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Timer 0 Mode 2 # Include # Define uchar unsigned char # Define uint unsigned int Sbit led1 = p1; Uint num; Void main () { Tmod = 0x02; Th0 = 6; Tl0 = 6; Ea = 1; Et0 = 1; Tr0 = 1; While (1) { If (num = 3686) { Num = 0; Led1 = ~ Led1; } } } Void t0_timer () interrupt 1 { Num ++; } Method 3 # Include # Define uchar unsi

The sum of factorialEnter N, calculate s=1! +2! +3! + ... +n! The last 6 bits (excluding the leading 0). N≤10 6, n! SaidThe product of the first n positive integers.Sample input:10Sample output:Package Demo;import Java.util.scanner;public class Demo02 {public static void main (string[] args) {Scanner in=new Scanner ( system.in); int n=in.nextint (); Long sum=

Document directory 0: stopped 0: downtime 1: single-user mode, only root for Maintenance 2: multi-user, cannot use net file system3: full multi-user 5: Graphical 4: security mode 6: restart actually, you can view/etc/rc. rc * in d *. d .. Init 0, the corresponding system will run, the program specified in/etc/rc. d/

Using Newton's Iterative method to find the root of the following equation near 1.5:2x^3-4x^2+3x-6=0 As for the Newton iterative method, in the course of computational methods, the basic formula is: xn+1=xn-f (Xn)/F *(Xn) xn+1 is the n+1 iteration result,Xn is the nth iteration result,f * ( Xn) is the Guide function value of f (Xn) . Basic steps: The first step