linked list class c

Troubled for a long time the data structure to pick up, refer to the blog Daniel's article, think out a bit of their own understanding, hope to learn the data structure on the way of the brothers and sisters to help, but also for their home to clear ideas. Nonsense not much to say, directly on the code.The required header files are as follows and the security warning is masked:#define _crt_secure_no_warnings#includeThe data type of the linked

->next = q;return head;}listnode* p = p1->next;listnode* q1 = q->next;Q->next = NULL;Doreverse (P);P1->next = q;P->next = Q1;return head;}}There are short implementations of code, but I am learning from others, execution speed is similar:listnode* dummy = new ListNode (0);Dummy->next = head;ListNode *lefti = dummy;for (;--m;--n) Lefti = lefti->next;ListNode *cur = lefti->next, *rtail = cur, *pre = nullptr;while (n--) {listnode* NXT = cur->next;Cur->next = pre;Pre = cur;cur = NXT;}Rtail->next = c

Title: Reverse list of nodes from m-n locationsFor example:Given1->2->3->4->5->null, m = 2 and n = 4,Return1->4->3->2->5->null.The nodes from the second to the fourth are reversed.where m and n satisfy the condition:1≤ m ≤ N ≤length of the list.Ideas:Still in reverse order, consider using a secondary space stack.The nodes of the m-n are sequentially placed into the stack and marked with the front and back two nodes adjacent to the stack node Pfirst an

Title DescriptionEnter a list that returns a ArrayList in the order of the list values from the end of the header.Title Addresshttps://www.nowcoder.com/practice/d0267f7f55b3412ba93bd35cfa8e8035?tpId=13tqId=11156tPage=1rp=2 ru=%2fta%2fcoding-interviewsqru=%2fta%2fcoding-interviews%2fquestion-rankingIdeasUsing the Python library function, create a new list, insert

It is known that the data elements in a single-linked list contain three types of characters (i.e. alphabetic characters, numeric characters and other characters), try to write the algorithm, construct three circular linked lists, make each loop list contain only the same class of characters, and use the node space in

#include "stdio.h"#include "conio.h"#include "stdafx.h"#include using namespace Std;struct stu{Char name[20];char sex;int no;int age;struct Stu * NEXT;}*linklist;struct Stu *creatlist (int n){int i;H is the head node, p is the previous node, S is the current node.struct Stu *h,*p,*s;h = (struct Stu *) malloc (sizeof (struct stu));H->next = NULL;P=h;for (i=0;i{s = (struct Stu *) malloc (sizeof (struct stu));P->next = s;printf ("Please input the information of the Student:name sex no-age \ n");sca

Doubly linked list,Doubly linked list needs to add a previous property/*doubly linked list **/functionNode (Element) { This. Element =element; This. Next =NULL; This. Previous =NULL;//the doubly

","Zara","Yes","But","Row","OK","another"); linkednode"-------------------------------------------"); Dumplinkedlist (HEAD22);End Prepare System.out.println ("\n++++++++++++++++++++++++++++++++++++++++++\n");Start Test linkednode"-------------------------------------------"); linkednode/** recusive. Return head node as ascending. Would change parameters, non reentrant. */PublicStatic MergeSortedLinkedList1 (linkednodeif (A = =NULL) {return b; }if (b = =NULL) {return A; }if (Isfirstlessthansecond

Static linked list of adding and deleting, note the method of boundary check and parameter validity check. Test cases should be comprehensive!!!#include This article is from the "Small Stop" blog, please be sure to keep this source http://10541556.blog.51cto.com/10531556/1703847Linked list: static linked

"Idea": the direct addition of the test data is the line. But I still want to try the list, data structure after a year does write a little trouble. Alas.Note: The spelling of the node link. And p->p at the time of traversal, skimming the head node."AC Code":#include Blue Bridge Cup ALGO-107 9-7 linked list data summation operation (

Package Linklist.doublelinklist;public class Node {public int data;//data domain public node next;//node field, next node public node prve;// node field, previous node//head node Initialize public node (node next) {This.data=data;this.next=next;this.prve=null;} Non-head node initialization public node (int data,node next,node prve) {this.data=data;this.next=next;this.prve=prve;}}*************************************************************************************************************** ******

1. pointer Interaction Two pointers are directed to the frontend and the successor nodes respectively, and are moved on the one-way linked list. When the Pointer Points to the knots to be processed, the frontend of the node also points. 2. an unordered one-way linked list is created, and the values of the data fields a

The double-ended linked list is very similar to the traditional linked list. The only difference is that a last reference points to the end of the linked list. Therefore, you can add nodes at the end of the

Data structure experiment linked list 3: reverse configuration of the linked list Data structure experiment linked list 3: reverse configuration of the linked

This is a document issued during company training, not original This is a list of two-way linked list header files. h I understand. Almost all linked list operations are OK, which is quite easy to use. # Ifndef _ list_h _# DEFINE _ list_h _ /** Simple doubly

Single-cycle linked list and cyclic linked list 1 # include

#include C Language: "Single-linked list" To find the middle node of a single-linked list, requires only one time to traverse

New ListNode ( -1= dummy3; while (head2!=nullhead1!=null) { Pre.next=head1; = Head1.next; Head1.next=head2; = Head2.next; Head2.next=null; Pre=head2; Head1=head1next; Head2=head2next;}The code above is the correct notation.1ListNode dummy3 =NewListNode (-1);2ListNode pre =Dummy3;3 while(head2!=NULLhead1!=NULL){4pre.next=Head1;5Pre.next.next =head2;6 //ListNode head1next = head1.next;7 //head1.next=head2;8 //ListNode head2next = head2.next;9

Joseph's ring is an application of mathematics: n people (represented by numbers 1, 2, 3... n) are known to be sitting around a round table. The number of people numbered k starts to report, and the person counting to m is listed; his next person starts from 1 The number of people who count to m is displayed again. Repeat this rule until all the people around the Round Table are listed. Now we are writing a circular linked

The number of inserts is num. If it is smaller than the head, it is inserted in the chain table header. If it is larger than the elements in the chain table, it is inserted at the end; otherwise, it is inserted in the chain table; The Code is as follows: 1 link * link: add (link * plink, int num) {2 link * P1, * P2; 3 p1 = plink; 4 link * p0 = new link; 5 P0-> id = num; 6 7 while (P0-> ID> P1-> ID) (P1-> next! = NULL) {8 P2 = p1; 9 p1 = p1-> next; 10} 11 // insert 12 if (P0-> id 28 return pli