MemcpyPrototype: extern void * memcpy (void * DEST, void * SRC, unsigned int count );Usage: # include Function: copy count bytes from the memory area indicated by Src to the memory area indicated by DeST.Note: the memory areas specified by Src and DEST cannot overlap. The function returns a pointer to DeST. You can copy any data type object.
For example, char a [100], B [50]; memcpy (B, A, sizeof (B); If si
# Include "memory. H"
Memset is used to set all memory spaces to a specific character. It is generally used to initialize the defined string to ''or '/0'. For example, char a [100]. memset (A, '/0', sizeof ());
Memcpy is used for memory copying. You can use it to copy any data type object and specify the length of the copied data. For example, char a [100], B [50]; memcpy (B, a, sizeof (B); note that if siz
Copy Code code as follows:
#include #include #include #include
memcpy: Copying by byte
Prototype: extern void* memcpy (void *dest,void *src,unsigned int count)
Function: Copy count bytes from the memory area referred to by SRC to the memory area referred to by dest;
With strcpy
void *memcpy_su (void *dest, void *src, unsigned int count)
{
ASSERT ((dest!=null) (src!=null));
char* bdest = (ch
Simulation Implementation memcpy Library function # include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced."C Language" simulation implements MEMCPY library function
The memcpy function in the The specific use is as follows:Where Y is the beginning address of the memory segment copied to, and X is the beginning of the memory segment from the copy side. The third parameter is the number of bytes of memory copied, which is used by sizeof to determine the number of bytes of the type.C + + memory copy function memcpy
First, sizeof is an operator, not a function, but when the operand is a type name you need to enclose the type name in parentheses (the operand is not required for the variable), and this rule makes sizeof look like a function. Second, if the operand of sizeof is a static array name, the result is the amount of space (in bytes) of the entire array, but if the operand is a dynamic array, it is only the size of a pointer variable (4byte on my machine). This is because arrays and pointers are actua
Header file: string.hvoid *memcpy (void *dest, const void *SRC, size_t n);Function: Copies n bytes from the beginning of the memory address referred to by the source SRC to the starting position of the memory address referred to by the target destvoid *memset (void *s, int ch, size_t n);function: Replace n bytes (typedef unsigned int size_t) with the current position in s with ch and return S.Memset: The function is to populate a block of memory with
/makeThis step causes problems.Make [1]: *** [rtppacket. Lo] Error 1: rtppacket. cpp: 51: Error: 'memcpy' was not declared in this scopeI don't know if many people will be unable to install jrtplib due to this situation, but the resources on csdn and the website I just mentioned will all have the same error. In fact, the solution is very easy. Just add the header file string. h to rtppack. cpp, that is, # include In addition, rtcpcompoundpacketbuilder
Strtol
Convert the string A, B, and C into numbers in hexadecimal notation (10, 2, 16 ).
# IncludeMain ()
Char A [] = "1000000000 ";
Char B [] = "1000000000 ";
Char C [] = "FFFF ";Printf ("A = % d/N", strtol (A, null, 10 ));
Printf ("B = % d/N", strtol (B, null, 2 ));Printf ("C = % d/N", strtol (C, null, 16 ));
A = 1000000000
B = 512C = 65535.
Fprintf:
Can be output to more types of devices, not just as printf defaults to stdout
Memcpy
Note the relationship between the source memory address and the target address when copying the address, that is, whether the source memory address and the target address are crossed.
1. If there is no crossover, you can directly copy the data in a loop.
2. If there is crossover, there are also two types of crossover.
First:
In this case, Src> = DST SRC
Second:
In this case, DST> SRC DST
The following uses an array: int arr [] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9:
If the source and target parameters overlap, memmove can provide guaranteed behavior, while memcpy cannot provide such guaranteed behavior, so it can be implemented more efficiently. If yourProgramIf you have any questions, it is best to use memmove.
It seems easy to implement memmove (). You only need to perform additional detection to effectively ensure the overlapping parameters.
Void * memove (void * DST, void * SRC, size_t N) {register char *
Example:
(1) Char buffer [] = "this is a test of the memset function .";
Printf ("before: % s/n", buffer); // before: This is a test ......
Memset (buffer, '*', 4 );
Printf ("after: % s/n", buffer); // After: ***** is a test of ......
Conclusion: The operations on characters (Note: one byte) are completely correct.
Example:
(2) int item [3] [3]; // The output result is: 50529027.
Memset (item, 3, 9); 50529027
For (INT I = 0; I
For (Int J = 0; j
{
Cout
}
Conclusion: When the value is 9, on
Recently to do some real-time transmission aspects of things, did not find this thing is not easy to see, also not fitThat thought can smooth good outfit, pretend to be very depressed, make always reported me wrong:MakeThis step is a problem.Sdh_pocket_reader.cpp:208:error: ' memcpy ' is not declared into this scopeI don't know if there's a lot of people who are going to do this, but I'm going to make the same mistake. In fact, the solution is very ea
call memcpy
leaq -16 (%RBP),%rax
MOVL (%rax),%eax
movl %eax, -4 (%RBP)
movl $,%eax
leave
As you can see in the code, the memory copy method takes up 7-12 lines, a total of 6 lines, and the cast takes up 13-15 lines, a total of 3 lines, and half of the instructions are less.
Delve into the fact is not only, because the 12th line is actually a function call, there must be the migration of the stack, so the efficiency of the
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