m2ts to mov

have been learning about Windows kernel recently, write a blog for memo.The specific process of Windows system call in the Pan teacher's "Windows kernel Principle and implementation" in the 8th chapter has been written very clearly, first read the picture given in the.Take CreateFile as an example, after some parameter checking in Ring3 's CreateFile, the final call is NtCreateFile in Ntdll. There are also zwcreatefile, but their addresses point to the same area, so they are essentially the same

it know this? You can view the two information shown in 1. Let's take a look at the code. Figure 1004035D2 E8 23730100 open multiple call program. 0041A8FA004035D7 A1 0C234300 mov eax, dword ptr ds: [43230C]004035DC 85C0 test eax, eax004035DE 74 37 je short program open more. 00403617004035E0 68 E8004300 push program multiple open. 004300E8; you can use this program without limit!004035E5 68 0A040000 push 40A004035EA 8BCE

unit opened by SWAp in the stack as the form parameter X and Y. This can be seen from the following Assembly Code (the author adds the annotation ):22: void main ()23 :{............13: int A = 1, B = 2;00401088 mov dword ptr [ebp-4], 100401_f mov dword ptr [ebp-8], 214: int * P1 = ;00401096 Lea eax, [ebp-4]00401099 mov dword ptr [ebp-0Ch], eax15: int * P2 = B;0

Buffer xor bx, BX mov BL, Al Add Bx, v_keymap mov Al, [BX] CMP Al, 0 JZ end mov ah, 0eh mov BX, 07 h int 10 h CMP Al, 13 JZ p_cl JMP end p_cl: mov Al, 10; if it is a carriage return, print the line feed mov ah, 0eh

commands in the program are accessed through the memory address of the variable or function. This address is an absolute address. If you insert the code to any other place and use the address generated during the original compilation to find them, you will not be able to find them because they have already moved. However, when writing a program, you can put a few lines of code at the beginning of the code to get the base address of the program, and then use the variable and function as the offs

Manual -- pecompact 2.x-> Jeremy collakePeid: pecompact 2.x-> Jeremy collakeThe shell removal tool has a dedicated shell removal tool, which is used as a trainer here.Od load and shell program.Entry Point: --- this is strange. If you leave F8, it will fly when you reach 00401016.1. Ignore all exceptions first.2. Line F8 in two steps. The ESP law can be used here.00401000> B8 dc2b4100 mov eax, rcrawler.00412bdc00401005 50 push eax00401006 64: ff35 0000

variable and function as the offset address, explicitly add this base address to find it, which is the relocation. Just like this code. Call getbaseaddress Getbaseaddress: Pop EBX Sub EBX, offset getbaseaddress MoV eax, dword ptr [EBX + var1] If you use macro assembly language to write viruses, use EBX as the base address pointer instead of EBP, because EBP changes when calling a function with parameters. (2) obtain the required API addre

= 2; int *P1 = a; int *P2 = b; Swap (P1, p2) } The function swap takes two pointer variables as arguments, and when main () calls swap, the pointer variable p1, the value of P2 (that is, the address of the variable A, b) is placed in the memory unit of the swap on the stack as the form parameter x and Y, in the same way that the value is passed. This can be seen from the following assembly code (note is added by the author): : void Main () 23: { ...... ...... INT.: int a = 1

I. PURPOSE of INTERNSHIPThe idea and method of writing program in assembly language with Palm grip.Second, the Internship contentfrom the first address to 1000H Start Storage Ten Number , which requires the design program to order these numbers from small to large, sorted by the number is still placed at the original address. Third, the CodeData segment Count DB 10; Array db 12,34,56,21,234,54,45,58,96,14; Msgone db ' The source array number is: ', ' $ ' msgtwo db 0AH,0DH, ' the sorted array n

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std0047EB5F BE 208F9F0F mov esi, 0F9F8F200047EB64 ED in eax, dx0047EB65 ^ 7F 91 jg short Allok_Vi.0047EAF8Bytes -----------------------------------------------------------------------------------------------Let's verify my guess.BP GetFileTime. After the breakpoint is canceled, the returned value is00484C92 C745 AC 0000000> mov dword ptr ss: [ebp-54], 000484C99 EB 09 jmp short Allok_Vi.00484CA400484C9B 8B4

Assume Cs: codedata segment dB 10 DUP (0) Data endscode segmentstart: mov ax, 13666 mov BX, data mov ds, BX mov Si, 0 call DTOC mov DH, 8 mov DL, 3 mov Cl, 2 call show_str

is as follows: Buf1 management structure (8 bytes) | buf1 real operable space (32 bytes) | buf2 management structure (8 bytes) | buf2 real operable space (16 bytes) | two double-stranded table pointers (8 bytes) Now, if the memcpy operation of buf1 overflows and overwritesManagement structure of the next idle heap (8 bytes) | two double-stranded table pointers (8 bytes)When there are 16 bytes in total, the rtlallocheap operation of buf2 will be abnormal. The reason is the code of rtlallocheap.

functions during memory construction and analysis? Copy to clipboardprint? 74: manager m; 00401268 lea ecx, [ebp-4] 0040126B call @ ILT + 60 (manager: manager) (00401041) 75 :} 00401270 lea ecx, [ebp-4] 00401273 call @ ILT + 0 (manager ::~ Manager) (00401005) 00401278 pop edi 00401279 pop esi 004020.a pop ebx 004010000b add esp, 44 h 0040da-e cmp ebp, esp 00401280 call _ chkesp (00408760) 00401285 mov esp, ebp 00401287 pop ebp 74: manager m; 004012

From: http://blog.codingnow.com/2005/10/vc_memcpy.html In many compilers, memcpy is an intrinsic function, that is, this function is implemented by the compiler. It is easier to be optimized during compilation than the inline function. The compiler can make multiple versions based on whether the memcpy parameter is a constant or a variable to achieve optimal performance. This cannot be done using inline or template. Let's take a look at the optimization of memcpy by VC. (Vc6) Void Fo

program, the Data Segment and the stack segment and the code are both different, when we execute the J function, the stack and the number segment are together. Pay special attention to this. 　　 Ifndef ?? Version ? Debug macro Endm Endif ? Debug s "c4.c" 　　 _ Text Segment byte public code Dgroup _ data, _ BSS Assume Cs: _ text, DS: dgroup, SS: dgroup _ Text ends 　　 _ Data Segment word public data D @ label byte D @ w label word _ DATA ends 　　 _ BSS segment word public BSS B @ label byte B @ w la

annotated in this way.; Boolean; Kiswapcontext (; In pkthread oldthread; In pkthread newthread;)But let's look at the code in wrk.MoV EDI, ECx; set old thread addressMoV ESI, EDX; set next thread addressMovzx ECx, byte PTR [EDI]. thwaitirql; Set APC interrupt bypass disableCall swapcontext; Swap ContextIt is indeed two parameters. View with windbg80545975 8bf1 mov ESI, ECx80545977 8bbb24010000 mov EDI, dwo

INT3 017f:1003d211 7c24 JL 1003d237 (NO JUMP) 017f:1003d213 0801 OR [ecx],al 017f:1003d215 0f8581010000 jnz NEAR 1003d39c 017f:1003d21b Pusha 017f:1003d21c be00a00210 MOV esi,1002a000 "R eip eip-1", "D EIP", the 017f:1003d210 place to 80H: 017f:1003d210 807c240801 CMP BYTE [esp+08],01 017f:1003d215 0f8581010000 jnz NEAR 1003d39c 017f:1003d21b Pusha 017f:1003d21c be00a00210 MOV esi,1002a000 017f:

-segment ts of truehd audio tracks, and there is indeed a problem of intermittent sound. There are two solutions:1. Merge multi-segment ts into a single TS2. Wait for the firmware upgrade from the manufacturer. Iii. Playback of multiple primary videos (m2ts) with truehd audio tracks on the original BD drive:After testing the original version of spider 2, there must be intermittent sound problems. Current solution: 1. tsmuxer re-generates a single