mxtoolbox spf

An undirected graph is used to calculate a cut point. Is the use of tarjan. [Cpp]# Include # Include # Include Using namespace std;Const int maxn = 1e3 + 9, N = 1e3;Bool e [maxn] [maxn];Int dfn [maxn], low [maxn], count, in [maxn];Void tarjan (int t, int from){Dfn [t] = low [t] = ++ count;Int ret = 0;For (int I = 1; I If (e [t] [I]){If (I = from) continue;If (dfn [I] =-1){Ret ++;Tarjan (I, t );Low [t] = min (low [t], low [I]);If (low [I]> = dfn [t])In [t] ++;}Else{Low [t] = min (low [t], dfn [I]

(inti = Head[u]; I! =-1; i =edge[i].nxt) { intv =edge[i].to; if(!Dfn[v]) {Tarjan (v,u); Low[u]=min (low[v],low[u]); if(Low[v] >=Dfn[u]) { if(U = = start) son++; ElseMark[u] =1; } } Else if(v! = FA) Low[u] =min (low[u],dfn[v]); } return ;}voidBFsintXintcant) {Queueint>que; while(!que.empty ()) Que.pop (); Que.push (x); VIS[X]=1; while(!Que.empty ()) { intnum =Que.front (); Que.pop (); for(inti = Head[num]; I! =-1; i =edge[i].nx

intHead[maxn],ne; One voidAddedge (intUintv) { AEdge[ne].v=v; Edge[ne].next=head[u]; head[u]=ne++; - } - intDN,DFN[MAXN],LOW[MAXN],SON[MAXN]; the voidDfsintu) { -dfn[u]=low[u]=++DN; - for(intI=head[u]; i!=-1; I=Edge[i].next) { - intv=edge[i].v; + if(Dfn[v]) { -low[u]=min (low[u],dfn[v]); + Continue; A } at Dfs (v); - if(u==1) ++Son[u]; - Else if(Low[v]>=dfn[u]) + +Son[u]; -low[u]=min (low[u],low[v]); - } - } in BOOLoutput () { - B

; $ while(1){ -scanf"%d",u); - if(u==0) - Break; Aprintf"Network #%d\n",++CAs); +Memset (Next,0,sizeof(next)); theMemset (Head,0,sizeof(head)); -memset (adj,0,sizeof(adj)); $memset (DFN,0,sizeof(DFN)); thememset (Low,0,sizeof(Low)); thememset (Cut,0,sizeof(cut)); thememset (T,false,sizeof(t)); thetx=sta[0]=c=n=m=0; - while(1) in{scanf ("%d",v); them++; then=Max (N,max (u,v)); About Addedge (u,v); the Addedge (v,u); thescanf"%d",u); the if(u==0) + Break; - } the for(i=1; i)Bayi

The main idea: give a picture, ask to cut points, the number of connected components is how manyProblem-solving ideas: cut points of water problems, set template can beHad to spit out the slot for input.#include #include #define MIN (a) #define N 1010#define M 2000010structedge{intTo, next;} E[M];intHead[n], Num[n], pre[n], lowlink[n];intTot, dfs_clock, root;BOOLIscut[n];voidDfsintUintFA) {Lowlink[u] = pre[u] = ++dfs_clock;intChild =0; for(inti = Head[u]; I! =-1; i = e[i].next) {intv = e[i].to;i

Title: http://poj.org/problem?id=1523Topic Analysis:Pay attention to the problem input input, prevent PE, the topic is to seek cutting points, and ask the cut point this connected graph into a few sub-graphs, is a template problem bar.#include #include#includestring.h>#include#include#includestring>#defineN 10010using namespacestd;structnode{intX,y,next;} eg[2*N];intTt,head[n],dfn[n],low[n],ti,f[n];voidinit () {memset (head,-1,sizeof(head)); TT=0; TI=1; memset (DFN,0,sizeof(DFN)); Memset (F,0,si

SPF -- standard parasitic formatDspf -- Detailed standard parasitic formatRSPF -- reduced standard parasitic formatSpef -- standard parasitic Exchange FormatSbpf -- Synopsys binary parasitic format Summary: SPF, dspf, and RSPF are in the Candence format and do not contain information about crosstalk C. They cannot be used in PT Si. Dspf has detailed RC information, which is relatively large in size and cl

Approximate test instructions: a connected undirected graph is given to find out which points are cut points, and for each cut point, the number of connected components after the point is removed. Output "No SPF nodes" if there is no cut point. Ideas:Seek cutting point with Tarjan can, and then ask to delete the number of connected components after cutting point, every time to find a cut point, and then from the point of cut Dfs, you can also directl

Meaning Give a connected undirected graph, find all the cut points of this graph, and output each cut point and the connected edge is removed, will become several connected components Ideas Use Tarjan to find the basic problem of cutting point, the principle of Tarjan algorithm to really understand, this problem on the water. Code /**===================================================== * This are a solution for ACM/ICPC problem * * @source: poj-1523 S