metrocast prices

$sa = ' SELECT * from Pql_spices_class ORDER by ID ASC '; $ra =mysql_query ($SA); $i =1; while ($rsa =mysql_fetch_array ($ra, MYSQL_ASSOC)) { //echo $rsa [' classname ']. ",". $rsa [' id ']. ""; $cid = $rsa [' id ']; $RESF =mysql_query (' SELECT * from ' pql_spices ' where classid= '. $cid. ' ORDER by ID DESC '); while ($RSF =mysql_fetch_array ($RESF)) { $Prices + = $RSF [' Price ']; } echo $i. "

1. Initialization1.1 Array () enumeration member $products = Array (' Tires ', ' oil ', ' spark plugs '); $prices = Array (' Tires ' = +, ' oil ' = 7.5, ' spark plugs ' = 32 ); 1.2 Range () generationRange (start, end, step = 1) $odds = Range (1, 2), $letters = Range (' A ', ' Z '); 2. Accessing elementsEcho $products [2]; $products [8] = ' Yes '; The key of an array does not have to be contiguous. It is more like a Key-to-Value mapping table. 3. C

benefitSolution: def maxprofit (self, prices): "" : Type Prices:list[int]: Rtype:int "" " minprice = 9999999 Maxpro = 0 for i in range (len (prices)): if prices[i] Parsing: Using two variables to record the minimum value of the current day and the maximum value of the gains best time to buy and Sell stock II English

, here's the first version: Import Akka.actor._ object Register { sealed trait article case Object Espresso extends article case Object Cappuccino extends article Case class Transaction (article:article) } class Register extends Actor { C7/>import register._ Import barista._ var revenue = 0 val prices = Map[article, Int] (Espresso, Cap Puccino, def receive = {case Transaction (article) + val Price =

Beijing News: Five rings inside million yuan under the House, the whole city disappears. 2007-07-27 11:31:35 Posted in Focus real Estate net-talk about the house-country Garden Hot Spring community (WU ai block) forum wfocus Statistics show that the first half of Beijing four ring Road The median residential flat price reached 13696 yuan/square meters, four ring to five ring road is 11439 yuan/square meters, five rings to six ring road for 8006 yua

1. Create and initialize arrays: $products =array (' Tires ', ' oil ', ' Spark plugs '); Array () is a language result as well as Echo $numbers =range (1,10,2); The range () function creates a 1-10 numeric array with a difference of 2 in ascending order $letters =range (' A ', ' Z '); Range () also allows you to manipulate characters The size of the array in 2.PHP will change dynamically depending on how many elements are added; such as: $products [0]= ' Tres '; If the $products array does not e

Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).The extension of the previous question, the requirement is to buy and sell only two times, and then find the maximum profit.With dynamic planning, the front and back are calculated once, and then the results are calculated.

Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. Transactions at the most K .Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Feel this problem is too difficult, because the request can only be traded, so in consideration of peaks, trough the basis to consider the number of transactions, on-line only found the C + + version, run a bit, can run correctly.cl

the past, to start from scratch and to do every single thing carefully.After the careful summary, to avoid the wrong mistakesAfter each trade, we should learn from our lessons. Especially for those recurring problems, but also toViewport Like some investors always love to chase up, a see price rise is considered to reverse the market, for fear of falling a round of rising prices, the result repeatedly catch up repeatedly quilt cover, also some friend

best time to Buy and Sell Stock IVSay you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. Transactions at the most K.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Credits:Special thanks to @Freezen for adding this problem and creating all test cases.The difficulty of this problem is obviously increased. It is the combination of the best time to buy and Sell St

if(Majorty = =Nums[i]) { Onecount++; A } - Else { -count--; the } - } - returnMajorty; - } +}View Code(3) best time to Buy and Sell StockTest Instructions: an array representing the price of the stock per day, and the number of I in the array represents the price of the stock on the first day. If only one transaction is allowed, that is to say, buy only one stock and sell it for maximum benefit.problem-solving ideas: Dynamic programming me

There are a variety of theories and methods for choosing stocks, which generally belong to the two main ideas camps-value investment and trend investment. Value-Investing believes that a stock has a relatively stable intrinsic value, unlike the price of frequent changes. such as the assets of a car company, how much debt, management level, research and development capabilities, market share, brand value geometry (analysis these are called basic analysis) ... All these factors combine to determin

I. Title DescriptionSay you had an array for which the i-th element was the price of a given stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:you engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).Two. Topic analysisCompared with the first two questions, this problem limits the number of trades traded, up to two trades.You can use dynamic planning to do it, first of all, first scan, calculate

PHP Learning Series Seven Database operations Array: $product = Array (' tires ', ' oil ', ' spark plugs '); Array is a language structure, not a function. $product [0], $product [1] foreach ($produce as $current) { echo $current. " "; } Associative arrays: $prices =array (' Tires ' =>100, ' oil ' =>10, ' spark plugs ' =>4) Visit: $prices [' Tires '] Traversal: foreach or List () and each () structure fore

Question address: http://poj.org/problem? Id = 1952 Buy low, Buy lower Time limit:1000 ms Memory limit:30000 K Total submissions:6692 Accepted:2302 Description The advice to "buy low" is half the formula to success in the bovine stock market. To be considered a great investor you must also follow this problems 'advice: "Buy low; buy lower" Each time you buy a stock, you must purchase it at a lower price than the previous time you bought

Title:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You could complete as many transactions as (ie, buy one and sell one share of the stock multiple times). However, engage in multiple transactions for the same time (ie, you must sell the stock before you buy again).Tips:This problem should use the idea of greedy algorithm. The greedy rules I use are as follows: Iterates from the first element to th

(vectorint> prices) { if(Prices.empty ())return 0; intn=prices.size (); inti; intlow=prices[0]; intLeft[n]; left[0]=0; for(i=1; i) { low=min (low,prices[i-1]); Left[i]=max (left[i-1],prices[i]-Low ); } inthigh=prices[n-1]; intRight[n]; Right[n-1]=0; for(i=n-

Price change of residential sales in 70 major cities in May 2015Http://www.stats.gov.cn/tjsj/zxfb/201506/t20150618_1170358.html(a) compared with last month, 70 medium and large cities, the price drop in the city has 43, the rising city has 20, the flat city has 7. In the chain price change, the maximum increase is 6.7%, the lowest is down 0.6%.(b) compared with the same month last year, there were 69 cities in 70 major cities with lower prices, with 1

Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again). Public classSolution { Public intMaxprofit (int[] prices) { /*each point in the entire interval is cut, then the maximum values of the left and right sub-intervals are co

Given a vector, the vector represents the price of a stock in the first day, Y to make the stock yield the largest should be bought on the day I, the first i+n days to sell, to find out the value of the maximum profit is how muchIdea: Record the minimum value with a variable, a variable record the maximum benefit, scan the price from beginning to end, when scanning to the price of the day I, if the price is smaller than the minimum value, then replace, if it is larger than the minimum value, the