luminous electric

, boss can make a damage of (b_atk-w_def) to Warrior if (b_atk-w_def) bigger than zero, otherwise no damage. Outputfor each case, if boss's HP first turns to being smaller or equal than zero, please print "Warrior wins". Otherwise, please print "Warrior loses". If Warrior cannot kill the boss forever, please also print "Warrior loses".Sample InputW100 900100 900b100 1000 900100 1000 900Sample Outputwarrior Winswarrior losesWater problem, how much time to find out, pay attention to the case of 0

process it.Outputfor Each test case, the your program should the output one section. The first line of all sections must be ' test Case #k ', where k is the number of the the ' Test case ' (starting with 1). The second one must be ' total explored area:a ', where A is the ' total explored area ' i.e. the area of the the Union of all Rec Tangles in this test case), printed exact to both digits to the right of the decimal point.Output a blank line after each test case.Sample Input210 10 20 2015 1

, the vowels is ' a ', ' e ', ' I ', ' o ', and ' u '; all other letters is consonants.) Note that these rules is not perfect; There is many common/pronounceable words that is not acceptable.Inputthe input consists of one or more potential passwords, one per line, followed by a line containing only the word ' end ' That signals the end of the file. Each password are at least one and at the most twenty letters long and consists only of lowercase letters.Outputfor each password, output whether or

Text ReverseTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 17702 Accepted Submission (s): 6717Problem Descriptionignatius likes to the write words in reverse. Given a single line of text which are written by Ignatius, you should reverse all the words and then output them. Inputthe input contains several test cases. The first line of the input was a single integer T which is the number of test cases. T test Cases follow.Each test case contain

Problem-solving ideas: Because food can be casually eaten, so is a complete backpack, calorie represents consumption, happiness represents value, set of formula can be done.Problem Description for foodies, the happiest thing about the new Year is to eat, not one! 　　But for girls, calories are predators. Senior beauty is familiar with the "fat to fall like a mountain, fat to go like a ladder," the truth, so she hoped you can help develop a recipe, can make her eat happy at the same time, will not

sequence of the first and the end elements.Sample Input6-2 11-4 13-5-210-10 1 2 3 4-5-23 3 7-2165-8 3 2 5 01103-1 -5-23-1 0-20 Sample Output1310 1 410 3 510 100-1 -20 0 0HintHintHuge input, scanf is recommended.The subject uses the idea of dynamic programming, defines 3 arrays, namely DP (state), a (record data), S (record start subscript);The state transition equation is: Dp[i]=max (Dp[i-1]+a[i],a[i]);Core code:for (int i=1;i{if (Dp[i-1]+a[i]>a[i]){Dp[i]=dp[i-1]+a[i];S[I]=S[I-1];}Else{Dp[i]=a[

6del 3sum6add 1add 3add 5add 7add 9sumSample Output345HintC + + maybe run faster than g++ in this problem. The topic has been tangled for a long time, the line tree version of the online problem is not very detailed, it may be strange I can not understand .... Violence vector Step-by-step simulation like can pass, muddle through, after the line tree level deepened later, and then back to write a line tree version hope ~ Learn to debug code with vim for the first time.　Feel OK ~ Just a lot of ma

));Memset(Dp,0 ,sizeof( Dp));S[0]=S[1]=1; for (int I=1;IK;I++) {Cin>>A[I]; } for (int I=1;IK;I + +) { if( Dp[I-1]+A[I]>=A[I]) {Dp[I]=Dp[I-1]+A[I];S[I]=S[I-1]; } Else { Dp[I]=A[I];S[I]=I; }} int Start=1,End=1; int Max=Dp[1]; for (int I=2;IK;I + +) { if( MaxDp[I]) {Max=Dp[I];Start=S[I];End=I; } }cout"Case"Count":"Endl;coutMax" "Start" "EndEndl; if (T!=0)coutEndl; } return 0;} Copyright NOTICE: This article for Bo Master original article, without Bo Master permi

Solution idea: Because the state transfer equation for the complete backpack F[v]=max (F[v],f[v-c[i]]+w[i]) has documented all of the backpack composition scheme, but usually ask for the maximum value, now requires the total number of programsThat is F[v]=sum (F[v],f[v-c[i]+w[i]]),Problem description in a country only 1 points, 2 points, 3 cent coins, the exchange of money n into coins there are many kinds of laws.Please compile the procedure to calculate the total number of different methods.In

The title means: Ask N! How many zeros are there in the tail.Just started talking nonsense, in the last paragraph of the problem description to understand the topic to do.Ask N! The tail of the number of 0, first calculate n! , one more number, it is impossible, and N Max reaches 100000000. And we need to analyze from a mathematical point of view, how is 0 produced?By writing out the factorial of the previous few numbers, you know that to generate 0, you have to have 5 and an even number to mult

Problem-Solving ideas: Direct set formula can be done by a complete backpack.Problem description The undead Lich King, the Death Knight got an n-dollar bill (remember, only a note), in order to prevent his frequent death in the battle, he decided to buy himself some props, so he came to the Goblin store before.Death Knight: "I want to buy props!"Goblin businessman: "We have three kinds of props here, 150 pieces of blood bottle, a magic medicine 200 pieces of one, invincible potion 350 pieces of

]==true ) { while( K!=0) {Sum+=K%Ten;K/=Ten; } if( Prime[Sum]!=true) {Beauty[I]=false; } }}} voidDp()///Dynamic planning idea, dp[i] that is, the number of primes 1 to I {Memset(Dp,0 ,sizeof( Dp)); for (int I=1;I1000000;I + +) { if( Beauty[I]==true) {Dp[I]=Dp[I-1]+1; } Else Dp[I]=Dp[I-1]; }}int main() { int A,B,T,_count;Findprime();Beautyprime();Dp(); while (scanf("%d",T)!=Eof) {_count=0; while (T--) {_count++;scanf("%d%d",A,B);Printf("Case #%d:%d\n",_co

Output010SourcenoiRecommendll | We have carefully selected several similar problems for you:1404 1536 1517 1524 1729 Witzov game (Wythoff game): There are two piles of various items, two people take turns From a heap or at the same time from the two piles to take the same number of items, the provisions of at least one at a time, more than open, the last to win the light.In this case it is quite complicated. We use (AK,BK) (AK≤BK, k=0,1,2,...,n) to indicate the number of items and call it the s

Problem number Hdu Type Game Distribution Eventually 1001 5327 YES √ 1002 5328 YES √ 1003 5329 H 1004 5330 W 1005 5331 H 1006 5332 W 1007 5333 H 1008 5334

The meaning of the title is: the Rabbit casually hide in a hole, the wolf from the hole No. 0 began to find, every time to find the next is a number of M, all the holes formed ring.Input m and n, Hole is number No. 0 to n-1.The greatest common divisor of M and N is 1, and the wolf can be found in every hole. Otherwise, some holes are ignored, and those holes are safe.The following is the code for the AC:#include Copyright NOTICE: This article for Bo Master original article, without Bo Master per

hook after performing the operations.Consider the original hook is a made up of cupreous sticks.Inputthe input consists of several test cases. The first line of the input is the number of the cases. There is no more than cases.For each case, the first line contains a integer N, 1Next Q lines, each line contains three integers X, Y, 1Outputfor, print a number in a line representing the total value of the hook after the operations. Use the format in the example.Sample Input11021 5 25) 9 3Sample O

Problem description for a given string, statistics the number of occurrences of a numeric character.Input data has multiple lines, the first line is an integer n, indicating the number of test instances, followed by n rows, each containing a string consisting of letters and numbers.Output for each test instance, outputs the number of values in the string, with each output occupying one row.Sample INPUT2ASDFASDF123123ASDFASDFASDF111111111ASDFASDFASDFSample Output69Code:1#include 2#include malloc.

Nuclear reactorTime limit:1000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 12219 Accepted Submission (s): 5547Problem description There are two types of events occurring in a nuclear reactor:When the high-energy particle strikes the nucleus, the particle is absorbed, releasing 3 high-energy particles and a low-energy particle.When the low-energy particle strikes the nucleus, the particle is absorbed, releasing 2 high-energy particles and a low-energy par

+ + and use __int64 against VC6AuthorUnknownSource 2006/1/15ACM Program Design Final ExamRecommendLcyAnalysis: From the No. 0 second to 1 seconds, 1 high-energy particles emit 3 high-energy particles and a low-energy particle, from the 1th second to 2nd seconds 3 high-energy particles and a low-energy particle generation (3*3+2*1) a high-energy particle, while 3 high-energy particles produce 3 low-energy particles + 1 low-energy points to produce 1*1; a[ The array contains a high-energy particl

Find the safest roadTime limit:10000/5000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 9368 Accepted Submission (s): 3308Problem Descriptionxx Planet There are many cities, each city has one or more flight lanes, but not all roads are very safe, each road has a safety factor s,s is the real number between 0 and 1 (including 0, 1), a channel p from u to V The safety is safe (P) = S (E1) *s (E2) ... *s (EK) E1,e2,ek is on the side of P, now 8600 want to go out t