java list remove duplicates

Title:Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Tips:This problem is relatively straightforward and should be noted that redundant nodes should be removed.Code:/** Definition for singly-linked list. * struct ListNode {* int val; * ListNod

Title Description: (link)Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Problem Solving Ideas:1 /**2 * Definition for singly-linked list.3 * struct ListNode {4 * int val;5 * ListNode *next;6 * ListNode (int x): Val (x), Next (NULL) {}7 * };8

Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Ideas:More concise, traversing the linked list, encountering duplicate elements will delete the node. There is a note in the writing, the Link table node compares the node with the current node ra

Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Subscribe to see which companies asked this questionAnswerThis problem is too water, be careful not to dereference the null./** Definition for singly-linked list. * struct ListNode {* int val; * s

Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given1->1->2, return1->2.Given1->1->2->3->3, return1->2->3./** * Definition for singly-linked list. * struct ListNode {* int val; * ListNode *next; * listnode (int x): Val (x), Next (NULL) {} *}; */class Soluti On {public: listnode* deleteduplicate

Given a sorted Linked List, delete all duplicates such that each element appear onlyOnce. For example,Given1->1->2, Return1->2.Given1->1->2->3->3, Return1->2->3. Https://oj.leetcode.com/problems/remove-duplicates-from-sorted-list/ Idea: the Basic Linked

found that Prev is Fakenode node initially. Because the Fakenode node initially points to the head node.Runtime:8ms/** * Definition forsingly-linked list. * struct ListNode {*intVal * ListNode *Next; * ListNode (intx): Val (x),Next(NULL) {} * }; */classSolution { Public: listnode* deleteduplicates (listnode* head) {ListNode * fakenode=NewListNode (0); Fakenode->Next=head; ListNode *prev=fakenode; while(head!=NULL) {if(head->Nexthead->val==head->Ne

Remove duplicates from sorted list Given a sorted Linked List, delete all duplicates such that each element appear onlyOnce. For example,Given1->1->2, Return1->2.Given1->1->2->3->3, Return1->2->3. Algorithm ideas: For a single traversal, the drive is the same as the driv

Topic:Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Ideas: Packagelist; Public classRemoveduplicatesfromsortedlist { PublicListNode deleteduplicates (ListNode head) {ListNode P=Head; ListNode Start=Head; while(Head! =NULL Head.next! =NULL) {ListNode Headnext=Head.next; if(Head.next.val

Topic:Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given1->1->2, return1->2.Given1->1->2->3->3, return1->2->3.Idea: and array deletions are very similar#include Remove Duplicates from Sorted List--leetcode

Topic:Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Thinking and Analysis: direct traversalCode: Public StaticListNode deleteduplicates (ListNode head) {if(Head = =NULL){ return NULL; } intIntflag =Head.val; //ListNode listcurrent = head.next;ListNode listc

TopicGiven a sorted linked list, delete all duplicates such this each element appear only once.For example,Given1->1->2, return1->2.Given1->1->2->3->3, return1->2->3.Codepublic static ListNode Deleteduplicates (ListNode head) { if (Head==null | | head.next==null) return head; ListNode first = head; ListNode Second=head.next; while (second!=null) { if (first.val==secon

Description:Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Code:1listnode* Deleteduplicates (listnode*head) {2 if(head==NULL)3 returnNULL;4 5listnode* p =head;6listnode* pre =NULL;7 8Pre =p;9p = p->Next;Ten One while(P) A

Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given1->1->2, return1->2 . Given1->1->2->3->3 , Return1->2->3 . Simple topic, directly on the AC code:listnode* Deleteduplicates (listnode*head) { if(!head)returnNULL; ListNode*fir =Head; ListNode*sec = fir->Next; while(sec) {if(Fir->val = = sec->val) {sec= sec->Next; } Else{fir->next

Problem description: Given a sorted Linked List, delete all duplicates such that each element appear only once. for example, given 1-> 1-> 2 , return 1-> 2 . given 1-> 1-> 2-> 3-> 3 , return 1-> 2-> 3 . Train of Thought: For a traversal table, use two pointers to save the current position and the previous position of the current position. If the values of the two pointer nodes are equal, the c

LeetCode: Remove Duplicates from Sorted List, leetcodeduplicates Problem description: Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given1-> 1-> 2, Return1-> 2.Given1-> 1-> 2-> 3-> 3, Return1-> 2-> 3. Train of Th

do not know the size of the problem, it is very bad. It also caused me to waste a quick 2 hours =.= (listnode* res,*tmp;STD:: mapint,int>Ans ListNode *deleteduplicates (ListNode *head) {ListNode * I,*K,*AA;intJBOOLflag=true;if(head = = NULL | | head->next = = NULL)returnHead for(j=-65536;j65537; j + +) Ans.insert (STD::p airint,int> (J,0)); for(I=head;i!=null;i=i->next) {ans[i->val]++;//cout} for(I=head;i!=null;i=i->next) {if(ans[i->val]==1){int*a =New int; ListNode L (i->val);//cout

; * ListNode *next; * ListNode (int x): Val (x), Next (NULL) {} *}; */class Solution {public:listnode* deleteduplicates (listnode* head) {if (head==null) return NULL; if (Head->next==null) return head; listnode* P=head; listnode* Q=head; listnode* k=p->next; BOOL Flag=false; while (k) {if (p->val==k->val) {if (p==q) {p=q=k; Head=k; k=k->next; } else {listnode* tobedeleted=k; p->next=tobedeleted->next; k=p->next; Delete tobedeleted; Tobedeleted=nu

; inFlag2 =0; the } the About returnhead; the the } the};1 /**2 * Definition for singly-linked list.3 * struct ListNode {4 * int val;5 * ListNode *next;6 * ListNode (int x): Val (x), Next (NULL) {}7 * };8 */9 classSolution {Ten Public: Onelistnode* Deleteduplicates (listnode*head) { A if(head = = NULL | | head->next = =NULL) - { - returnhead; the } -ListNode *p = head->Next; - - if(

Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list. For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 . Problem Solving Ideas:Create a new auxiliary header, using two pointers pre,p;Start cycle judgment1. Pre->next=p->next, stating that there is the same element, then p=p->next; know t