lightest chromebook

the principle that a Light Bubble cannot be under a heavy bubble, scan the array R from the bottom up: Any Light Bubble scanned to a violation of this principle will make it "float" up ". This is repeated until the last two bubbles are light and heavy.(1) initialR [1. n] is an unordered area.(2) First scanThe weights of two adjacent bubbles are compared from the bottom of the unordered area to the top. If the light bubbles are found to be in the lower and severe bubbles, the positions of the tw

complete, the "lightest" bubble floated to the top of the interval, that is, the record with the smallest keyword is placed on the highest position R [1.(3) second scanScan R [2. n]. When scanning is completed, the "light" bubble floated to the R [2] position ......Finally, the sequential area R [1. n] can be obtained through n-1 scanning.Note:During the I-trip scan, R [1 .. I-1] and R [I.. n] are the current sequential and disordered areas, respecti

each pair of bubbles (R [j + 1], R [j]), if R [j + 1]. key When the first scan is complete, the "lightest" bubble floated to the top of the interval, that is, the record with the smallest keyword is placed on the highest position R [1.(3) second scanScan R [2. n]. When scanning is completed, the "light" bubble floated to the R [2] position ......Finally, the sequential area R [1. n] can be obtained through n-1 scanning.Note:During the I-trip scan, R

) First scanThe weights of two adjacent bubbles are compared from the bottom of the unordered area to the top. If the light bubbles are found to be in the lower and severe bubbles, the positions of the two bubbles are exchanged. That is, compare (R [n], R [n-1]), (R [n-1], R [N-2]),…, (R [2], R [1]); for each pair of bubbles (R [j + 1], R [j]), if R [j + 1]. key When the first scan is complete, the "lightest" bubble floated to the top of the interval,

bottom up: Any Light Bubble scanned to a violation of this principle will make it "float" up ". This is repeated until the last two bubbles are light and heavy.(1) initialR [1. n] is an unordered area.(2) First scanThe weights of two adjacent bubbles are compared from the bottom of the unordered area to the top. If the light bubbles are found to be in the lower and severe bubbles, the positions of the two bubbles are exchanged. That is, compare (R [n], R [n-1]), (R [n-1], R [N-2]),…, (R [2], R

bubbles are found to be in the lower and severe bubbles, the positions of the two bubbles are exchanged. That is, compare (R [n], R [n-1]), (R [n-1], R [N-2]),…, (R [2], R [1]); for each pair of bubbles (R [j + 1], R [j]), if R [j + 1]. key When the first scan is complete, the "lightest" bubble floated to the top of the interval, that is, the record with the smallest keyword is placed on the highest position R [1.(3) second scanScan R [2. n]. When sc

+ 1]. key When the first scan is complete, the "lightest" bubble floated to the top of the interval, that is, the record with the smallest keyword is placed on the highest position R [1.(3) second scanScan R [2. n]. When scanning is completed, the "light" bubble floated to the R [2] position ......Finally, the sequential area R [1. n] can be obtained through n-1 scanning.Note:During the I-trip scan, R [1 .. I-1] and R [I.. n] are the current sequenti

scanThe weights of two adjacent bubbles are compared from the bottom of the unordered area to the top. If the light bubbles are found to be in the lower and severe bubbles, the positions of the two bubbles are exchanged. That is, compare (R [n], R [n-1]), (R [n-1], R [N-2]),…, (R [2], R [1]); for each pair of bubbles (R [j + 1], R [j]), if R [j + 1]. key When the first scan is complete, the "lightest" bubble floated to the top of the interval, that i

it "float" up ". This is repeated until the last two bubbles are light and heavy.(1) initialR [1. n] is an unordered area.(2) First scanThe weights of two adjacent bubbles are compared from the bottom of the unordered area to the top. If the light bubbles are found to be in the lower and severe bubbles, the positions of the two bubbles are exchanged. That is, compare (R [n], R [n-1]), (R [n-1], R [N-2]),…, (R [2], R [1]); for each pair of bubbles (R [j + 1], R [j]), if R [j + 1]. key When the f

) initialR [1. n] is an unordered area.(2) First scanThe weights of two adjacent bubbles are compared from the bottom of the unordered area to the top. If the light bubbles are found to be in the lower and severe bubbles, the positions of the two bubbles are exchanged. That is, compare (R [n], R [n-1]), (R [n-1], R [N-2]),…, (R [2], R [1]); for each pair of bubbles (R [j + 1], R [j]), if R [j + 1]. key When the first scan is complete, the "lightest" b

of the two records is the opposite, the two records are exchanged until there is no reverse order record.The basic concepts of application exchange sorting include Bubble sorting and quick sorting.Bubble Sorting1. Sorting MethodVertically arrange the sorted record array R [1. n]. Each record R is considered as a bubble with the weight of R. key. According to the principle that a Light Bubble cannot be under a heavy bubble, scan the array R from the bottom up: Any Light Bubble scanned to a viola

complete, the "lightest" bubble floated to the top of the interval, that is, the record with the smallest keyword is placed on the highest position R [1.(3) second scanScan R [2. n]. When scanning is completed, the "light" bubble floated to the R [2] position ......Finally, the sequential area R [1. n] can be obtained through n-1 scanning.Note:During the I-trip scan, R [1 .. I-1] and R [I.. n] are the current sequential and disordered areas, respecti

do is to select the label in this range of all goods weight of the lightest one, And tell little hi the weight of this product. But in the process, the weight of the goods in certain locations may change (for example, the replacement of other kinds of goods) because of the behavior of others.Little Ho proposed two very simple methods, but none of them could be solved perfectly. So this time, in the face of a bigger data size, what will little ho be g

order of two adjacent elements is correct. If the order of two adjacent elements is incorrect, that is, the "light" elements are located below, and their positions are exchanged. Obviously, after processing it again, the "lightest" element floated to the highest position; after processing it twice, the "minor" element floated to the lower position. During the second processing, you do not have to check because the element at the highest position is a

The simplest sorting method is the Bubble sorting method. The basic idea of this method is to regard the elements to be sorted as vertical "Bubbles", and the smaller elements are relatively light, so as to move up and down. In the Bubble sorting algorithm, we need to process the "bubble" sequence several times. The so-called one-time processing is to check the sequence from the bottom up, and always pay attention to whether the order of two adjacent elements is correct. If the order of two adjac

lot of interaction logic and rendering work, and the server mainly processes requests and returned data. Frontend and backend System Coupling: the client and the server process the coupling of their internal subsystems. The coupling between the client and the server is simplified as a communication and data channel. This channel is used to transmit communication requests and return data; Request communication: HTTP/TCP protocol Data Channel: JSON, XML, text string, and byte. The in

]), (R [n-1], R [N-2]),…, (R [2], R [1]); for each pair of bubbles (R [j + 1], R [j]), if R [j + 1]. key When the first scan is complete, the "lightest" bubble floated to the top of the interval, that is, the record with the smallest keyword is placed on the highest position R [1.(3) second scanScan R [2. n]. When scanning is completed, the "light" bubble floated to the R [2] position ......Finally, the sequential area R [1. n] can be obtained through

heavy.(1) initialR [1. n] is an unordered area.(2) First scanThe weights of two adjacent bubbles are compared from the bottom of the unordered area to the top. If the light bubbles are found to be in the lower and severe bubbles, the positions of the two bubbles are exchanged. That is, compare (R [n], R [n-1]), (R [n-1], R [N-2]),…, (R [2], R [1]); for each pair of bubbles (R [j + 1], R [j]), if R [j + 1]. key When the first scan is complete, the "lightest