latitude 3550

Functionradian ($d) { $d *3.1415926535898/180.0;}functiondistance_calculate ($longitude 1, $latitude 1, $longitude 2, $latitude 2) { $radLat 1=adian ( $latitude 1); $radLat 2=radian ( $latitude 2); $a =radian ($ latitude1) -radian ( $latitude 2); $b =radian ( $longitude

Requirement: Obtain the surface distance between two points according to latitude and longitude, and calculate the direction between two pointsReference:Android get latitude and longitude, calculate distance, azimuth angle there is a formula in the post, I will not repeat it. There is no function to write the azimuth, because it is very simple to use temporarily.Calculate the distance and direction between

Copy Code code as follows: function Getdistancebetweenpointsnew ($latitude 1, $longitude 1, $latitude 2, $longitude 2) { $theta = $longitude 1-$longitude 2; $miles = (sin (Deg2rad ($latitude 1)) * Sin (Deg2rad ($latitude 2)) + (cos (Deg2rad ($latitude 1)) * cos (Deg2r

Specifies a latitude and longitude, given a range value (in kilometers), to isolate the data within this range around the latitude and longitude.Longitude: 113.914619Latitude: 22.50128Range: 2kmLongitude as a data table longitude fieldLatitude for the data table latitude fieldSQL is tested under MySQL, other databases may need to be modifiedThe SQL statements are

P.s: in this article, you will find a way to obtain the latitude and longitude Based on the city keyword, that is, to obtain the latitude and longitude through the reverse latitude and longitude query interface of the Google map API.Google map APIIs a powerful map API, many well-known websites are using Google map API, once I also wrote a program based on visitor

The earth is a nearly standard ellipsoid with an equatorial radius of 6378.140 km, a polar radius of 6356.755 km and an average radius of 6371.004 km. If we assume that the earth is a perfect sphere, then its radius is the average radius of the Earth, recorded as R. If the 0-degree meridian is used as a benchmark, the surface distance between the two points can be calculated based on the latitude and longitude of any two points on the Earth's surface

describe a concept, a map overlay: All overlays or overlays to the map, collectively referred to as map overlays. such as callouts, vector graphic elements (including: Polylines and polygons, and circles), positioning icons, and so on. Overlays have their own geographic coordinates, and when you drag or zoom the map, they move accordingly. requirements to be fulfilled: if we know the GPS latitude and longitude of the Beijing Tian ' an gate (building):

publicclassgeoutil{/** * returns a rectangular range based on latitude and longitude **@ paramlng* Longitude * @param lat* Latitude * @param distance* distance (in meters) * @return [lng1,lat1,lng2,lat2] lower-left corner of the rectangle ( LNG1,LAT1) and upper right Corner (LNG2,LAT2) */publicstatic double[]getrectangle (doublelng,doublelat,longdistance) { floatdelta=111000;if (lng!=0lat!=0) { doublelng

Foreword: When doing iOS project today, need to be positioned to get the name of the current city. Baidu Maps SDK has this function, but in order to not rely on a third party, here I use iOS with the framework corelocation to achieve this requirement. IOS8 out, for positioning needs a little more processing, can be normal positioning, this will be at the end of the article to supplement, in the statement before the part is the default iOS7 processing. First, we need to import the Corelocation s

#region//latitude and longitude transfer of Mercator static double m_pi = Math.PI; Transfer of Mercator by latitude Longitude (Lon), Latitude (LAT) Public double[] Lonlat2mercator (double lat, double lon) { double[] xy = new DOUBLE[2]; Double x = Lon *20037508.342789/180; Double y = Math.Log (Math.tan (90+lat) *m_pi/360))/(m_pi/180); y = y *20037508.34789/180; Xy

Original source: http://blog.163.com/ezy_dk/blog/static/166651492201221445753585/ Reference Web: A preliminary study of nearby location search The following is a summary of your own SQL code Declare @EARTH_RADIUS float Set @EARTH_RADIUS = 6371000.00-Earth's radius declare @lat float declare @lng float declare @dlng float declare @dlat float declare @distance int --distance set @distance = --300 m C9/>set @lat =xx.xxxxx -This is the central location set @lng = xxx.xxxx -central

It is now often necessary to provide some information about location based on the location provided by the user. Sometimes you can directly determine the latitude and longitude of the user, sometimes not necessarily determine the user's latitude and longitude information, the user is through the input of some road name, landmark building or store name location, but our database may not be stored in the user