mahjong titans

[Game Statement]Jingdezhen Mahjong[Action Options]: Eat and touch the bar Hu[Eat cards]sub-card: Flush[3]only Home Note: > Flush[million-piece tube]> Word Loops[Cardinal][Medium Whitish][Touch Cards]Sub-card: With three cards[3][Bar Card]Sub-card: The same four cards[4][rules of the HU brand]Pinhou (four pair of Hu) hand {pair will[1], sub-card} + side pair seven pair (seven pair can hu) hand {pair will[7]} (all by the unitary group card can also HU)

First of all, four Laizi to do 34*34*34*34 's poor lifting.And then do the pruning optimization.Time complexity differs by an order of magnitude 34But it's not the average efficiency, and the worst is still not going to rise too much.But some mahjong Laizi number more than 7At this point should be used to look up the table, and then the cycle to do the poor is obviously a waste of efficiencyThe relevant code is temporarily not availableYou can leave a

DescriptionQuestion Bank linkGive you a pair of mahjong, the condition of the HU card is a pair will and a number of straight and engraved composition. Now give you \ (m\) cards, cards common \ (n\) species, ask you to listen to which card.\ (1\leq n\leq 400,1\leq m\leq 1000\)SolutionConsider enumerations to listen to that card, and then enumerate which pair to do.For the rest of the cards, first from small to large to sweep once, if the current card

Mahjong sorting time limit:1 Second Memory limit:65536 KB Dreamgrid has just found a set of mahjong with suited tiles and a white Dragon the in his pocket. Each suited tile has a suit (Character, Bamboo or Dot) and a rank (ranging from 1 to), and there is exactly one tile of E Ach rank and suit combination. Character tiles whose rank ranges from 1 to 9 Bamboo tiles whose rank ranges from 1 to 9 Dot tiles wh

Reprint Please specify the source Thank you: http://blog.csdn.net/vmurder/article/details/42921985Title: give you a deck of cards, ask whether it is a draw (that is, add a card can "Hu"), if it is, the output to touch which cards can hu, not output "no"Hu rules: The first need to have two of the same number of cards are eliminated, and then can be three of the same card to eliminate, can also be three consecutive label cards to eliminate, eliminate the hu.For example, 22 444555 789 is the HU car

Mahjong machine out thousand gambling ▓▓ ren words: Hzl23111▓▓q:⒗⒊⒛⒉⒏⒐⒏⒌▓▓ Professional card Yard Master, guide you to learn, pack learn to operate ▓ Tel: ⒔⒉⒉⒐⒋⒉⒊⒒⒈▓ address " Guangzhou, No. No. 211 Guangyuan Middle Road, Baiyun District, Hebei Building (formerly CTS Hotel) "The country can deliver door, absolute secrecy, quality assurance, safety, no flaws, easy to get started operation." After the satisfaction of receiving goods, our aim is to let y

Test instructions: Given 13 tiles, ask if you are "listening" to the card, if it is output "listen" which one.Analysis: This problem, very obvious violence, is on the original foundation put on a card, see is not can Hu, idea is very simple, also better realize, the result is tle, has been tle, this unscientific ah ...Very hard to write out, unexpectedly tle ... Heartache. is the first to determine a card, and then the flush analysis, in fact, is to prune, that is, if there are 1 or two cards, a

What about the Japanese mahjong .. There are no luxury seven pairs... It's no more difficult than enumerative search. Three types of cards F1 is 7-to-F2 is 13-So F3 is a normal fake. First, find one and then find three. Is always timeout .. Under the guidance of the peak, many pruning comments are marked .. In this way, it takes a long time .. # Include

1. This question requires final answersCode(C #) 2. The final code must be compiled, run, and implement the following business functions 3. Time LimitOne hourIncluding the time for reading documents and submitting code Business functions: A number of mahjong cards are given (assuming there are only one million cards and no cards or cylinders) The following conditions must be met: All cards must be connected to any other card or three cards: 123

= akindpai[j + 1];int ineedbigtwo = akindpai[j + 2];if (Iimagicpainum AKINDPAI[J]-= 2;Akindpai[j + 1] = 0;Akindpai[j + 2] = 0;Iimagicpainum-= Ineedbigone;Iimagicpainum-= Ineedbigtwo;Akindpai[0] = akindpai[0]-2-ineedbigone-ineedbigtwo;Bresult = Analyzepai (Akindpai, Biszi, Bhasjiang);AKINDPAI[J] + = 2;Akindpai[j + 1] + = Ineedbigone;Akindpai[j + 2] + = Ineedbigtwo;Akindpai[0] = Akindpai[0] + 2 + ineedbigone + ineedbigtwo;return bresult;}else {if (Bhasjiang) {if (Iimagicpainum AKINDPAI[J]-= 2;Iim

Title Link: BZOJ-1028Problem analysisEnumeration of what kind of cards to listen to, and then enumerate the pairs of what kind of cards, and then greedy judgment:Enumerate each card from 1 to N, if the number of such cards is less than 0, the return is illegal.The number of this card is 3, the remaining can only and I + 1, i + 2 These two cards constitute shun, so num[i + 1]-= num[i]; Num[i + 2]-= Num[i];The type of cards to enumerate to n + 2, since the n-1 and nth cards may lose the N + 1,n +

#include Sha 11210 Chinese Mahjong

(C1 2) D[u] = (2LL * FAC[C2] * T)%MOD; A ElseD[u] = (FAC[C2] * T)%MOD; the } + - intMain () $ { $fac[0] =1; - for(inti =1; i 1] * i)%MOD; - the intT scanf"%d", T); - for(intKase =1; Kase )Wuyi { the intN scanf"%d", n); - for(inti =1; I ) g[i].clear (); Wu for(inti =1; I ) - { About intU, v; scanf"%d%d", u, v); $ G[u].push_back (v); - g[v].push_back (u); - } - Aprintf"Case #%d:", Kase); + the if(n = =1) {puts

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At the end of the Eastern Han Dynasty, the disputes between the princes and the chaos of the world were over. In various regions, zhuhou only needs to improve his own strength and occupy more land. However, among the many forces, only Cao, Liu Bei,

Yingxiu's T-series motherboards are well known for their solid workmanship, rich onboard equipment and accessories, and are highly prized by DIY players for their strong overclocking capabilities and good stability. In particular, TForce550 in the

"88 Fan" 1 Senior XI is composed of 4 pairs of wind carving (staves) and cards. Regardless of the ring wind, Men, three wind carved, touch and 2 junior Yuan and card, there are 3 pairs of white engraved. Do not count the arrow engraved 3 green

This is my last question in my career. Acm has left me too much... No. The basic thing is to use enumeration + greedy. But there are several minor issues: 1. Seven small pairs are seven different pairs. 2. east, west, north, south, and so on cannot

Question link: Http://acm.hdu.edu.cn/showproblem.php? PID = 1, 4431 Question: Give a deck and find all the cards that can be pasted. Solution: Enumerate each card to see if it can be pasted. Because there are only 14 cards in total, each time the

The original matrix and target matrix are given. Http://acm.hdu.edu.cn/showproblem.php? PID = 1, 4306 Two operations: select a horizontal line to exchange two elements (cost CA ). Select the two-element exchange (CB) of a column ). An operation