mongodb cost

Option explicit 01 1 Note (0.20 yuan) Cost: 0.20 get a bonus: 0.68 yuan expected net profit: 0.48 yuan02 3 Note (0.60 RMB) Cost: 0.80 yuan received bonus: 2.04 yuan expected net profit: 1.24 yuan03 6 Note (1.20 yuan) Cost: 2.00 get a bonus: 4.08 yuan expected net profit: 2.08 yuan04 11 Note (2.20 yuan) Cost: 4.20 get

HDU 4862 Jump (Multi-school joint training 1) (minimum cost maximum stream), hdu4862 Address: HDU4862 The minimum cost flow is still too small. You cannot figure it out... Directly reference the official question... The minimum K path coverage model is solved by the cost flow or KM algorithm. A two-part graph is constructed. X has N * M nodes, and The Source Vert

Let's talk about poj3680: give n permissions ( Thought: Restricted processing: s --> the starting traffic is K, and the total permission is required to be the largest, that is, the maximum cost. Therefore, the cost is negative, and the minimum cost is the maximum flow. For the input range [a, B]: W, add edge: A --> B, the traffic is 1, and the fee is-w. For verte

　　small food to join http://www.jmlingshi.com/smallpro/ to know how much money to join the small food, the first to determine the franchise brand. Not the same brand because of internal system, management method is not the same, the cost of capital differences, so, the brand selection is to do the key to cost accounting. Again, a small series of demand tips you, choose to join the brand, not single from th

What's a Profit center and cost center for Balance Sheet Items?by Dennis Hartman, Demand MediaEvery business must maintain a balance sheet, which are one of the major financial statements that businesses produce and u SE to track financial performance. A Balance Sheet Lists all assets and liabilities for the business, including those this belong to their profit centers, cost Centers and other types of depar

Address: hdu4862 The minimum cost flow is still too small. You cannot figure it out... Directly reference the official question... The minimum K path coverage model is solved by the cost flow or KM algorithm. A two-part graph is constructed. X has n * m nodes, and The Source Vertex connects one edge to each node in X, with 1 traffic, the cost is 0. Department

There are M supply points for goods. It provides k types of goods and N stores. These N stores need to order a certain amount of these k types of goods from the goods points, each supply point has different supply for these k types of goods, and each store has different requirements for k types of goods. Each supply point has different costs for delivering a single item of different types of goods to each store, the relationship between supply points, stores, k types of goods, and costs is now g

The root-path overhead is based on the network segment between the switches, and the cost of the local path is also called the port overhead for the local physical link to the relevant IETF provisions for Physical link Overhead 10G/S 2 1G/S 4 100m/s 19 10M/S 100 According to the picture above, SW1 is the root bridge, that SW2 F0/1 is the root port, because SW2 to from the network Segment 1 and network segment 3 received BPDU respectively, netw

Every time I share a virtual desktop with a client, I can see the excitement in the eyes of the user, and of course it will inevitably be asked by the user about the cost of the virtual desktop. Today we're going to talk about the cost of virtual desktops------A problem you have to consider when you're on a desktop virtualization project. With virtual desktops, each user typically has a virtual machine (w

Minimum Transport CostTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 9052 Accepted Submission (s): 2383Problem Descriptionthese is N cities in Spring country. Between each pair of cities there is one transportation track or none. Now there are some cargo that should being delivered from the one city to another. The transportation fee consists of the parts:The cost of the transportation on the path b

Title Link: http://acm.hdu.edu.cn/showproblem.php?pid=1853There is N cities in our country, and M one-way roads connecting them. Now Little Tom wants to make several cyclic tours, which satisfy so, each cycle contain at least both cities, and each CI Ty belongs to one cycle exactly. Tom wants the total length of the "all" tours minimum, but he's too lazy to calculate. Can you help him?Test Instructions Description: N cities have m one-way path, each path has a weight, each city belongs to and be

In coding reality, we are often too optimized to complete the work on time. One fact is, the cost is accumulated when we keep coding it. If we take a look at each step of coding, it probably like this: Create the structure of the application Create the module to handle different functionality If the problem is complex, then the module will be complex as well, this time, the level will be increased dramatically high, because to maintain it, w

In our SEO drink a forum, recently I often see some webmaster talk about the various ways of network marketing, often talk about advertising alliances, mail marketing, bulk SMS, tend to like to add a low-cost or the cheapest slogan, but SEO drink a post of Chen Xiaohuan really do not understand, If you don't actually operate a large number of ad leagues, how do you know the minimum cost of online marketing

SOURCE:HDU 3790 Shortest Path problemhttp://acm.hdu.edu.cn/showproblem.php?pid=3790Problem DescriptionGive you n points, M without the edge, each side has a length D and spend P, give you the beginning of the end of T, the minimum distance from the output starting point to the end point and the cost, if the shortest distance there are multiple routes, the output is the least cost.InputEnter N,m, the number of the point is 1~n, then the M line, 4 numbe

TransportationTime limit:2000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 2670 Accepted Submission (s): 1157Problem Descriptionthere is N cities, and M directed roads connecting them. Now the want to transport K units of the goods from the City 1 to the city N. There is many robbers on the road and so you must be very careful. The more goods your carry, the more dangerous it is. To being more specific, for each road I, there is a coefficient ai. If you wan

Test instructionsAdd capacity to some sides of a network, increasing the sum of the maximum to K, making the maximum flow maximum.Cost flow: The cost of increasing unit traffic on an edge.Then it is possible to build 2 edges between 2 points, and the first given edge (u,v,x,0) has an edge cost of 0At the same time the other side (u,v,k,1) costs 1, you can find the maximum flow by limiting the corresponding

The topic of the first fee flow---In fact---still do not understand, only know along the shortest path to find the augmented roadBuilding MapSource point to 1 with a capacity of 2 (because to go back and forth), the cost is 0 of the edgeN to a meeting point with a capacity of 2 and a cost of 0 sidesThe other one is the one that was typed in the title.In addition, the problem is the non-direction side-----MA

This article comes from NetEase cloud community.How can you quickly get a large number of target users at a low cost, rather than a protracted war with your competitors?This is not common on the internet today. Now, most of the industry is already a long time competition in the Red Sea, and the blue Ocean market technology, resource barriers are very high, the general product is far behind. In the fierce competition of the Red Sea market, how can we a

This article comes from NetEase cloud community.How can you quickly get a large number of target users at a low cost, rather than a protracted war with your competitors?This is not common on the internet today. Now, most of the industry is already a long time competition in the Red Sea, and the blue Ocean market technology, resource barriers are very high, the general product is far behind. In the fierce competition of the Red Sea market, how can we a

There was a saying that users convert a search engine in just 27 seconds, with little cost. The idea is to question the soundness of Google's business model. On the Internet, you change a mailbox, you need to notify all your contacts, the cost is very high. Another portal to watch the news, the cost is lower, but the habit and the level of editing will also stop