Title Description:
Enter a positive integer n to output the factorial of N.
Input:
Positive integer N (0
Output:
Input may include multiple sets of data, for each set of input data, the factorial of the output n
Sample input:
4515
Sample output:
Find the number of digits of a number factorialFlyfish 2015-8-15For example 7! =5040, the factorial result of 7 is 4 digits (10 binary)Ask for a number of digits1 Loop methodint get_digit_loop(int N) { int0; do { digit ++; while100); return digit;}2 recursive modeint get_digit_recursion(int N){ int0; 1011 + get_digit_recursion(N/10); return digit;}3 Library functions with the math header fileint get_digit_lib(int N){
Title Description:
Enter a positive integer n to output the factorial of N.
Input:
Positive integer N (0
Output:
Input may include multiple sets of data, for each set of input data, the factorial of the output n
Sample input:
4515
Sample output:
Factorial and time limit: Ms | Memory limit: 65535 KB Difficulty: 3
Describe
Give you a non-negative integer n to determine if n is a sum of the factorial of some number (these numbers are not allowed to be reused and are positive), such as 9=1! +2!+3!, if yes, output yes, otherwise output no;
Input
The first line has an integer 0Each set of
The title means: Ask N! How many zeros are there in the tail.Just started talking nonsense, in the last paragraph of the problem description to understand the topic to do.Ask N! The tail of the number of 0, first calculate n! , one more number, it is impossible, and N Max reaches 100000000. And we need to analyze from a mathematical point of view, how is 0 produced?By writing out the factorial of the previous few numbers, you know that to generate 0,
Math problems172. Factorial Trailing ZeroesGiven an integer n, return the number of trailing zeroes in N!.Note:your solution should is in logarithmic time complexity. (easy)Analysis: to find the number of the last 0 of the factorial of N, that is, to find the number of factors in the n! 5 (more than 2:5), the simple idea is to iterate over, for each number, divided by 5 to find the number of factor 5, but w
Ask for a factorial of 10000 or less n
Total time limit:
5000ms
Memory Limit:
655360kB
Describe
Ask for a factorial of 10000 or less n.
Input
Only one line of input, integer n (0
Output
A row, which is the value of n!.
Sample input
100
Two questions about factorialThis article describes two issues related to factorial operations in two. Remember that you cannot calculate the result of factorial because it overflows. Also do not convert to string to do, because it is more troublesome. In general, we can use mathematical methods to convert results to n-related, not n! of the results.1. Count n! There are several zeros at the endGiven an n,
Test instructionsHow many 0 are behind the factorial of n?The factorial of 6 = 1*2*3*4*5*6 = 720,720 is followed by a 0. InputA number n (1 OutPutNumber of outputs 0Ideas:A 0 can only be obtained by 2*5. Statistics n! the number of 2 and the number of 5, take less. That is, the number of 5 in n! is obtained. "Number theory: [n/5]+[n/5^2]+[n/5^3]+[n/5^4]+ ...]" {I can also draw this conclusion from my own an
From: http://www.cppblog.com/abilitytao/archive/2009/10/31/99907.html
How can I solve this problem? Don't worry. Let's discuss the following sub-problems:1. How can we find the number of occurrences of X (for example, 5) in the N factorial?For example, 15 factorial: 1*2*3*4*5*6*7*8*9*10*11*12*13*14*15Since the prime factor 5 only appears in the multiples of 5, I have extracted 5 from 5, 10, and 15, which i
Zoj2022 factorial
The first question of self a in the IDC room ~
Find the number of consecutive zeros on the tail of the given factorial;
Train of Thought: high requirements on efficiency, so there is no need to doubt that it is a reference to others' ideas. The most intolerable way of thinking: Calculate the factorial and then count ~ The maximum number is 10. H
Leetcode Note: Factorial Trailing Zeroes
I. Description
Given an integer n, return the number of trailing zeroes in n !.
Note: Your solution shocould be in logarithmic time complexity.
Ii. Question Analysis
The requirement of the question is to give an integern, Find outn!The end of the result is0. The brute force law is obtained first.n!And directly calculate the end0. (Repeated (n !) /10, until the remainder is not 0), if the inputnWhen the value is
/* 1. factorial 2. */# include "stdio. H "Void main () {// 1. test the factorial // long s (int n); // printf ("% lD", S (10); // 2. evaluate the void move (int n, char a, char B, char c) Test of the tower. Move (4, 'A', 'B', 'C ');} // 1. the factorial function long s (int n) {If (n = 1) return 1; elsereturn N * s (n-1);} // 2. the void move (int n, char a, char
Public Function factorial (intc as integer) as string
On Error goto myerr:
Dim INTA () as integer, intt () as integer, I as integer
Dim J as integer, Intr as integer
Redim INTA (20), intt (20)
If intc Intr = 20
INTA (0) = 1
For I = 2 to intc
For J = 0 to intr
Intt (j) = INTA (j) * I
Next J
J = 0
Do until j> intr
INTA (j) = intt (j) mod 10
If intt (j)> = 10 then intt (J + 1) = intt (J + 1) + intt (j)/10
J = J + 1
Loop
Next I
Do While true
J = J-1
If I
First, define two integer Arrays:Int FAC [1000]; // set to 1000 bits for the moment. I call it a "result array"Int add [1000]; // I call it a carry array"
The functions of the two arrays are described as follows:
1. FAC [1, 1000]For example, if the factorial of a number 5 is 120, I will use this array to store it:FAC [0] = 0FAC [1] = 2FAC [2] = 1Now I understand the role of the array FAC. With such an array, we can put the
n!=n* (n-1)!Import Java.io.bufferedreader;import java.io.inputstreamreader;/** * n factorial, i.e. n! (n (n-1) * (n-2) * ... 1). * 0! why = 1, due to 1!=1*0!. So 0!=1 * * @author Stone * @date 2015-1-6 pm 18:48:00 */public class Factorialrecursion {static long fact (long N) {if (n -----The program starts, enter the factorial value you want to calculate,-----111122223666424242451201201208403204032040320
Problem Description:Item 2-factorial of some numbers no, forget it.The n! function, when the user's input is negative, and the input number is too large (for example, greater than 12), use the exception handling mechanism to reject, and give appropriate hints.Code implementation:#include Operation Result:The 16th Week "C + + Language foundation" practice reference--some number of factorial not forget
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