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More than half the number of occurrences in the array "Microsoft interview 100 question 74th"

[] = {5,6,7,1,2,1,2,1,2,3,3,4,3,2,1,3,2,1,2,1,3}; Find (ID, +); return 0;}voidFind (int* ID,intN) { intntimes[3], I; intcandidate[3]; ntimes[0]=ntimes[1]=ntimes[2]=0; candidate[0]=candidate[1]=candidate[2]=-1; for(i =0; i ) { if(id[i]==candidate[0])//These juxtaposition of ideas are important, think about it .{ntimes[0]++; } Else if(id[i]==candidate[1]) {ntimes[1]++; } Else if(id[i]==candidate[2]) {ntimes[2]++; } Else if(ntimes[0]==0) {ntimes[0]=1; candidate[0]

Microsoft OS build number Daquan

Operating System Build Number Windows 10 10.0* Windows Server Technical Preview 10.0* Windows 8.1 6.3* Windows Server R2 6.3* Windows 8 6.2 Windows Server 2012 6.2 Windows 7 6.1 Windows Server R2 6.1 Windows Server 2008 6.0 Windows Vista 6.0 Wind

Microsoft algorithm 100 question 68 with the smallest number of arrays

68. Arrange the array to the smallest number.Title: Enter an array of positive integers, concatenate them into a number, and output the smallest of all the numbers that can be drained.One.For example, the input array {32, 321}, the output of these two can be ranked as the smallest number 32132.Please give an algorithm to solve the problem, and prove that the algorithm1 PackageCom.rui.microsoft;2 3 Importja

Microsoft Algorithm 100 question 25 find the longest consecutive number string

Question 25th:Write a function whose prototype is int Continumax (char *outputstr,char *intputstr)Function:Find the longest consecutive number string in the string, and return the length of this string,and send this longest number string to one of the function parameters outputstr the memory.For example: When the first address of "abcd12345ed125ss123456789" is passed to Intputstr, the function returns 9,Out

Microsoft fourth question the maximum number of cities given cost can traverse

N*n Matrix Cost:m in a direction graph, the maximum number of nodes that can be traversed such as a can have 0->1->2->0->1 cost: 2+2+3+2=9#include using namespacestd;intMain () {intn=3;intm=Ten; inta[][3]={{0,2,3},{4,0,2},{3,4,0}}; intlast_step[3]; intdist[3][3]; for(intI=0; i) { for(intj=0; j) {Dist[i][j]=A[j][i]; } } for(intI=0; ii;} intmax=0; for(intstep=1; step-max1; step++){ for(intj=0; j){ intMin=int_max;i

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