The switch will send an echo to its neighbor. If the neighbor does not receive a response within a certain period of time, it is deemed that the link with the neighbor has a problem. In normal mode, the link may be regarded as an uncertain state and will not be closed (note that normal mode can only detect misunderstandings of optical fibers, such as Tx and Rx insertion and inversion ). In the aggressive mode, the link is regarded as one-way and closed (the interface is placed in the err-Disable
. ClassName = xxx.The first sentence of JavaScript--if judgmentCase: Click on the "More" button to display and hide DivImplementation Principle Analysis:When the user clicks, if the div is shown hidden = ODiv.style.display = ' None 'Or Div is hidden to show up = ODiv.style.display = ' block 'Basic syntax:if (div is display) {ODiv.style.display = ' None ';}else{ODiv.style.display = ' block ';}Summary: A tentative study of the charms of JavaScript (1)What is JS? JavaScript modifies the style or pr
l2-019. Quietly focus on time limit MS
Memory Limit 65536 KB
Code length limit 8000 B
Standard author Chen Yue The procedure of the sentence
Sina Weibo has a "quiet attention", a user quietly focus on the person, does not appear on the user's list of concerns, but the system will push its quietly concerned about the microblog published by the user. Now we're going to be a cyber detective, picking out people who are likely to be secretly concerned, b
l2-001. Emergency response time limit of MSMemory Limit 65536 KBCode length limit 8000 BChen, standard author of the procedure for the award of questions
As the head of a city's emergency rescue team, you have a special national map. The map shows a number of scattered cities and some quick roads connecting the city. The number of rescue teams in each city and the length of each fast road connecting two cities are marked on the map. When other cities
l2-001. Emergency rescue
As the head of a city's emergency rescue team, you have a special national map. The map shows a number of scattered cities and some quick roads connecting the city. The number of rescue teams in each city and the length of each fast road connecting two cities are marked on the map. When other cities have an emergency call for you, your task is to lead your rescue team to the scene as quickly as possible, while gathering as m
l2-023. Graph coloring problem time limit (ms)Memory Limit 65536 KBCode length limit 8000 BChen, standard author of the procedure for the award of questions
The graph coloring problem is a well-known NP-complete problem. Given the graph G = (V, E), ask if you can assign a color to each vertex in V with a k color, so that no two adjacent vertices have the same color.
But the question is not to solve this coloring problem, but for a given color assignme
Title Link: https://www.patest.cn/contests/gplt/L2-006
Thinking analysis: After the order can know the root, and then in the middle sequence to find the root, and can determine the left and right sub-tree, and then recursively to the left and the sub-tree decomposition, you can restore the two-fork tree. Finally, the built-up tree BFS can be written hierarchically traversed.
The AC code is as follows:
#include
l2-001. Emergency rescue time limit MS Memory limit 65536 KB code length limit 8000 B procedure StandardAuthor ChenAs the head of a city's emergency rescue team, you have a special national map. The map shows a number of scattered cities and some quick roads connecting the city. The number of rescue teams in each city and the length of each fast road connecting two cities are marked on the map. When other cities have an emergency call for you, your ta
l2-004. Is this a two-fork search tree? Time limit MS Memory limit 65536 KB code length limit 8000 B procedure StandardAuthor ChenA binary search tree can be recursively defined as a two-fork tree with the following properties: for any node,
The key value of all nodes in the left subtree is less than the key value of the node;
The key value of all nodes in the right subtree is greater than or equal to the key value of the node;
The le
An analysis of the two-layer VLAN forwarding of Huawei Ethernet switches and its advantages. To solve the problem of VLAN introduced by Huawei Ethernet switches, we must first understand the benefits brought by VLAN introduction. Remember the corresponding instance. Therefore, it is very advantageous to study the following carefully.
Packet forwarding thread: After VLAN is introduced, the packet forwarding thread of the L2 Switch has the following imp
PAT L2-006. tree traversal, patl2-006L2-006. tree traversal
Time Limit
Memory limit
Code length limit
Question determination procedure
Author
400 MS
65536 kB
8000 B
Standard
Chen Yue
Given the post-and Middle-order traversal of a binary tree, please output ITS sequence traversal. Here we assume that the key values are all positive integers that are not equal to each other.
Input Format:
The first line of
Title: http://community.topcoder.com/stat?c=problem_statementpm=13251rd=16017References: Http://apps.topcoder.com/wiki/display/tc/TCO+2014+Round+2CAssume that each edge is calculated first, the adjacency matrix is used to represent the graph, and then the BFS or Floyd-warshall algorithm is used to calculate the distance. The time complexity is O (n^3), which times out. According to the title of the tip know to use the nature of clique graph to do. The basic idea is to treat a clique as a whole i
the stock (in million tonnes) of each mooncake, and the last line gives a positive n indicating the total price of each mooncake (in billions of dollars). The numbers are separated by a space.Output format:For each set of test cases, output the maximum profit in a row, in units of billions and accurate to 2 digits after the decimal point.Input Sample:3 2018 15 1075 72 45Sample output:94.50Simple structural and sequencing application questions1#include 2#include 3#include 4 using namespacestd;5
The simple rules for students to evaluate each other's work are as follows: Everyone's homework will be judged by the K-students and get K scores. The system needs to get rid of a maximum score and a minimum score, and the remaining scores are averaged to obtain the student's final result. The subject asks you to write the calculation sub-module of this mutual evaluation system.Input format:Enter the first line to give 3 positive integers n (34, total students), K (3Output format:Outputs the hig
Original web site http://blog.csdn.net/yygydjkthh/article/details/6750399
It is the specific forwarding process of the L2 Switch. The following describes the forwarding process in detail.
First, let's take a look at what tpid means?
Frames in the 802.1Q document of VLAN protocol are embodied in the following data packets:
Here, the blue position is the 802.1Q header, and the specific meaning of each item is:
Tag protocol identifier(TAG protocol ide
CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->// L1
Game game = new Game () {Width = 600, Height = 400 };
Game. Camera = new Camera ();
Game. Camera. Position = new Coordinate (100,150,100 );
Game. Camera. Target = new Coordinate (0, 0, 0 );
Game. Children. Add (new OmniLight () {Position = new Coordinate (0, 0, 0 )});
// L2// A new Mesh object MeshMesh Teapot = new Mesh ();// Set coordinatesTeapot. Position = new Coordinate (0, 0, 0 )
An instance of VLAN configuration for Cisco L3 switches and L2 SwitchesCisco VLAN implementation is usually port-centric. The port connected to the node determines the VLAN in which it resides. There are two ways to allocate a port to a VLAN: Static and Dynamic. The process of creating a static VLAN is to forcibly allocate the port to a VLAN. That is, we first create a VLAN on The VTP (VLAN Trunking Protocol) server, and then assign each port to the c
Question:
Ideas
Method 1: determine each substring of a string. If it is symmetric, obtain its length. This method is used to determine whether a substring is a substring from both ends to the middle. The total time complexity is O (n ^ 3 ),
The time complexity is O (n ^ 2.
Method 2: opposite to the method, each start in the string is extended to both sides, which can be divided into two situations:
(1) When the length of a symmetric substring is an odd number, the current character is used as t
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