javascript tetris

Rank of TetrisTime limit:1000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 5672 Accepted Submission (s): 1616Problem description Since Lele developed the rating system, his Tetris career is even more powerful, he soon all over the game to the world.To better match the preferences of those enthusiasts, lele a new idea: he will make a global Tetris Master rankings, reg

let Android into my life! The recent period of time relatively busy, tidy up their own 360 cloud disk, inadvertently found a classic Russian block before the source, take out to share a little, very classic, because before the HTML time has been a bit long, some grammar has been forgotten, it is not analyzed in this, public for reference, Can learn from, indeed write very good, block drawing, data processing, logical judgment, very clear, hope to bring you help!Very classic

Http://www.htmleaf.com/html5/html5youxi/201501201236.htmlHttps://github.com/Aerolab/blockrain.js/blob/gh-pages/src/blockrain.jquery.src.jsJS Write Tetris Game

# I nclude # I nclude # I nclude # I nclude # I nclude # Ifdef _ cplusplus# DEFINE _ cppargs...# Else# DEFINE _ cppargs# Endif# Define minboxsize 15/* minimum square size */# Define bgcolor 7/* Background coloring */# Define GX 200# Define Gy 10# Define sjnum 10000/* each time a player hits a 10 thousand-level score plus a level */ /* Key code */# Define vk_left 0x4b00# Define vk_right 0x4d00# Define vk_down 0x5000# Define vk_up 0x4800# Define vk_home 0x4700# Define vk_end 0x4f00# Define vk_sp

The official transfer to Tetris was developed yesterday. Previously, it was learning MFC and lasted about three weeks.It took a lot of time on the drawing. I used to think about dividing multiple views on the main window, moving the blocks, the next squares, and the scores. The button information is divided into various views, it took a day to study the split window and found that there was no need to do so. Finally, I chose to display all the content

60 lines of js Code to implement Tetris This is what I saw on the Internet before. It was written by a great god and has been worshipped. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

return; the } the if(L Modify (L, Mid, L, R, X, Y, v);98 if(Mid 1, R, L, R, X, Y, v); About } - 101 intQueryintLintRintLintRintXinty) {102 if(l returnMX---Query (1, M, x, y);103 intRES = tag---Query (1, M, x, y);104 if(L query (L, Mid, L, R, X, y)); the if(Mid 1, R, L, R, X, y));106 returnRes;107 }108 #undefMid109} *T; the 111 intMain () { the intx, y, dx, dy, h, Tot;113n = Read (), M = Read ()

Title Link: Hdu 5374 TetrisThe simulation, each time the operation is judged whether the operation is legitimate, the legitimate to execute, otherwise skipped. Each time a token is landed, determine if there is any elimination of the entire line.#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. HDU 5374 Tetris (analog)

Ideas:Several functions are written first. Rotation, four operations to determine if merge elimination is possibleThere are several details to consider in the question, such asWhen nature falls to the bottom, it is not judged by the merger, but when the natural fall is illegal.If you eliminate a row, the block above the line will drop only one line, and there is no direct drop to the bottom of the caseThe game test instructions not understand well, wrong these two places.There are some mistakes

; } } } returninf;}intGets_h (Point p[]) {intmx=0; for(intI=1; iMax (mx,dis[p[i].x][p[i].y]); returnMX;} Point Modify (point x,inty) { if(BND (X.X,X.Y))returnx; Point now=point (x.x+dx[y],x.y+Dy[y]); if((!map[now.x][now.y]) | | (!judge (NOW.X,NOW.Y)))returnx; Else returnNow ;}BOOLIDA (intDeep,point p[]) {Point NODE[MAXN*MAXN]; if(Gets_h (p) +deep>d)return false; if(Deep==d)return true; for(intI=1; i4; i++) {Ans[deep]=i; for(intj=1; jModify (P[j],i); if(IDA (deep+1, node))retur

Puzzle: Test instructions is very naked ~ ~ ~Training when said to write Mark permanent, anyway permanent is very water, directly wrote.But I don't know why I want to be permanent, or I can't understand it deeply, but I'm sure I can analyze it 233.Probably perhaps it is:Direct reason: The next pass mark cannot go down.Root cause:The segment tree has two layers, so that it can be passed a bit like a topologyIs that the outer segment tree needs to pass to the inner layer segment tree, and then the

; + intu=Q.front (); - Q.pop (); thern--;Bayi for(intI=0; I){ theindu[edge[u][i]]--; the if(indu[edge[u][i]]==0){ - Q.push (Edge[u][i]); - } the } the } the returnAllon; the } - the the voidsolve () { the while(~SCANF ("%d%d",n,m)) {94 init (); thern=N; the for(intI=0; i){ thescanf"%d%s%d",u[i],op[i],v[i]);98 if(op[i][0]=='='){ About if(Unite (U[i],v[i])) { -rn--;101 }102

");129 Elseprintf"ok\n"); the }131 the intMain () {133 //FRead ();134 intu, v;135 while(~rint (n) ~Rint (M)) {136Cls (inch); CLR (Head,-1); hcnt =0;137num =N;138Rep (i, n+5) Pre[i] =i;139 Rep (i, m) { $ Rint (Uu[i]); Rs (Cc[i]); Rint (Vv[i]);141 if(cc[i][0] =='=') {142 if(Unite (Uu[i], vv[i])) num--;143 }144 }145 Rep (i, m) {146 if(cc[i][0] !='=') {147U = Find (Uu[i]); v =find (Vv[i]);148 if(cc[i][0] =

Problem:Let the computer automatically go to The Tetris game. Solution:For the current building block, enumerate each shape after it is rotated from the board of each column, compare the board with the previous one, and score, finally, the shape with the highest score and the column are used as the current operation of the computer. (Since some readers do not use this program, it indicates that file redirection is required to run this program. [Cpp]#

returnfa[x]=Find (fa[x]); the } + - voidMerge (intXinty) $ { $ intFx=find (x), fy=Find (y); - if(fx!=FY) { -fa[fx]=fy; the } - }Wuyi the voidAddintUintv) - { Wuedge[tot].to=v; -edge[tot].next=Head[u]; Abouthead[u]=tot++; $ } - - voidTopper () - { Aqueueint>que; + while(!que.empty ()) Que.pop (); the for(intI=0; i){ - if(deg[i]==0fa[find (i)]==i) { $ Que.push (i); thecnt++; the } the } the while(!Que.empty ()) { - inttop=Que.front ();

Step by step teach you how to use Swift to develop Tetris: No.0, swiftno.0 It took a week to complete the Russian square game by following the Swift development tutorials, various materials, various google games, and a series of teaching blogs. Although the tutorials were not long enough, however, I still encountered many difficulties in the process of learning Swift from scratch. I don't know how many bugs came out, but I had to overcome them one by

, -1,1,-1,1, 0, 2, 1, 1, 1,1,0,2, 1, 1, 0, 2, 1,1,0,2, 1, 0, 1, 0, 0 , 2,-1,1, 0, 1, 1, 1, 1,1,-1,2, 0, 2, 0, 2, -1,2,-1,1, 0, 1, 1, 2, 1,2,-1,0, 0, 2, 0, 2, -1,0,-1,2, 0, 1, 1, 1, 1,1,0,2, 1, 2, 1, 2, 0, 2,-1,1, 0,1, ublic, and,};p string Getappletinfo () {return ("blocks-by Ali");} Initialize appletpublic void init () {Short i;screendata=new short[xblocks][yblocks];blocks=new color[maxcolors+1];// Set the background color blocks[0]=background;//set the block color Blocks[1]=new color (255,0,0)

The third topic is Tetris game. The game algorithm is relatively simple, the main kungfu in the interface experience, such as block graphics, user control, elimination and accumulation. We use GDI + graphic display, a total of 8 kinds of graphics, of course, can be customized according to their preferences. How do I represent graphics? We can draw on the mosaic effect. All graphics are represented by 3*3 matrices, 0 for background color, 1 for shaded

[parseint (x) + [] = fly.stopaxis[x];Fly.stopaxis[x]=[];}}}}For (var m in Fly.stopaxis) {//refactoring baselineif (Kzy.hasownproperty (m)) {FLY.STOPAXIS[M]=KZY[M];}}},};$ (function () {$ ("#start"). Bind ("click", Function () {if (fly.moving==0) {This.mode=[];Fly.creat (Fly.xyz[math.floor (Math.random () *7+1));Clearinterval (Fly.time);$ ("#fy"). Append (Fly.mode[0],fly.mode[1],fly.mode[2],fly.mode[3]);Fly.time=setinterval (function () {Fly.start (0,+20,false);},700);fly.moving=1;}})Fly.control

"title": An array int a[10] that requires a random value of 0 or 1 for each element, but these 10 elements cannot be 0 or all 1. "description": Tetris in the need to insert a number of random squares at the bottom of the row, to increase the difficulty of the game. Of course not a row is full of squares, so you can't drop it. Also can not have no box, that is less difficult. "Method 1" one by one random, unified judgment Randomly generated 10 elem