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] + [\/= \? % \-_~ '@ [\] \': +!] * ([^ } // The data warehouse receiving escape special character input value can be a string or a one-dimensional array Function data_join ( $ data) { If (get_magic_quotes_gpc () = false) { If (is_array ($ data )) { Foreach ($ data as $ k => $ v) { $ Data [$ k] = addslashes ($ v ); } } Else { $ Data = addslashes ($ data ); } } Return $ data; } // Data warehouse restore special character input value can be a string or one/two-dimensional array Function data_reve

('/^ [_\. 0-9a-z-] + @ ([0-9a-z] [0-9a-z-] + \.) + [a-z] {2, 4} $/', $ str ))? True: false;}// Verify the phone numberFunction fun_phone ($ str){Return (preg_match ("/^ (\ d {3} \) | (\ d {3 }\-))? (\ (0 \ d {2, 3} \) | 0 \ d {2, 3 }-)? [1-9] \ d {6, 7} $/", $ str ))? True: false;}// Verify the zip codeFunction fun_zip ($ str){Return (preg_match ("/^ [1-9] \ d {5} $/", $ str ))? True: false;}// Verify the urlFunction fun_url ($ str){Return (preg_match ("/^ http: \ // [A-Za-z0-9] + \. [A-Za-z0-9

original value is replaced with the new value. Test code: [Java]Package test. junit;Import java. util. HashMap;Import junit. framework. TestCase;/*** In HashMap, determine whether two keys are the same: first judge the hashCode and determine whether equals* E. hash = hash (k = e. key) = key | key. equals (k ))* @ Author xuefeng**/Public class HashMapTest extends TestCase {/*** The hashCode of v1 and v4 is the same, but the equals does not match. Therefore, v1 and v4 form a linked list.*/Publi

T1:"Data Range"40% of the data meet a;another 30% of the data meet n,m;| s|,| T|100% of data meet n,m;| s|,| t|. The number of occurrences of the match in the Loop section, that is, the LCM (S,t), is first obtained.Then multiply the number of loops.is the number of equal character logarithm of the position of D=GCD (s,t) in the s,t.Can prove.Prove:Set S length to l1,t length of L2If the character of position A in S is the same as the character of position B in T.If it can be matched within the l

($ data );}}Return $ data;}// Data warehouse restore special character input value can be a string or one/two-dimensional arrayFunction data_revert ( $ data){If (is_array ($ data )){Foreach ($ data as $ k1 => $ v1){If (is_array ($ v1 )){Foreach ($ v1 as $ k2 => $ v2){$ Data [$ k1] [$ k2] = stripslashes ($ v2 );}}Else{$ Data [$ k1] = stripslashes ($ v1 );}}}Else{

lists are combined into an ordered dictionary2 #dic = {' K1 ': ' v1 ', ' K2 ': ' V2 '}3 #li = List ([' K1 ', ' K2 '])4 #5 #For I in Li:6 #print (Dic[i])7 ImportCollections8 9DIC =collections. Ordereddict ()Tendic['K1'] ='v1' Onedic['K2'] ='v2' Adic['K3'] ='v3' - Print(DIC)#ordereddict ([' K1 ', ' v1 '), (' K2 ', ' V2

EnterpriseLinux Server release 5.4 Hostname Gc1 Gc2 Database Oracle 10.2.0.1 Oracle 11.2.0.1 Character Set ZHS16GBK ZHS16GBK ORACLE_SID PROD EMREP Listener Name/Port LISTENER/1521 LISTENER/1521 Goldengate User Ogg Ogg 1. Continue to the experiment 3 environment, close the synchronization process, and perform updata and delete operations on gc1. SQL>Select * from TCUSTMER; CUST NAME CITY ST -----------

1. For numbers and strings, assignments, shallow copies, and deep copies are meaningless because they always point to the same memory address. >>> Import Copy# ######### number, string #########>>> N1 = 123>>> Print (ID (N1))# # # Assignment # #>>> N2 = N1>>> Print (ID (n2))# # # Light Copy # #>>> N2 = copy.copy (n1)>>> Print (ID (n2))# # # Deep Copy # #>>> n3 = copy.deepcopy (N1)>>> Print (ID (n3))2. For dictionaries, Ganso, and lists, the changes in the memory address of the assignment, the sh

Code Source: "Graph theory algorithm and its realization of MATLAB" (Beijing Air and Space Press)P25First, the function N2shorf is used to calculate the shortest path length between any two points and the least-shorted nodeNeed to enter start point, end point1function [P u] =N2shorf (W,K1,K2)2 3%W represents the weight matrix4%K1 represents the starting point, and K2 represents the endpoint5%p represents th

weights1.1.1.1 11.1.1.2 21.1.1.3 1#那么在内存中主机列表为:host_list=[' 1.1.1.1 ', ' 1.1.1.2 ', ' 1.1.1.2 ', ' 1.1.1.3 ',]Python Operation Memcache ClusterMC = Memcache. Client (['1.1.1.1:12000', 1), ('1.1.1.2:12000', 2), (' 1.1.1.3:12000', 1)], debug=True) mc.set ('K1' ' v1 ')Memcache Common operationsStorage commands: Set, add, replace, append, prepend, CAsGet command: Get, getsOther commands: Delete, statsAdd methodImportMEMCACHEMC= Memcache. Client (['192.1

(name, value)#检查value是否是name对应的集合内的元素Spop (name)#从集合的右侧移除一个元素, and return itSunion (keys, *args)#获取多个name对应的集合的并集R.sunion ("Set_name", "set_name1", "set_name2")Srem (name, value) removes an element from the collectionR.srem ("Set_name", "AA")Hash type operationRedis stores the hash type in memory as a dictionary stored in name.Hset (Name,key,value)#name对应的hash中设置一个键值对 (does not exist, is created; otherwise, modified)#参数:#name: Redis's name#key: Key1 key in the corresponding hash#value: value in

keys keyword common directives Here bloggers first set K1 v1 k2 v2Exists key Determine if key exists Move Key Dbnum Move key values to Dbnum libraryHere move K1 to library 2nd, view current library only K2, after switching to library 2nd, view the current K1 has moved over Expire key seconds Set the expiration time for a given key TTL key See how many seconds ar

Basic ConfigurationFirst, create a Django programTo create a project Terminal command:Project:django-admin startproject mysitecd mysitepython manage.py Startapp app011. Routing systemGeneral relationship:/index/---- functions ... #其他框架有 Reflection: /(\w+)/(\w+) /home/index/ = import: Home module, getattr (index) Fun () dynamic Relationship: /index/(\ w+) \ (parameter) routing distribution:/index/- app.url file [

DP, the state is F[I][J][K1][K2], for the first person, with J Boys, the suffix of boys more than the number of girls in the maximum value of K1, girls more than the number of boys maximum is k2.k1,k2 State transition equation F[i][j][k1][k2] = f[i-1][j-1][k1+1][k2-1] + f[i-

[Cryptography 02] cryptographic system principles and mathematical background In the previous article [cryptography], four theme topics briefly introduced the technical means used to achieve the confidentiality and integrity of information transmission, as well as identity authentication and anti-Repudiation: 1) Password Technology (encryption and decryption ). 2) Hash technology, that is, Hash technology. 3) random number. 4) timestamp. Next we will discuss the password technology. It is a typ

be divided into K dimensions. similarity calculation is its own behavior, put in bean internal only suitable, cancel annotation use) * @ author fuhuaguo * @ e-mail fhg@jusfoun.com * @ date September 1, 2015 10:43:25 **/public class Point extends Kmeansable {Private String id; // Dimension 1 private double k1; // dimension 2 private double k2; // dimension 3 private double k3; public Point () {} public Point (String id, double

Built-in data types:int float ComplexSTR list tupleDict SetUnderlying data type:int float ComplexSTR list tupleDictCollections module:Some extensions are made based on the underlying data type1, Orderddict: Ordered dictionary Python3.6 after automatic order2. Defaultdict: Default Dictionary3, Counter: Counter4, Namedtuple: can be named Yuan zu5. Deque: Double-ended queue1, Orderddict: (Ordered dictionary)　　　　The use of Dict,key before Python3.6 is unordered. We cannot determine the order of key

determines the number of specific items in a package. If the [] location of the persistent A statement to judge a statement that is durable in a particular position. If the parcel is empty Judge the sentence, judge the vacancy in the bag, easy to understand If the current map name Judge the statement of a map For example: If the current map name =[hot Sand desert], then ... (meaning: The current map is hot sand, then the ... do so) If the current map name If the body [] position of the equi

Find the list of values greater than 100, give the dictionary dic's K1 key, less than or equal to 100 of the value, to the dictionary dic K2 key‘‘‘Tip: Two ways to create a dictionaryEx‘‘‘V1 = [2,3,4,5== = = {'K1'K2' = Dict (K1 = v1, K2 = v2,) Print (DIC1) Print (DIC2)List = [2, 5, 9, 20, 27, 80, 100, 110, 127, 158, 166, 198,]dic= {}#define an empty dictionary#me

computer considers True to be 1 andFalse to 0 if the k value in front of it has 0 or 1, it will beCover it off. At output, True is replaced with 1,false is replaced with 0, which is found in the experiment when this feature is available. By the means, anon-0 value of type bool will be represented as 1 inside the computer . the value that causes the bool type to be false is 0, empty ( None), empty string ( ""), Empty tuple ( ()), empty list ( []), Empty dictionary ( {}), empty c