kanban equation

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Java Practice Questions: solving a two-time equation, judging leap years, judging the standard body, three numbers to take the maximum value

1. Solution of a two-dimensional equationNote: The root formula is (-b+ radical Delta)/2a, (-b-)/2a Scanner sc=new Scanner (system.in); SYSTEM.OUT.PRINTLN ("Input A:");d ouble a=sc.nextfloat (); SYSTEM.OUT.PRINTLN ("Input B:");d ouble b=sc.nextfloat (); SYSTEM.OUT.PRINTLN ("Input C:");d ouble c=sc.nextfloat ();d ouble delta=b*b-4*a*c,x1,x2;if (delta>0) {x1= (-b+math.sqrt ( Delta)/(2*A); x2= (-b-math.sqrt (Delta))/(2*A); System.out.println ("real roots of the

The course summary of the numerical solution of differential equation in this semester (MATLAB code)

The simplest solution to the numerical solution of a differential equation: Euler method function [X,y]=euler_method (DUFUN,SPAN,H,X0,Y0)%euler format,% equation y ' =dufun (x, y), where x \in[a,b];y0 is the initial value; n is the discrete number of independent variables ; Y is the solution result X=span (1): H:span (2), n=length (x); Y=zeros (1,n);% stored value solution x (1) =x0;y (1) =y0;for i=1:n

1743: Solution equation

1743: Solution Equation descriptionA group of Ultraman defeated a group of small monsters, known all Ultraman have X1 head, y1 leg (mutation Ultraman), all the small monsters have x2 head, y2 leg. Battlefield on a total Q head, W leg, asked how many Ultraman, how many small monsters?InputThe input data has several groups each group contains 6 positive integers, respectively, x1,y1,x2,y2,q,w; (0OutputThe output takes up a row, containing two positive i

Intersecting Lines (cross product, equation)

X1y1x2y2x3y3x4y4. Thus each of these input lines represents, lines on the Plane:the line through (x1,y1) and (X2,y2) and the line Throug H (x3,y3) and (X4,y4). The point (x1,y1) is always distinct from (x2,y2). Likewise with (X3,y3) and (X4,y4).OutputThere should be n+2 lines of output. The first line of output should read intersecting LINES output. There'll then being one line of output for each pair of planar lines represented by a line of input, describing how the Lin Es intersect:none, line

"CodeVS1983" equation problem

DescriptionThere is an unfinished equation: 1 2 3 4 5 6 7 8 9=n space (1 front without spaces) can be filled in +,-, can also be blank. Programming to find out the total number of all scenarios in which the equation is formed after entering an integer N. Guaranteed to have a solution.InputEnter a number n.OutputOutputs a number. The number of all scenarios.Sample Input108Sample Output15ExercisesTo find out

HDU 2199 Can You solve this equation? (Two-point search)

Topic linksproblem DescriptionNow,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 = = Y,can you find its solution between 0 and 100;Now try your lucky.InputThe first line of the input contains an integer T (1OutputFor each test case, you should just output one real number (accurate up to 4 decimal places), and which is the solution of the E Quation,or "No solution!", if there is No solution for the equation

Hdu3579:hello Kiki (solution of one-element linear congruence equation set)

Title: http://acm.hdu.edu.cn/showproblem.php?pid=3579Problem analysis: To find the smallest solution x of a linear congruence equation, it is important to note that if x equals 0, an integer interval LCM (a1,a2,a3,... An) is required to add a general solution to the equation group.There's nothing else to watch out for.#include #include#includestring.h>#include#includeusing namespacestd;__int64 a,b,c,d;__int

POJ 2947-widget Factory (Gaussian elimination solution with congruence equation)

Title Address: POJ 2947Test instructions: N Kinds of items, m Records, and then write to M line, each line has k,start,end, the expression from the week start to the End of the week, do the K-items, the next number of K for the item numbers. This topic notes that the final result is to be adjusted to 3-9.Ideas:It is easy to think of Gaussian elimination. But it's Gaussian elimination with the same equation, and it's time to start building a relationsh

1103. Two-time equation calculator

Title Description: Design a two-time equation calculator Input: Each case is a two-time equation of expression for x, and for simplicity, each coefficient is an integer form. Output: Each case outputs two real numbers (from small to large output, separated by spaces), retains two decimal places, and outputs "no

Hdu2769: enumeration + homogeneous equation

A random number generator X [I + 1] = (A * X [I] + B) % 10001 We know that x1, X3, x5... is used to calculate X2, X4, x6 ...... The number of X is 2n (n Analysis: There are two unknown numbers A and B. It is difficult to solve the equation, but only by enumeration. During the competition, I thought about enumerating a and B. I felt a little more complex and did not dare to write it. (later, it was said that I could pass through the violent posture) T

Equation language: c

ArticleDirectory Solving Equations Time limit for solving the equation: 1000 ms memory limit: 10000 k total time limit: 3000 Ms Description: Calculate the root of the equation 2x ^ 3-4x ^ 2 + 3xsinx-6 = 0 using the Newton iteration method, and the error must be less than-6 power of 10. Input: A floating point number, indicating the start point. Output: A floating point number is the

Fzoj2102: solve equation

You are given two positive integers A and B in base C. For the equation: A = K * B + d We know there always existing into non-negative pairs (K, d) that satisfy the equation above. Now in this problem, we want to maximize K. For example, a = "123" and B = "100", c = 10. So both A and B are in base 10. Then we have: (1) A = 0 * B + 123 (2) A = 1 * B + 23 As we want to maximize K, we finally get one

Week 9 Task 5-find the root of the mona1 quadratic equation

Content on the machine: Use the if statement to solve the root of a quadratic equation. Objective: To learn the Branch StructureProgramDesign/** copyright (c) 2012, School of Computer Science, Yantai University * All Rights Reserved. * Prepared by: Yang Chen * Completion Date: July 15, October 25, 2012 * version No.: V1.0 ** enter the value of A, B, and C * Problem description: enter a, B, C to obtain the root of the

Use Equation Editor in Word to edit mathematical formulas

In Word2003, you can use the Equation Editor to enter mathematical formulas such as fractions, radicals, and so on, as described in the following procedure: Step 1th, open the Word2003 document window and select the Insert → object menu command in the menu bar, as shown in the figure. In the 2nd step, in the Open Object dialog box, switch to the new tab. Select the Microsoft Formula 3.0 option in the Object Type list and click OK, as sho

Java practice-Write a form program to compute a two-time equation. __java

Practical Training Requirements: Code: Equationexception class: Import java.awt.*; Import java.awt.event.*; Import javax.swing.*; Class Equationexception extends RuntimeException {public static final int none_equation = 1; public static final int no_realroot = 2; private int errorcode; Public equationexception (String msg, int errorcode) {super (MSG); This.errorcode = ErrorCode; public int GetErrorCode () {return errorcode; } public class Equationframe extends JFrame implements Actio

Solution of "Openjudge" three-time equation _ two points

7891: One-yuan three-time equation solution Total time limit: 1000ms memory limit: 65536kB description Tangible as: Ax3+bx2+cx+d=0 such a unary three-time equation. The coefficients of each of the equations (A,b,c,d are real numbers) are given, and it is agreed that there are three different real roots (the root range is between 100 and 100), and the absolute value of the difference between root and root is

Solving a three-time equation of one dollar

problem DescriptionTangible such as: ax^3+bx^2+cx+d=0 such a one-dimensional three-time equation. The coefficients of each of the equations (A,b,c,d are real) are given, and the equation has three different real roots (the range of the roots between 100 to 100), and the absolute value of the difference between root and root is >=1. It is required to output these three real roots (spaces between root and roo

C language: Calculate the heel of the quadratic equation of a. The coefficients a, B, and c are input by the keyboard.

C language: Calculate the heel of the quadratic equation of a. The coefficients a, B, and c are input by the keyboard.Calculate the following of the quadratic equation of a, B, and c from the keyboard input program: # Include Result: Enter the values of a, B, and c: 2 3 1x1 =-0.500000x2 =-1.000000. Press any key to continue...

Basic algorithm of C language 24-Golden section method for approximate root of equation

Golden Division!/*================================================================Title: The root of 3*x*x*x-2*x*x-16=0 is solved by the Golden Section method.================================================================*/#include #include #define E 1e-8Double HS (Double x){return 3*x*x*x-2*x*x-16;}Double Gen (double a,double b){Double x,fx,fa,fb,g;G= (sqrt (5)-1.0)/2;FA=HS (a);FB=HS (b);while (Fabs (b-a) >e){x=g* (b-a) +a;FX=HS (x);if (fa*fx>0){A=x;FA=FX;}else if (fb*fx>0){B=x;FB=FX;}}return

POJ 2115 for Loop count-number theory-(congruence equation + extended Euclidean algorithm)

Test instructions: Given the initial value of the For loop, the end value and increment, and a modulo, the minimum number of cycles.Analysis:After reading the question should know is a concept of congruence, so it is to solve a one-time congruence equation, like the above problem with the expansion of Euclidean algorithm. The trick point of the problem is K Max is 32, then 2^32 out of int, to use a long long, so in 1Code:#include Copyright NOTICE: Th

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