linear programming book

strategy B3The expression for the expected loss-in-the-share for company-B for each company A strategy are provided in Table 5.10.Company A would select A1, A2, or A3 based onMax {El (A1), El (A2), El (A3)}When company A selects its strategy, the value of the game would be the expected loss, which would maximize company B ' s EXPE CTED loss in the market share. Company B would select its optimal mixed strategy using a MINIMAX strategy to minimize the maximum expected loss. This objective is wri

Test instructions: P, q, all integers.Sigma (Ai * ki) >= p,Sigma (Bi * ki) >= q;ans = Sigma (ki). Minimum value for output ansconstraints of 2, but the variable K has 100,000, so you can use duality to convert to SolvingAns = p * y1 + q * y2The constraints are:Ai * y1 + Bi * y2 That is, the n constraint condition. It's just a three-point back.1#include 2 using namespacestd;3 Const intMAXN = 1e5 +5;4 DoubleA[MAXN], B[MAXN], p, q;5 intN;6 DoubleCheckDoublex) {7 Doubley =1e20;8 for(inti =

#include 4#include 5#include 6 using namespacestd;7 Const intMAXN =1005;8 structLamp9 {Ten intV, K, C, L; One BOOL operatorConstlamp a)Const A { - returnV A.V; - } the }LAMP[MAXN]; - intDP[MAXN], SUM[MAXN]; - intMain () - { + intN; - while(~SCANF ("%d", n) N) + { A for(inti =1; I ) at { -scanf"%d%d%d%d", lamp[i]. V, lamp[i]. K, lamp[i]. C, Lamp[i]. L); - } -Sort (lamp+1, lamp+1+n); -memset (SUM,0,sizeof(sum)); -Memset (DP,0,sizeof(DP)

1, delete the data at the specified location;Questions and Answers:/* Delete data at the specified location */#include Operation Result:Learning experience:Delete data from one location, and each subsequent data will overwrite the previous data;Knowledge Summary:The number of deleted I loops becomes smaller;The data length becomes smaller after deletion;The function definition takes into account which parameters are used and whether there are return values;2, insert a data at the specified posit

1. (DVDFormulaCodeMODEL:SETS:CN/c1. C1000/: B;dn/d1. D100/:D Vnum; LINKS (CN,DN): sati,x; Endsetsdata:sati,dvnum[Email protected] ('D:\LINGO\DATA\b2005table2.xlsx'); @OLE ('D:\LINGO\DATA\b2005table2.xlsx','X','B')=x,b; @TEXT ()=@STATUS (); Enddatasa=@SUM (LINKS (i,j): @IF (Sati (i,j) #EQ #0,0,1) *x (i,j) * ( One-Sati (i,j)); NUM=@SUM (CN (i): B (i)); MAX=SA; @FOR (LINKS (i,j): @BIN (X (i,j)), @FOR (CN (i): @BIN (B (i))), @FOR (DN (J): @SUM (CN (i): X (i,j))Dvnum (j)); @FOR (CN (I): @SUM (DN (j):

Rewrite requirement 1: Replace array with pointer PA, PB, respectivelyRewrite requirement 2: Enter data element from keyboard any number of elements, enter 0 end#include #includeusing namespacestd;classdata{Double*pa,*PB; Doublemax,min; Doublenew_max,new_min; intlength; Public: DATA (DoubleA1[],DoubleXDoubleYintLen) { inti; Length=Len; PA=New Double[Len]; PB=New Double[Len]; for(i=0; i) Pa[i]=A1[i]; New_max=x; New_min=y; Max=min=pa[0]; for(i=0; i) {

the The linear programming is given by the standard type. n variables, m constraints.n,m≤20 N,m\le Simplex template problem #include

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