java list remove duplicates

Given a sorted Linked List, delete all nodes that have duplicate numbers, leaving onlyDistinctNumbers from the original list. For example,Given1->2->3->3->4->4->5, Return1->2->5.Given1->1->1->2->3, Return2->3. Solution: remove duplicates from sorted list is similar. Howeve

Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 .Delete the duplicate numbers in the list, and note that this is the number that will be removed once the numbers have been duplicated. So how to completely

Given a sorted Linked List, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example,Given1->2->3->3->4->4->5, Return1->2->5.Given1->1->1->2->3, Return2->3.Original question link: https://oj.leetcode.com/problems/remove-duplicates-from-sorted-

Description:Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 .Code:1listnode* Deleteduplicates (listnode*head) {2 if(head)3 {4listnode* p =head;5listnode* Lastnode =head;6 7 intLastdeleteval =0;8 BOOLFlag =false;//flag is false to indic

Given a sorted Linked List, delete all nodes that have duplicate numbers, leaving onlyDistinctNumbers from the original list. For example,Given1->2->3->3->4->4->5, Return1->2->5.Given1->1->1->2->3, Return2->3. The question is to delete all repeated nodes, leaving only non-repeated nodes, and the nodes are sorted in order. Personal thoughts: 1. Traverse from the head of the linked

Given a sorted Linked List, delete all nodes that have duplicate numbers, leaving onlyDistinctNumbers from the original list. For example,Given1->2->3->3->4->4->5, Return1->2->5.Given1->1->1->2->3, Return2->3. 1 /** 2 * Definition for singly-linked list. 3 * public class ListNode { 4 * int val; 5 * ListNode next; 6 * ListNode(int x) { 7 *

Tags: des style blog Io color for SP Div on Given a sorted Linked List, delete all nodes that have duplicate numbers, leaving onlyDistinctNumbers from the original list. For example,Given1-> 2-> 3-> 3-> 4-> 4-> 5, Return1-> 2-> 5.Given1-> 1-> 1-> 2-> 3, Return2-> 3. 1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 *

Given a sorted Linked List, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example,Given1->2->3->3->4->4->5, Return1->2->5.Given1->1->1->2->3, Return2->3. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * };

This is a linked list of problems, in fact, about the list of problems are not any skill, is a bunch of pointers to refer to, and girlfriend this short time emotional instability, quiet heart to write, directly see the answer, because the feeling is not difficult, all is to see careful not careful/** * Definition for singly-linked list. * struct ListNode {* i

title :Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 .code : OJ online test via 288 ms1 #Definition for singly-linked list.2 #class ListNode:3 #def __init__ (self, x):4 #self.val = x5 #Self.next = None6 7 classSolution:8 #@param head, a

Because the list is used, there are several ways to remove duplicate data. Recorded in this ...Test data:listMethod One:hashsetSeveral ways to remove duplicates in the list collection-reproduced

/** Definition for singly-linked list. * struct ListNode {* int val; * ListNode *next; * ListNode (int x) : Val (x), Next (NULL) {}}; */classSolution { Public: ListNode* Deleteduplicates (listnode*head) { if(Head ==null)returnHead; if(Head->next ==null)returnHead; ListNode*res =Head; intHead_val; while(head) {Head_val= head->Val; if(Head->next head->next->val = =head_val) { while(Head Head->val = = head_val)//

82. Remove Duplicates from Sorted List II, duplicatessorted Given a sorted linked list, delete all nodes that have duplicate numbers, leaving onlyDistinctNumbers from the original list. For example,Given1->2->3->3->4->4->5, Return1->2->5.Given1->1->1->2->3, Return2->3. 1 /

Removes a repeating element from the linked list, given a sorted list.Ideas:Because they are already sorted, it is possible to determine whether or not the adjacent elements are equal if they are duplicated.1 traversal, using the new linked list TMP to save the non-repeating elements of the linked list head, return to the new linked list.Implementation code:publi

Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.ExampleGiven 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 ./*** Definition for ListNode * public class ListNode {* int val; * ListNode Next; * ListNode (int x) {* val = x; * next = NULL; * } * } */ Public classSolution {/** * @paramListNode Head is the head of the linked

Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 .Test instructionsGive a list and delete all duplicate nodes.Steps:(1) Define a new head node that points to the head and moves the head forward one bit.1, 1, 1, 2, 3To head, 1, 1, 1, 2, 3(2) Tr

[Leetcode daily question] 82. Remove Duplicates from Sorted List II, leetcodeduplicates Question: Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example,Given1->2->3->3->4->4->5, Return1->2

Given a sorted Linked List, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example, Given 1-> 2-> 3-> 3-> 4-> 5, return 1-> 2-> 5. Given 1-> 1-> 1-> 2-> 3, return 2-> 3. Idea: if the next element of the current element exists and the current element has the same value as the next element, use a loop to skip all the elements that are the same as the cu

Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 .Subscribe to see which companies asked this questionAnswer:/** Definition for singly-linked list. * struct ListNode {* int val; * struct ListNode *next; *};*/structlistnode* Deleteduplicates (s

Remove Duplicates from Sorted List II -- LeetCode, removeduplicatesQuestion: Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example,Given1->2->3->3->4->4->5, Return1->2->5.Given1->1->1->2->3