data structures and algorithms (iii) -- simple sorting Data alone is not enough. Data presentation often needs to be arranged in a certain order. The higher the requirement, the more complicated the sorting. This article only introduces three simple sorting types. 1) B

of the algorithm, such as the operating system is also a program, if you like, your computer can be open, keep the operating system running.4, the relationship between the program, algorithm, software:Program: The computer implementation of the algorithm. Implemented in a programming language.Algorithm: Represents the solution of the problem.Software: Programs + documentationProgram Design = data structure + algorithmThird, the

; 1){ - if(Peoples[index]) { incount++; - if(Count = = 3){ toPeoples[index] =false; +Count=0; -leftcount--;//minus 1 for the rest of the population. the } * } $ Panax Notoginseng //put the element under the label -index++; the + //If you have counted to the end of the array, start the number A if(Index > Len-1){ theindex = 0; + } - } $ $ for(i

List operation code is small but more error-prone, is more suitable for the interview place. Code implementation /** * Source Name: Mylinklist.java * Date: 2014-09-05 * program function: Java list operation * Copyright: [emailprotected] * A2bgeek */import Java.util.Sta Ck;public class Mylinklist {class Linknode"Data structures and Algorithms"

; J ) {System.out.print (A[j]+ " "); } System.out.println (""); } //Bubble Sort Public voidBubblesort () {intOut , in; for(out = nElems-1, out > 1; out--) { for(in = 0; in ) { if(A[in] > a[in + 1]) {swap (in,+ 1); } } } } //Insert Sort Public voidInsertionsort () {intin, out; //Out are dividing line for(out = 1; out ) { //Remove marked item Longtemp =A[out]; //start shifts at outin =Out ; wh

) { +Temp[i] =key; -}Else { theTemp[i] = This. table[i-1];Bayi } the } the - This. Table =temp; - } the the Public intSearchindex (intkey) { the intn = key/m-1; the intStart =-1; - intLength =-1; the //Find index location the for(inti = 0; I This. Indextable.size (); i++) { the if(n = = This. Indextable.get (i). Index) {94Start = This. Indextable.get (i). Start; theLength = This. Indextable.get (i). len

List interface, repeatable, ordered. List has ArrayList, because is the array structure, is suitable for the data query, LinkedList, because is the chain list structure, is suitable for uses in the deletion operation. If the array of additions and deletions, need to follow the elements are moving forward or backward, if the first element to make additions and deletions, the following elements move is very large, inefficient. Linked list If you do a qu

(6321/101)-Ten * (int (6321/102)) = 632-630 = 2;K3 = Int (6321/102)-Ten * (int (6321/103)) = 63-60 = 3;K4 = Int (6321/103)-Ten * (int (6321/104)) = 6-0 = 6;A: Example: Radixsort.javaQ: What is the efficiency of cardinality sequencing?A: All you have to do is copy the original data items from the array to the list and copy them back. If there are 10 data items, there are 20 copies. The number of copies is p

This article is about the search for ordered tables, which mainly includes the optimization usage of sequential lookups, binary lookups, interpolation lookups, Fibonacci lookups;Sequential Optimization Search : The efficiency is very low, but the algorithm is simple, suitable for small data search;Binary lookup : Also known as a binary lookup, it is searched from the middle of the lookup table. Finding results requires only half of the

Stacks and queuesStack (last in, first out)Stack, which allows access to only one data item: The last inserted data item.Stacks can be used to check the matching problems of parentheses and parse mathematical expressions, similar to those used in the compilation principle.The operation of the picture is actually summed up: 1. Read the left delimiter into the stack, 2. The right delimiter is read to match th

) + (N-2) +...+1 = N (N-1)/2When the value of N is very large, the algorithm compares the number of N2/2 times, ignoring minus 1.Assuming that the data is random, it is possible to swap locations each time, possibly without swapping, assuming a probability of 50%, then the number of interchanges is N2/4. However, if the worst-case scenario is that the initial data is reversed, the position is swapped for ea

Hash tables are also known as hash lists, and there are direct translations of hash tables, which are data structures that are accessed directly from the keyword value (key-value). It is based on an array, by mapping the keyword to an array of subscript to speed up the search speed, but also arrays, lists, trees and other data

} the } + } - classdolinkedlist{ $ PrivateLinkedlistLinkedList; $ Publicdolinkedlist () { - This. LinkedList =NewLinkedlist(); - } the Public voidAddele (String str) { - Wuyi Linkedlist.add (str); the } - PublicString Getele () { Wu returnLinkedlist.removefirst (); - } About Public Booleanisemp () { $ returnlinkedlist.isempty (); - - } -}A simple small program, the package is not very good, written in

Chapter 6 of Robert lafore, Java data structures and algorithms /* 6.1 assume that you have bought a cheap handheld computer, but find that its built-in chip cannot be used for multiplication and can only be used for addition. To get rid of this dilemma, you need to write your own program, write a recursive method mult (), and its parameter number is X and the re

---------------------");d L.myadd (" Hello.. 1 ");d L.myadd (" Hello.. 2 ");d L.myadd (" Hello.. 3 ");d L.myadd ("Hello.. 4 "), SOP (" queue out Order "),//sop (DL), while (!dl.isempty ()) {SOP (Dl.myget ());} SOP ("---------------------End-------------------");} public static void Duizhan () {Duizhan dz=new Duizhan (); SOP ("-------------------stack---------------------");d Z.myadd (" Hello.. 1 ");d Z.myadd (" Hello.. 2 ");d Z.myadd (" Hello.. 3 ");d Z.myadd (" Hello.. 4 "), SOP (" Stack Out Or

(e e);//replace element in collection * "9" void Add (e e);//At the previous position of the current index or the current Adds a new element to the collection at the back of the index position. *//whether or not to add new elements before or after the current index position depends on whether you are traversing sequentially or in reverse order * If it is {@link#next}, insert at the previous position of the current position *//if it is {@link#previous} to inser

1. Bubble Sort: Time complexity is O (n2)The hypothesis is a small to large sort: a comparison between two adjacent numbers, and a larger number at the back. The largest number in the last row after a comparisonsuch as: 40, 8, 15, 18, 121 times after the order is: 8, 15, 18, 12, 40 in turn until from small to big pat good for (int i = 0;i ) { for (int j = 0;j n-1-i;j++) {//The last few are already lined up There is no need to sort the if(A[j] > a[j+1]) { k= a[j] ; = A

Stack top element public class stackelementTool Stack class:public class seqstackOperation Result:Shortcomings, please correct me.Implementation of the stack of data Structures (JAVA) (i)

]; while (end>start) { while (end>startarrys[key)//If there is nothing smaller than the key value, compare next until there is a smaller swap position than the key value, And then compare it back to the past End--; if (arrys[end]) { arrys[end]; arrys[arrys[start]; arrys[tmp; } while (end>startarrys[start]) Start+ +; if (arrys[key) {