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Expensive dowry Time limit:1000 ms Memory limit:10000 K Total submissions:36654 Accepted:10560 DescriptionThe young explorer came to an Indian tribe. There he fell in love with the daughter of the chief, so he went to ask for advice from the Chief. The chief promised to marry his daughter only when he used 10000 gold coins as a dowry. The explorer asked the chief to lower his requirements if he could not get so m

Label: poj1062 description Question: Chinese Question, here only provides question transfer door http://poj.org/problem? Id = 1062 Question: first, if item 1 can be obtained by item 2 and X yuan, a one-way edge of B-> A is connected, and the edge weight is X. The Source Vertex then connects an item to each item for direct price. Then, the lower and upper limits of the enumeration point right are listed. Okay, it's very watery. However, the data range is poor !!! Point permission can st

about how to add or remove elements from linked list, because I believe that as a programmer you must know array, linked list, set, MAP and string algorithms. if you want to add another level of cushion than you can also ask about how to remove duplicates in array without using any library function. this will give you enough idea whether to proceed further or not. I knowTrivia is not a good way to find a programmers, But questions which are closely related to practical experience are good way

A shortest path is not too difficult ~ Let me speak out, the chief is not the highest-So what are you really ?! Enumerating a position range [I. I + M-1] As long as all traders are in that range, there will be no conflict And this sad chiefs must be in the range, so if the leader's position is l0, then the enumerated range is [L0-i, l0 + M-I] {I | 0 Then there is the bare Dijkstra, and the position in the range is taken out, and then a new vertex N + 1 is added to connect to all vertices, dista

MySQL queries several SQL statements of the most expensive book dealers bitsCN. commysql> use test; Database changed Mysql> create table shop ( -> Article INT (4) unsigned zerofill default '100' not null, -> Dealer CHAR (20) DEFAULT ''not null, -> Price DOUBLE (16, 2) DEFAULT '0. 00' not null, -> Primary key (article, dealer )); Query OK, 0 rows affected (0.13 sec) Mysql> insert into shop VALUES -> (1, 'A', 3.45), (1, 'B', 3.99), (2, 'A', 10.99), (3,

blog, restart the basic algorithm of learning, do not want to get what a great prize, just down-to-earth Step by stepImpetuous seems to have been accompanied by me, took me the wrong way, around a circle. I am a word not much, but really work hard, more than 300 days I a nearly 300 questions, the middle with a lot of pain, every day of the curriculum and the faith in my heart let me every day in the insistence, if not detours, I think I have gone quite far away. But I actually do not have much

;Q; $Q.push (1); $ - while(!Q.empty ()) { - intx =Q.front (); the Q.pop (); -ALREADYINQUEUE[X] =false;Wuyi the for(inte = head[x]; E! =-1; E =Next[e]) { - inty =Edge[e]; Wu - if(Level[y] Max_level About Max_level-level[y] m $ Cm[x] + cost[e] Cm[y]) { -Cm[y] = Cm[x] +Cost[e]; - - if(!Alreadyinqueue[y]) { A Q.push (y); +Alreadyinqueue[y] =true; the } - } $ }

POJ on a rare Chinese question ...Idea: To create a map with a source point of 0, then the value of Map[0][n] represents the value of item n, and Map[i][j] represents the value of item J after substituting J for I. We think that the chief's commitment is node ' 1 ', then what we need to do is to find the minimum value of Map[0][1 by a series of operations, then we can see that this is a shortest path problem. The title also stipulates that the high level will not agree with the low level of exch

Test instructionsWell, look directly at the topic, anyway, is also a Chinese problem, not good with a few words to express clearly ~ ~ ~Topic linksThinking of solving problemsBecause the level gap cannot be traded indirectly, the level of each trade is within a range, the range must contain the High priest's rank, the interval can be enumerated, the High priest level of L, you need to from [l-m,l], has been enumerated to [l,l+m], to ensure that all the points of the transaction level in this ran

Original When a plane from London arrived on Sydney airport, workers began to unload a number of wooden boxes which contained cloth Ing. No one could account for the fact, one of the boxes was extremely heavy. It suddenly occurred to one of the workers to open the box. He is astonished at the what he found. A man is lying in the box on top of a pile of woollen goods. He is so surprised at being discovered, that he does not even a try to run away. After he is arrested, the man admitted hiding in

ItemsSample output Sample outputs5250It is easy to think of constructing a diagram, each node of the graph is an item, the right value is the price after the discount set the merchant to 0., find the shortest possible 1. Due to the level limit, the node must be 1 or less than the level of M, then for each of the upper and lower difference between the interval of M to find the shortest possible, and finally take the minimum value.Easy to understand, draw a very bad picture, we gather live to lo

Chinese questionsProblem-solving ideas: The most source point of the Chiefs, with a structure to record each point to the chief of the shortest, and the level range, when updating the new node, you can determine the level range to update the#include #include #include #include #define N#define M 10010#define INF 0x3f3f3f3fusing namespace STD;structPeople {intPrice, level, X;} P[n];structchange{intNo, Price;} C[M];structState {intDis, high, low;} S[n];intN, M, CNT;intDis[n][n];BOOLVis[n];voidInit

]; at } - if(mini==INF) - Break; - -v[k]=1; - for(j=1; j) in { - if(!v[j] inch[j] d[k]+maps[k][j]D[j]) to { +d[j]=d[k]+Maps[k][j]; - } the } * } $Mini=INF;Panax Notoginseng for(i=1; i) - { the if(D[i]+p[i]V[i]) +mini=d[i]+P[i]; A } the returnMini; + } - $ intMain () $ { - intm,x,t,v; - intI,j,minicost; the while(SCANF ("%d%d", m,n)! =EOF) - {Wuyi the

later in the building visualization is very important, not that rendering can not be done, but the repeated adjustment process of rendering too wasted energy, so in the rendering we just guarantee the light and shade, material, structure, composition of the direction of the big right can, as for details we can use PS to improve the appeal of the work. everyone has their own way of dealing with each other in the late, and it is worthwhile to borrow a sign to learn. Technology as long as someone t

#include #include#include#include#include#include#includeSet>#include#include#include#include#includetypedefLong Longll;using namespacestd;//freopen ("d.in", "R", stdin);//freopen ("D.out", "w", stdout);#defineSspeed ios_base::sync_with_stdio (0); Cin.tie (0)#defineMAXN 101Const intinf=0x7fffffff;//infinitely LargeintM,n;intPRICE[MAXN][MAXN];intLV[MAXN];intX[MAXN];intDIST[MAXN];intVISIT[MAXN];voidinit () {memset (Price,0,sizeof(price)); memset (LV,0,sizeof(LV)); memset (Dist,inf,sizeof(Dist)); m

valid levels $Mi =min (MI, Dijk (i)); $printf ("%d\n", MI); - } - return 0; the } - Wuyi voidInit () the { - intI, J; Wu for(i=0; i) - for(j=0; j) AboutMAP[I][J] =INF; $ } - - intDijk (intx) - { A intDIST[MAXN], VIS[MAXN], I, J; + intHigh = Goods[x].l + M;//Rank Maximum value the intlow = GOODS[X].L;//Rank Minimum value -memset (Vis,0,sizeof(Vis)); $ for(i=0; i//initialized to a valid value within a valid level, otherwise INF the if(Low High )

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In E-commerce site throwing money is very easy things, sometimes stroll a night taobao hundreds of yuan or even thousands of yuan is gone. But this is not the most expansive, today's e-commerce sites, small to the pin, big to the car house, there is no one you can't buy. A few years ago also heard that Taobao sell airplanes and so on, we China so vigorous development, then the American people across the coast? Gizmodo to their netizens, collecting some expen