Objective
In the process of web data transfer, JSON is transmitted in the form of text, which is a lightweight type of string, while the client generally uses JS to manipulate the JSON object that is received, so the conversion between JSON object and
Json object and array and simple implementation method for converting to js object, jsonjs
JSON syntax rules
JSON syntax is a subset of the syntax of JavaScript Object Notation.
• Data in name/value pairs• Data is separated by com
: This article describes how to convert arrays and objects to json. For more information about PHP tutorials, see.
"; // Converts a one-dimensional array to json $ arr1 = array (" username "=>" zhangsan "," age "=>" 100 "); $ arr12Json = json_encode ($ arr1); print_r ($ arr1); echo""; Print_r ($ arr12Json); // Two-dimensional array conversion
A JSON object is a format that can be manipulated directly using jquery, and the object (class name) can be used to point out properties (methods), just as objects in JS do.The JSON string is just a string, a whole, without intercepting the data stored in it, can not be used
This article describes in detail how to use jquery and json to achieve paging effect. If you are interested, refer to Json as a lightweight data exchange format, due to the convenience of its data format, today I accidentally want to apply it to paging implementation. Paging is a long-term topic for web development, so the efficiency and importance of its applica
In the course of API testing, it is often encountered that the incoming parameters are complex types, and under Python, it is customary to use dictionaries to represent complex types. But C + + string processing is more mentally retarded, in general C + + will use vector to store complex types, then there is the problem of conversion, the following small section of code to convert the string into a vector of the process to
IE7, the window does not have the JSON attribute.Console. log (window. JSON);-> in IE6 ~ 7. The output result is undefined.
How can I convert a string in JSON format to an object in JSON format when it is incompatible? -> Use eva
The recent project needs to connect with the customer a WebService interface, the customer that JSON string over, belong to the more complex JSON string, here to share with you in my project used in the Analytic method:The method requires the following jar Packagecom.test;Importjava.util.ArrayList;ImportJava.util.HashMap;ImportJava.util.Iterator;Importjava.util.List;ImportJava.util.Map;ImportNet.sf.json.JSO
1, the DT sequence into JSON, put to the foreground of the hidden control "hidboundary":
Copy Code code as follows:
String json = Jsonconvert.serializeobject (dttemp);
This.hidBoundary.Value = JSON;
Need to reference Newtonsoft.Json.dll
2, from the foreground hidden space to get the data in DT
Copy Code code as follows:
var boundarydiv
Turn: Fastjson convert objects into JSON to avoid $refDisablecircularreferencedetect to prohibit circular reference detection:Json.tojsonstring (..., serializerfeature.disablecircularreferencedetect)When toJSONString is performed, the object is referenced by default if the object is reused.However, some cases do not ap
This article mainly introduces the conversion methods between jQuery objects and DOM objects, and analyzes the functions of jQuery objects and DOM objects and their mutual conversion skills in the form of examples, for more information about how to convert jQuery objects to DOM objects, see the examples in this article
, $dat);
$data 1[' id '] = 2;
$dat 1[' name '] = "swallow";
$da [' Blue ']= array_merge ($data 1, $dat 1);
Print_r ($DA);///printed out is a two-dimensional array (as follows)
/*Array([Red] => Array([ID] => 1[Name] => Mary)[Blue] => Array([ID] => 2[Name] => Swallow))*/
echo Json_encode ($DA);//output is a string converted to JSON format, which can be used directly in JS (as follows)/*{"Red": {"id": 1, "name": "Mary"}, "Blue": {"id": 2, "name
convert a Java class object to a JSON stringSystem.out.print (str);response.getwriter (). print (str); Returning data to the foreground Ajax}%>Two. Front-end Ajax does not receive JSON values what's going on?Front page:function Ajaxpost () {$.ajax ({data:{"Name": $ ("#name"). Val (),"Age": $ ("#age"). Val (),"Sex": $
1, the Eval method analysis, I am afraid this is the earliest analytic way. As follows:functionvar json = eval (' (' + str + ') 'return '2, new function form, more strange oh. As follows:functionvar json = (new function ("return" +return3. Use the global JSON object as follows:functionreturnAt present IE8 (S)/FIREFOX3.
We must have encountered similar problems during the development process. If we directly pass the array obtained by JS to the backend, the backend cannot differentiate the array, because if the JS array is two-dimensional, it is like this: 1, zhang San, Li Si, 26
So here we will sort out the solution. Hope to help you
First, convert the array to JSON format in Js.
JSCodeAs follows:
/***
We must have encountered similar problems during the development process. If we directly pass the array obtained by js to the backend, the backend cannot differentiate the array, because if the js array is two-dimensional, it is like this: 1, zhang San, Li Si, 26
So here we will sort out the solution. Hope to help you
First, convert the array to json format in js.
The js Code is as follows:
[Javascript]/***
JSON object and JSON string
Output:
Aaberg, Jesper, 555-0100,555-0120
Aaberg, Jesper, 555-0100,555-0120
**************************************** **************************************** ****
Example of receiving a JSON object on the front-end page:
With the system comes with the package: Org.json canThe list collection encapsulates the object, which is the list to JSON/** * * @param list * Bookmark Collection * @return JSON-formatted object */private static Jsonobject Listtojsojsonobject (ListBelow is the JSON
1,eval way to parse, I am afraid this is the earliest way to parse. As follows:function Strtojson (str) {var json = eval (' (' + str + ') ');return JSON;}Remember to do not forget the parentheses on both sides of Str.2,new function form, more strange oh. As followsfunction Strtojson (str) {var json = (new Function ("return" + str));return
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