java list remove duplicates

Topic:Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Links: http://leetcode.com/problems/remove-duplicates-from-sorted-list/A brush, when considering whe

the head of the new linked list while(P!=null) {listnode* Pnext = p->next;intCount =1; while(Pnext!=nullpnext->val==p->val) {///whether subsequent nodes and P are duplicatedcount++; Pnext = pnext->next; }if(count==1){//equals 1 means no duplicates if(Ishead) {Newhead = P;newtail = Newhead;newtail->next=null;ishead =false;}//Head node requires special handling.

https://leetcode.com/problems/remove-duplicates-from-sorted-list-ii/Topic:Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 .Ideas:Requires two pointers,

Remove duplicates from Sorted List IIGiven a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given1->2->3->3->4->4->5, return1->2->5.Given1->1->1->2->3, return2->3.Problem Solving Ideas:The test instructions of this problem is to delete a

Given a sorted Linked List, delete all nodes that have duplicate numbers, leaving onlyDistinctNumbers from the original list. Example 1: Input: 1->2->3->3->4->4->5Output: 1->2->5 Example 2: Input: 1->1->1->2->3Output: 2->3 AC code: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), nex

TopicGiven a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 .AnswerIt's a bit similar to the remove duplicates from Sorted List , except that all occurrences o

[LeetCode] Remove Duplicates from Sorted List, leetcodeduplicatesQuestion: Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given1->1->2, Return1->2.Given1->1->2->3->3, Return1->2->3.Ideas: Delete duplicate items in the

Topic link The original title of https://leetcode.com/problems/remove-duplicates-from-sorted-list/ Given a sorted linked list, delete all duplicates such which each element is appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. Titl

Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Analysis: Similar to remove duplicated from Sorted array. Run Time 19ms1 /**2 * Definition for singly-linked list.3 * struct ListNode {4 * int val;5 *

https://leetcode.com/problems/remove-duplicates-from-sorted-list/1 /**2 * Definition for singly-linked list.3 * struct ListNode {4 * int val;5 * ListNode *next;6 * ListNode (int x): Val (x), Next (NULL) {}7 * };8 */9 classSolution {Ten Public: Onelistnode* Deleteduplicates (listnode*head) { AListNode * temp=NULL; -L

Title Description Link Address Solution Title DescriptionGiven a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the original List.ExampleGiven 1->2->3->3->4->4->5, return 1->2->5.Given 1->1->1->2->3, return 2->3.Link Addresshttp://www.lintcode.com/en/problem/remove-duplicates-from-sorted-

title :Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 . The following:This question is a classic double pointer problem, with two pointers one after the other pointing to the list. If the two pointers point to a value that is equal, then let th

Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Subscribe to see which companies asked this questionThis is a list without a head node, we just have to delete the duplicate (because the list is well-

Given a sorted Linked List, delete all duplicates such that each element appear onlyOnce. For example, Given 1-> 1-> 2, return 1-> 2. Given 1-> 1-> 2-> 3-> 3, return 1-> 2-> 3. Idea: The linked list is ordered. Each time you determine whether the current element is the same as the end element of the new linked list

.5) Otherwise retain the node. Point to the next node./***definitionforsingly-linkedlist.*structlistnode{ *intval;*structlistnode *next;*};*/structlistnode*deleteduplicates (StructListNode*head ) {if (head==null| | head->next==NULL) { returnhead;}struct listnode**list=head;intflag =0;while (*list) { if ( (*list)->next!=null (*

Given a sorted array, remove the duplicates in place such, all element appear only once and return the new L Ength.Do the allocate extra space for another array, and you must does this on place with constant memory.for example,given input Arraynums =[1,1,2] , your function should return length =2 , with the first and elements Ofnums Being1 and2 respectively. It doesn ' t matter what are you leave beyon

/** 82. Remove duplicates from Sorted List II * 2016-5-13 by Mingyang * First, if it is two equal, then go down to the unequal one * this time again judge, two cases * The next 1.pre is cur. So direct two is next * 2. Then ignore the cur, because cur must be the same as before.*/ PublicListNode deleteDuplicates1 (ListNode head) {if(head==NULL)return NULL;

Title: Given A sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Answer: Using three pointers, p identifies the linked list parts that have been processed, and q is used to refer to the node that is currently being compared, and R is used to iterate over

TopicGiven a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .AnswerMethod 1: Starting from the table head one by one comparison, encounter equal point to the next; Meet unequal, update the node to compare, start a new round of comparison, the code is as follows:/** * Definition for singly-linked

Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Solution: Removes duplicate nodes from the ordered list.Ideas:1) The input is the empty linked list;2) because it is well-ordered, repeating elements only appear in succession, so it is possible t